![简单水平路径](https://linux22.com/image/275225/%E7%AE%80%E5%8D%95%E6%B0%B4%E5%B9%B3%E8%B7%AF%E5%BE%84.png)
我正在尝试创建一个简单的水平箭头(线 1),从广告商到扫描仪,在一定距离内位于线 2 上方。由于时间太长,我试图找出正确的语法,但没有成功。我非常感谢任何帮助。
\begin{tikzpicture}[auto,
block_center/.style ={rectangle, draw=black, thick, fill=white,text width=12em, text centered, minimum height=12em},
\matrix [column sep=30mm,row sep=30mm] {
\node [block_center] (Scanner) {\textbf{Scanner}} ;
& \node [block_center] (Advertiser) {\textbf{Advertiser}} ; \\
}; % end matrix
\path [draw, ->] (Advertiser.west)+(0,1.5) -- node [midway,above] {line 1} (Scanner);
\path [draw, ->] (Advertiser.west) -- node [midway,above] {line 2} (Scanner) ;
\end{tikzpicture}
答案1
两个选项:
\documentclass{article}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}[
auto,
block_center/.style ={
rectangle,
draw=black,
thick,
fill=white,
text width=12em,
text centered,
minimum height=12em
}
]
\matrix [column sep=30mm,row sep=30mm]
{
\node [block_center] (Scanner) {\textbf{Scanner}} ;
& \node [block_center] (Advertiser) {\textbf{Advertiser}} ; \\
}; % end matrix
\draw[->] ([yshift=10pt]Advertiser.west) -- node [midway,above] {line 1} ([yshift=10pt]Scanner.east|-Advertiser.west);
\draw[->] (Advertiser.160) -- node [midway,above] {line 0} (Scanner.east|-Advertiser.160);
\draw[->] (Advertiser.west) -- node [midway,above] {line 2} (Scanner) ;
\end{tikzpicture}
\end{document}
一个更简单的图表来解释:
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\begin{document}
\begin{tikzpicture}
\node[draw,minimum size=2cm] (A) {A};
\node[draw,minimum size=2cm,right=2cm of A] (B) {B};
\draw (A.10) -- (B.west|-A.10);
\draw ([yshift=-20pt]A.east) -- ([yshift=-20pt]B.west|-A.east);
\end{tikzpicture}
\end{document}
在这两种情况下,关键在于使用垂直坐标系。语法(<name1>|-<name2>)
给出的坐标具有x
的 -坐标<name1>
和y
的 -坐标<name2>
。
说
\draw (A.10) -- (B.west|-A.10);
意思是“从 到坐标为和坐标为 的A.10
点画一条线”(这保证了该线是水平的。)x
B.west
y
A.10
类似地,
\draw ([yshift=-20pt]A.east) -- ([yshift=-20pt]B.west|-A.east);
意思是“从 画一条线A.east
,向下移动,到具有 的-坐标和的-坐标的20pt
点,并且向下移动”(同样,这保证该线是水平的。)x
B.west
y
A.east
20pt
还有语法(<name1>-|<name2>)
;阅读 PGF 手册中其含义是一项家庭作业。