我正在尝试使用多行选项创建一个表。我正在使用以下代码:
\documentclass[10pt]{article}
%\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{textcomp}
\usepackage{microtype}
\usepackage{graphicx}
\usepackage{multirow}
\begin{document}
\begin{table}[h]
\newcommand{\lambdabar}{{\mkern0.75mu\mathchar '26\mkern -9.75mu\lambda}}
\centering
\begin{tabular}{r@{=}ll}
\hline
\hline
$a_0$ & $\frac{\hbar^2}{m e^2}$
& \multirow{2}{7cm}{Bohr (radius of electron orbit in Bohr's model of Hydrogen)} \\
& $5.29\times10^{-9}$ & \\
$\lambdabar_c$ & $\alpha a_0 = \frac{\hbar}{m c}$
& \multirow{2}{7cm}{Reduced Compton wavelength ($\lambda_c = \lambda_c/2$). $ \lambda_c $ is change of wavelength of photon scattered at 90\textdegree by a stationary electron due to recoil of electron.} \\
& $3.86159\times10^{-11} $cm & \\
$ r_0 $ & $\alpha^2 a_0 = \alpha \lambdabar_c = \frac{d^2}{m c^2}$
& \multirow{2}{7cm}{Classical radius of electron (size for which electrostatic self energy equals rest mass energy)} \\
& $2.81794\times10^{-13}$cm & \\
\hline
\hline
\end{tabular}
\end{table}
\end{document}
我得到了以下输出:
这里我们可以看到最后两行出现在第三行和第四行。为什么会出现这种情况?如何才能使其正确?
答案1
multirow
不适用于在一个表格单元格中拥有更多行。为此,您应该使用适当类型的列,例如p{<column width>}
或使用tabularx
(如我在下面的示例中使用的)tabulary
等。对于数学内容,最好以某种方式声明表格列>{$}c<{$}
(或其他类型的列)。我希望下面的例子能够对您有所帮助。
\documentclass[10pt]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{textcomp}
\usepackage{tabularx}
\begin{document}
\begin{table}[h]
\newcommand{\lambdabar}{{\mkern0.75mu\mathchar '26\mkern -9.75mu\lambda}}
\renewcommand{\tabularxcolumn}[1]{m{#1}}
\renewcommand{\arraystretch}{1.4}
\centering
\begin{tabularx}{\hsize}{>{$}m{4cm}<{$}X}
\hline
\hline
a_0=\dfrac{\hbar^2}{m e^2}=5.29\times10^{-9}
& Bohr (radius of electron orbit in Bohr's model of Hydrogen) \\
\begin{aligned}
\lambdabar_c & =\alpha a_0 = \dfrac{\hbar}{m c}\newline\\
& = 3.86159\times10^{-11}\ \text{cm}
\end{aligned}
& Reduced Compton wavelength ($\lambda_c=\lambda_c/2$). $\lambda_c$ is change of wavelength of photon scattered at 90\textdegree by a stationary electron due to recoil of electron. \\
\begin{aligned}
r_0 & = \alpha^2 a_0 = \alpha\lambdabar_c = \dfrac{d^2}{m c^2}\\
& = 2.81794\times10^{-13}\ \text{cm}
\end{aligned}
& Classical radius of electron (size for which electrostatic self energy equals rest mass energy) \\
\hline
\hline
\end{tabularx}
\end{table}
\end{document}
答案2
这是 TABstacked 的替代方案。
\documentclass[10pt]{article}
%\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{textcomp}
\usepackage{microtype}
\usepackage{graphicx}
\usepackage{multirow}
\usepackage{tabstackengine}
\TABstackMath
\begin{document}
\begin{table}[ht]
\renewcommand\arraystretch{1.4}
\setstackgap{L}{1.3\normalbaselineskip}
\newcommand{\lambdabar}{{\mkern0.75mu\mathchar '26\mkern -9.75mu\lambda}}
\centering
\begin{tabular}{lp{2.65in}}
\hline
\hline
{\alignLongunderstack{a_0 =&\frac{\hbar^2}{m e^2}\\
=&5.29\times10^{-9}}}
& Bohr (radius of electron orbit in Bohr's model of Hydrogen) \\
{\alignLongunderstack{\lambdabar_c =& \alpha a_0 = \frac{\hbar}{m c}\\
=&3.86159\times10^{-11} \text{cm}}}
& Reduced Compton wavelength ($\lambda_c = \lambda_c/2$).
$ \lambda_c $ is change of wavelength of photon scattered
at 90\textdegree by a stationary electron due to recoil
of electron. \\
{\alignLongunderstack{ r_0 =& \alpha^2 a_0 = \alpha \lambdabar_c
= \frac{d^2}{m c^2}\\=&2.81794\times10^{-13} \text{ cm}}}
& Classical radius of electron (size for which electrostatic
self energy equals rest mass energy) \\
\hline
\hline
\end{tabular}
\end{table}
\end{document}
答案3
第三行(减少...)的文本占用 4 行,而不是 2 行。要修复此问题,您可以输入 '\multirow{2}...`,然后留下 2 个空行。
\documentclass[10pt]{article}
%\usepackage[utf8]{inputenc}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{textcomp}
\usepackage{microtype}
\usepackage{graphicx}
\usepackage{multirow}
\begin{document}
\begin{table}[h]
\newcommand{\lambdabar}{{\mkern0.75mu\mathchar '26\mkern -9.75mu\lambda}}
\centering
\begin{tabular}{r@{=}ll}
\hline
\hline
$a_0$ & $\frac{\hbar^2}{m e^2}$
& \multirow{2}{7cm}{Bohr (radius of electron orbit in Bohr's model of Hydrogen)} \\
& $5.29\times10^{-9}$ & \\
$\lambdabar_c$ & $\alpha a_0 = \frac{\hbar}{m c}$
& \multirow{4}{7cm}{Reduced Compton wavelength ($\lambda_c = \lambda_c/2$). $ \lambda_c $ is change of wavelength of photon scattered at 90\textdegree by a stationary electron due to recoil of electron.} \\
& $3.86159\times10^{-11} $cm & \\
\\
\\
$ r_0 $ & $\alpha^2 a_0 = \alpha \lambdabar_c = \frac{d^2}{m c^2}$
& \multirow{2}{7cm}{Classical radius of electron (size for which electrostatic self energy equals rest mass energy)} \\
& $2.81794\times10^{-13}$cm & \\
\hline
\hline
\end{tabular}
\end{table}
\end{document}
这会产生副作用,即=
在某些行中带有符号。我将从列规范中取出它们,并将第 1 列和第 2 列放在相同的位置。