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不需要的分页符

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不需要的分页符

一旦启动align环境，我的代码就会生成不需要的分页符。显示它的最佳方式是提供相关代码，以便有人可以编译它。

我的代码如下所示

\documentclass[a4paper]{article}
\usepackage[hmargin=2.5cm,vmargin=1cm]{geometry}
\usepackage{parskip}
\usepackage{amsmath}
\begin{document}
\section{Derivations}
\subsection{Derivations2}
bla bla 
\begin{equation}
c^i_1 + \frac{c^i_2}{1+r} + (n-r)\frac{x^i}{1+r}  = wl^i  -\tau 
\end{equation}

\begin{align}
& d(c^i_1) + d(\frac{c^i_2}{1+r}) + d((n-r)\frac{x^i}{1+r})   = d(wl^i)  -d(\tau) \\
& d(c^i_1) + \big[c^i_2 d(\frac{1}{1+r}) +  \frac{1}{1+r} dc^i_2 \big] + \big[x^i d(\frac{n-r}{1+r}) +  \frac{n-r}{1+r} dx^i \big]= d(wl^i)  -d(\tau) \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i  =  d(wl^i)  -d(\tau) - c^i_2 d(\frac{1}{1+r}) - x^i d(\frac{n-r}{1+r}) \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i  =  d(wl^i)  -d(\tau) - c^i_2 d(\frac{1}{1+r}) - x^i (n-r)d(\frac{1}{1+r}) - \frac{x^i}{1+r}d(n-r) \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i  =  d(wl^i)  -d(\tau) - c^i_2 d(\frac{1}{1+r}) - x^i (n-r)d(\frac{1}{1+r}) + \frac{x^i}{1+r}dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau) - \left[c^i_2 +  x^i (n-r) \right]d(\frac{1}{1+r}) + \frac{x^i}{1+r}dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \frac{\left[c^i_2 +  x^i (n-r) \right]}{(1+r)^2}d(r) + \frac{x^i}{1+r}dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \bigg( \frac{1}{1+r}\bigg)\frac{\left[c^i_2 +  x^i (n-r) \right]}{(1+r)}dr + \frac{x^i}{1+r}dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \bigg( \frac{1}{1+r}\bigg)(wl^i  -\tau  - c^i_1)d(r) + \frac{x^i}{1+r}dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \bigg( \frac{1}{1+r}\bigg)(\underbrace{wl^i + x^i -\tau  - c^i_1}_{s^i})dr  \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \bigg( \frac{s^i}{1+r}\bigg) dr \\
& d(c^i_1) +  \frac{1}{1+r} dc^i_2 + \frac{n-r}{1+r} dx^i =   d(wl^i)  -d(\tau)  + \bigg( \frac{s^i}{1+r}\bigg) dr +  \bigg( \frac{S}{1+r}\bigg)dr -  \bigg( \frac{S}{1+r}\bigg)dr \\
 & = d(wl^i) - d(\tau)  +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & = d(wl^i) - d[(r-n)b]  +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & = d(wl^i) - d[(r-n)b]  +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & = l^i dw - \left[(r-n)db + bdr \right] +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & = l^i (-k) dr - \left[(r-n)db + bdr \right] +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & =  - l^i k dr - (r-n)db - bdr - kdr + kdr +  \bigg( \frac{S}{1+r}\bigg)dr +  \bigg( \frac{s^ i - S}{1+r}\bigg)dr \\
 & = k (1-l^i)dr  - (k+b)dr - (r-n)db +  \bigg( \frac{S}{1+r}\bigg)dr +  \big( \frac{s^ i - S}{1+r}\big)dr \\
 & = - (k+b)dr - (r-n)db +  \bigg( \frac{S}{1+r}\bigg)dr + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr \\
 & = - \bigg[(k+b) - \big(\frac{S}{1+r}\big) \bigg]dr - (r-n)db + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr  \label{total change in life-cycle budget in general}\\
 & = - \bigg[(k+b) - \big(\frac{(1+n)(k+b)}{1+r}\big) \bigg]dr - (r-n)db + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr \\
 & = - \bigg[k + b -  \frac{(1+n)k}{1+r} - \frac{(1+n)b}{1+r}\bigg]dr - (r-n)db + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr \\
 & = - \bigg[\left(k -  \frac{(1+n)k}{1+r}\right) + \left( b- \frac{(1+n)b}{1+r}\right)\bigg]dr - (r-n)db + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr \\
 & = - \frac{r-n}{1+r} (k+b) dr - (r-n)db + \bigg[\big( \frac{s^ i - S}{1+r}\big) + k(1-l^i)\bigg] dr \label{total effect in the life-cycle budget}
\end{align}

\end{document}

我知道 LaTeXalign会尝试将其放在一页中，因为我有环境，但这会使另一页几乎为空。有办法修复它吗？任何帮助都将不胜感激。

答案1

请参阅文档中的\allowdisplaybreaks和。您还可以使用 放大页面。\displaybreakamsmathamsldoc\enlargethispage

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