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制作独立于 pgf 的表格

tag-icon • tag-icon tables pgfplotstable pgfmath journal-publishing
制作独立于 pgf 的表格

我用pgfplotstable它来生成要在线提交给期刊的表格。我希望我的论文能够独立于此，pgfplotsable因为文档的编译是使用过时的 LaTeX 发行版和笨拙的软件包处理在线完成的。

我已经问过一个这样的问题（见这个问题)，但现在我面临的情况更为复杂。通过这个，我了解了将表写入文件outfile=的命令选项。\pgfplotstabletypeset

我正在使用的一些功能pgfplotstable将表格中的数字替换为符号（灵感来自这个问题）这里有一个与我的实际代码类似的示例：

\documentclass{article}
\usepackage{pgfplotstable}

\begin{document}
\pgfplotstableset{symbol column/.style={column type=c,
    postproc cell content/.style={
      /pgfplots/table/@cell content={}{%
        \pgfmathparse{int(less(##1, 0.01))}
        \ifnum\pgfmathresult=1
        *
        \else
            \pgfmathparse{int(less(##1, .1))}
            \ifnum\pgfmathresult=1
            **
            \else
                \pgfmathparse{int(less(##1,1))}
                \ifnum\pgfmathresult=1
                ***
                \else
                { }
                \fi
            \fi
        \fi
      },
    },
}}





\pgfplotstabletypeset[outfile=output_table.tex,
columns/A/.style={symbol column},
columns/B/.style={symbol column},
]
{%
A B
.001 5
.1 .5
.2  .005
1.7 22
}
\end{document}

输出文件如下所示：

\begin {tabular}{cc}%
A&B\\%
{}{\pgfmathparse {int(less(.001, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(.001, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(.001,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }&{}{\pgfmathparse {int(less(5, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(5, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(5,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }\\%
{}{\pgfmathparse {int(less(.1, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(.1, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(.1,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }&{}{\pgfmathparse {int(less(.5, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(.5, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(.5,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }\\%
{}{\pgfmathparse {int(less(.2, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(.2, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(.2,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }&{}{\pgfmathparse {int(less(.005, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(.005, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(.005,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }\\%
{}{\pgfmathparse {int(less(1.7, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(1.7, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(1.7,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }&{}{\pgfmathparse {int(less(22, 0.01))} \ifnum \pgfmathresult =1 * \else \pgfmathparse {int(less(22, .1))} \ifnum \pgfmathresult =1 ** \else \pgfmathparse {int(less(22,1))} \ifnum \pgfmathresult =1 *** \else { } \fi \fi \fi }\\%
\end {tabular}%

这取决于pgf和\pgfmathparse相关命令。

有没有办法解决这个问题，而无需手动编辑表格或使用外部程序

答案1

一般来说这可能很难，但在这里你只使用 pgfmath 进行不等式测试，这是一个你可以避免的困难：

\documentclass{article}
\usepackage{pgfplotstable}



\begin{document}
\pgfplotstableset{symbol column/.style={column type=c,
    postproc cell content/.style={
      /pgfplots/table/@cell content={}{%
        \ifdim##1pt <0.01pt
        *
        \else
        \ifdim##1pt <0.1pt
            **
            \else
        \ifdim##1pt <1pt
                ***
                \else
                { }
                \fi
            \fi
        \fi
      },
    },
}}





\pgfplotstabletypeset[outfile=output_table.tex,
columns/A/.style={symbol column},
columns/B/.style={symbol column},
]
{%
A B
.001 5
.1 .5
.2  .005
1.7 22
}
\end{document}

生产

\begin {tabular}{cc}%
A&B\\%
{}{\ifdim .001pt <0.01pt * \else \ifdim .001pt <0.1pt ** \else \ifdim .001pt <1pt *** \else
 { } \fi \fi \fi }&{}{\ifdim 5pt <0.01pt * \else \ifdim 5pt <0.1pt ** \else \ifdim 5pt <1pt
 *** \else { } \fi \fi \fi }\\%
{}{\ifdim .1pt <0.01pt * \else \ifdim .1pt <0.1pt ** \else \ifdim .1pt <1pt *** \else { } \
fi \fi \fi }&{}{\ifdim .5pt <0.01pt * \else \ifdim .5pt <0.1pt ** \else \ifdim .5pt <1pt **
* \else { } \fi \fi \fi }\\%
{}{\ifdim .2pt <0.01pt * \else \ifdim .2pt <0.1pt ** \else \ifdim .2pt <1pt *** \else { } \
fi \fi \fi }&{}{\ifdim .005pt <0.01pt * \else \ifdim .005pt <0.1pt ** \else \ifdim .005pt <
1pt *** \else { } \fi \fi \fi }\\%
{}{\ifdim 1.7pt <0.01pt * \else \ifdim 1.7pt <0.1pt ** \else \ifdim 1.7pt <1pt *** \else { 
} \fi \fi \fi }&{}{\ifdim 22pt <0.01pt * \else \ifdim 22pt <0.1pt ** \else \ifdim 22pt <1pt
 *** \else { } \fi \fi \fi }\\%
\end {tabular}%

答案2

根据 Christian 的评论，我编写了以下代码：

\documentclass{article}
\usepackage{pgfplotstable}

\begin{document}
\newcommand{\filtercode}{%
       \pgfmathparse{int(less(\cellvalue, 0.01))}%
       \ifnum\pgfmathresult=1 %
       \edef\cellvalue{x}%
       \else
            \pgfmathparse{int(less(\cellvalue, .1))}%
            \ifnum\pgfmathresult=1 %
            \edef\cellvalue{xx}%
            \else
                \pgfmathparse{int(less(\cellvalue,1))}%
                \ifnum\pgfmathresult=1 %
                \edef\cellvalue{xxx}%
                \else
               \edef\cellvalue{Z}%
                \fi
            \fi
       \fi
        \toks0=\expandafter{\cellvalue}%
        \edef\value{{}\the\toks0}%
        %\show\value
        \pgfkeyslet{/pgfplots/table/create col/next content}\value
}

\pgfplotstableset{%
  create on use/AA/.style={create col/assign/.code={%
      \getthisrow{A}\cellvalue\filtercode}},%
  create on use/BB/.style={create col/assign/.code={%
      \getthisrow{B}\cellvalue\filtercode}},%
}

\pgfplotstabletypeset[outfile=output_table.tex,
columns/AA/.style={string type, column type=c},
columns/BB/.style={string type, column type=c},
    % debug,
    columns={AA, BB}
]
{%
A B
.001 5
.0001 .5
.2  .005
1.7 22
}

\end{document}

它产生这个输出

\begin {tabular}{cc}%
AA&BB\\%
{}x&{}Z\\%
{}x&{}xxx\\%
{}xxx&{}x\\%
{}Z&{}Z\\%
\end {tabular}%

这正是我所寻找的。

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