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根据最宽的列编写具有等间距列的表格

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根据最宽的列编写具有等间距列的表格

朋友们，我正在尝试生成一个表格，其中所有列的间距都相等（宽度相同）。 在我的例子中，所有列的宽度将是表格中最宽列的宽度：

\documentclass{article}

\begin{document}

\begin{tabular}{ll}
a & b \\
c & Mary had a little lamb
\end{tabular}

\end{document}

有什么提示吗？:)

答案1

好吧，我之前一直在解决这个问题，最后得到了一个相当通用的解决方案，请看示例（您需要运行代码两次才能获得正确的结果）：

在此处输入图片描述

\documentclass{article}

\usepackage{array}

\makeatletter
\newlength\eqcol@newlen
\newlength\eqcol@oldlen
\let\eqcol@bc\hfil
\let\eqcol@ec\hfil
\let\eqcol@br\hfil
\let\eqcol@el\hfil
\newcolumntype{e}[1]{%
  >{\setbox0\hbox\bgroup}#1%
  <{\egroup
    \ifdim\wd0<\eqcol@newlen\else\global\eqcol@newlen\wd0\fi
    \ifdim\wd0<\eqcol@oldlen\else\global\eqcol@oldlen\wd0\fi
    \hbox to \eqcol@oldlen{%
      \csname eqcol@b#1\endcsname
      \box0 %
      \csname eqcol@e#1\endcsname
    }%
  }%
}
\newcount\eqcol@count
\def\eqcolRead{%
  \global\advance\eqcol@count1 %
  \eqcol@oldlen5em\relax
  \csname eqcol@def@\romannumeral\eqcol@count\endcsname
}
\def\eqcolWrite{%
  \immediate\write\@auxout{%
  \gdef\expandafter\noexpand\csname eqcol@def@\romannumeral\eqcol@count\endcsname
    {\global\eqcol@oldlen\the\eqcol@newlen\relax}%
  }%
  \global\eqcol@newlen0pt\relax
}
\let\eqcol@old@tabular\tabular
\def\tabular{\eqcolRead\eqcol@old@tabular}
\let\eqcol@old@endtabular\endtabular
\def\endtabular{\eqcol@old@endtabular\eqcolWrite}
\makeatother

\begin{document}

\begin{tabular}{|el|er|}
\hline
111 & 22 \\\hline
33 & 4444444 \\\hline
\end{tabular}

\begin{tabular}{|ec|er|}
\hline
1 & 22 \\\hline
3 & 4 \\\hline
\end{tabular}

\begin{tabular}{|el|er|}
\hline
111 & 22 \\\hline
33 & 444444 \\\hline
\end{tabular}

\[
A =
  \eqcolRead\begin{array}{*3{ec}}
  1 & 10000 & 1 \\ 1 & 1 & 1
  \end{array}\eqcolWrite
\]

\end{document}

环境tabular默认经过调整，在其他情况下，您必须手动进行调整（参见array上面的示例）。

答案2

这是受到 tohecz 启发的，但使用专用环境，我认为这更好。

在 中，equalizedtabular可以使用任何列说明符，而不仅仅是L、C或R，但当然只有这些才会相等。由于.aux使用了文件，因此需要两次传递，并且在两次传递之间包含 时，equalizedtabular第一次编译将产生错误的结果；但是，下一次运行 LaTeX 将修复长度。

\documentclass{article}

\usepackage{array,collcell}

\newcolumntype{C}{>{\collectcell\docellC}c<{\endcollectcell}}
\newcolumntype{L}{>{\collectcell\docellL}c<{\endcollectcell}}
\newcolumntype{R}{>{\collectcell\docellR}c<{\endcollectcell}}

\makeatletter
\providecommand{\@nameedef}[1]{\expandafter\edef\csname#1\endcsname}
\newcommand{\docell}[2]{%
  \sbox\equalizedtablebox{#2}%
  \ifdim\wd\equalizedtablebox>\@nameuse{finallen\theequalizedtable}\relax
    \global\@nameedef{finallen\theequalizedtable}{\the\wd\equalizedtablebox}%
  \fi
  \makebox[\@nameuse{startinglen\theequalizedtable}][#1]{#2}%
}
\newcommand{\docellC}[1]{\docell{c}{#1}}
\newcommand{\docellL}[1]{\docell{l}{#1}}
\newcommand{\docellR}[1]{\docell{r}{#1}}
\newcounter{equalizedtable}
\newsavebox\equalizedtablebox
\newenvironment{equalizedtabular}[2][c]
  {%
   \stepcounter{equalizedtable}%
   \global\@namedef{finallen\theequalizedtable}{0pt}%
   \@ifundefined{startinglen\theequalizedtable}
    {\@namedef{startinglen\theequalizedtable}{5em}}{}
   \tabular[#1]{#2}%
  }
  {%
   \endtabular
   \begingroup\edef\x{\endgroup
     \write\@auxout{%
       \global\noexpand\noexpand\noexpand\@namedef{startinglen\theequalizedtable}%
     {\@nameuse{finallen\theequalizedtable}}%
   }}\x
  }
\makeatother
\begin{document}

\begin{equalizedtabular}{|L|C|}
\hline
111 & 22 \\\hline
33 & 4444444 \\\hline
\end{equalizedtabular}

\begin{equalizedtabular}{|R|C|}
\hline
111 & 22 \\\hline
33 & 4 \\\hline
\end{equalizedtabular}

\end{document}

在此处输入图片描述

答案3

我会稍微改变一下输入语法：

在此处输入图片描述

\documentclass{article}

\makeatletter
\def\paulo#1{\count@#1\relax\leavevmode\setbox\z@\vbox\bgroup}
\def\endpaulo{\egroup\dimen@\wd\z@\global\setbox\@ne\null
\setbox\z@\vbox{\unvbox\z@\loop\unskip\unskip\setbox\z@\lastbox
\ifvoid\z@\else
\global\setbox\@ne\hbox{\hbox to\dimen@{\box\z@\hfil}\penalty\z@\unhbox\@ne}%
\repeat}%
\vbox{\hsize\count@\dimen@\noindent\unhbox\@ne}}

\def\cell#1{\hbox{\kern\tabcolsep\ignorespaces#1\unskip\kern\tabcolsep}}

\makeatother
\begin{document}

\begin{paulo}{2}
\cell{a}
\cell{b}
\cell{c}
\cell{Mary had a little lamb}
\end{paulo}

\end{document}

答案4

这个答案与 egreg 的答案有点相似回答还有很多来自等式包裹。

\documentclass{article}

\usepackage{array}
\usepackage{eqparbox}

\makeatletter
\newcounter{eqtabular}
\newsavebox\eqtabularbox

\newcolumntype{C}{>{\begin{lrbox}{\eqtabularbox}}c<{\end{lrbox}%
                   \eqmakebox [\the\c@eqtabular @eqtabular]%
                              {\unhcopy\eqtabularbox}}}
\newcolumntype{L}{>{\begin{lrbox}{\eqtabularbox}}c<{\end{lrbox}%
                   \eqmakebox [\the\c@eqtabular @eqtabular][l]%
                              {\unhcopy\eqtabularbox}}}
\newcolumntype{R}{>{\begin{lrbox}{\eqtabularbox}}c<{\end{lrbox}%
                 \eqmakebox [\the\c@eqtabular @eqtabular][r]%
                            {\unhcopy\eqtabularbox}}}


\newenvironment{eqtabular}[2][c]
  {%
   \stepcounter{eqtabular}%
   \tabular[#1]{#2}%
  }
  {%
   \endtabular
  }
\makeatother

\begin{document}\thispagestyle{empty}

\begin{eqtabular}{|L|L|}
\hline
111 & 22 \\\hline
33 & 4444444 \\\hline
\end{eqtabular}

\begin{eqtabular}{|R|R|}
\hline
111 & 22 \\\hline
33 & 4444444 \\\hline
\end{eqtabular}

\begin{eqtabular}{|C|C|}
\hline
11111111111 & 22 \\\hline
33 & 4444444 \\\hline
\end{eqtabular}

\begin{eqtabular}{|R|L|}
\hline
11111111111 & 22 \\\hline
33 & 4444444 \\\hline
\end{eqtabular}

\begin{eqtabular}{|R|C|}
\hline
111 & 22 \\\hline
33 & 4 \\\hline
\end{eqtabular}

\begin{eqtabular}{|L|R|}
\hline
111 & 22 \\\hline
33 & 4 \\\hline
\end{eqtabular}

\end{document}

等式

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