对齐长方程式

对齐长方程式

我想通过等号对齐来输入以下等式,但是它似乎太长了:

\begin{align*}\prod_{z^n=-1}(w_1(z)^n+1)
&=& \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\\
&=& \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^{-n}+1)\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n)
\end{align*}

有人能帮帮我吗?非常感谢!

答案1

另一种方法:

\documentclass[preview,border=12pt]{standalone}
\usepackage{mathtools}
\begin{document}
\abovedisplayskip=0pt\relax
\begin{align*}
\prod_{z^n=-1}(w_1(z)^n+1)
&=\!
    \begin{aligned}[t]
        &\prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
        \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1) \\
        &\rule{10cm}{0pt}\mathllap{\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)}
    \end{aligned} \\
&=\!
    \begin{aligned}[t]
        &\prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
        \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^{-n}+1) \\
        &\rule{10cm}{0pt}\mathllap{\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
        \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n)}
    \end{aligned}
\end{align*}
\end{document}

在此处输入图片描述

注意:\!由于aligned为什么在“aligned”环境的开头有一个 \, 空格?

答案2

您可以使用multlined来自mathtools 包

\documentclass[11pt]{article}
\usepackage{mathtools}
\begin{document}
\begin{align*}\prod_{z^n=-1}(w_1(z)^n+1)&=
\begin{multlined}[t]
 \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
 \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1) \\       \times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
\end{multlined} \\    &=
\begin{multlined}[t]
  \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)
  \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^{-n}+1) \\         \times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)    
     \prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n)
\end{multlined}
\end{align*}
\end{document}

您可能需要更改换行符的位置,具体取决于字体大小、页面宽度等。

大方程式

答案3

如果太长,你必须把线分成两段

\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{align*}
\prod_{z^n=-1}(w_1(z)^n+1) &= \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\times\\
&\qquad\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\\
&= \prod_{l=0}^{l_0}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^{-n}+1)\times\\
&\qquad\times\prod_{l=l_1+1}^{n-1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n+1)\prod_{l=l_0+1}^{l_1}(w_1(e^{\frac{(2l+1)\pi i}{n}})^n)
\end{align*}
\end{document}

在此处输入图片描述

相关内容