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在数学模式中拉伸数学符号

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在数学模式中拉伸数学符号

为了练习，我必须垂直拉伸总和和其他符号，例如

enter image description here

如您所见，尺寸在水平方向上没有变化。有什么建议吗？我已经找了很长时间了 :/

*注意，我没有这张图片的代码，练习是关于如何重新制作这张图片。

答案1

像这样？

enter image description here

当然，因为这是一个练习，我不应该透露我制作图像的代码。;-)

当然，基础\resizebox{1}[1.6]{...}在于graphicx包装。不过，正确的定位并不容易，但也不是很难。

这是注释代码

\documentclass{article}
\usepackage{graphicx,calc,amsmath}
\newcommand{\ssum}{%
  \mathop{%
    % get the dimensions of \sum in \displaystyle
    \sbox0{$\displaystyle\sum$}%
    % lower the stretched \sum by its height and raise it by the height
    % of the unstretched symbol; give it the height it should have
    % and the right depth
    \raisebox{-\height+\ht0}[\ht0][\dp0]{\scalebox{1}[1.6]{\copy0}}%
  }\displaylimits
}
\newcommand{\sbrace}[2]{%
  #1{% #1 is either \mathopen or \mathclose, #2 is \lbrace or \rbrace (or any delimiter)
    % get the dimensions of the unstretched delimiter so that
    % it covers \sum with subscript and superscript
    \sbox0{$\displaystyle\left#2\vphantom{\sum_{i=1}^{n}}\right.\kern-\nulldelimiterspace$}%
    % as before, place the symbol, but in this case we want its
    % depth to be zero; the stretching is somewhat different
    \raisebox{-\height+\ht0}[\ht0][0pt]{\scalebox{1}[1.7]{\copy0}}%
  }%
}
\newcommand{\slbrace}{\sbrace{\mathopen}{\lbrace}} % stretched left brace
\newcommand{\srbrace}{\sbrace{\mathclose}{\rbrace}} % stretched right brace

\begin{document}
\[
0=\ssum_{i=1}^{n} m(X_{i},\hat{\theta}_{i})
=\ssum_{i=1}^{n} m(X_{i},\hat{\theta}_{0})
+\slbrace
  \ssum_{i=1}^{n}\frac{\partial m(X_{i},\theta^{*}_{n})}{\partial \theta^{T}}
  \srbrace
  (\hat{\theta}_{n}-\theta_{0}).
\]
\textbf{\qquad l 2} \emph{Omdat $\hat{\theta}_{n}\xrightarrow{p}\theta^{*}_{0}$
en $\theta^{*}_{0}$ een waarde is die tussen $\hat{\theta}_{n}$ en 
$\theta^{*}_{0}$ ligt, zal}
\end{document}

我不确定学生是否真的应该知道所有这些，但也许教练会学到一些东西。;-)

答案2

针对 sigma 失真和括号失真进行了修订：

\documentclass{article}
\usepackage{scalerel}
\usepackage{stackengine}
\stackMath
\newcommand\ssum[1]{\stackunder[1pt]{\stackunder[-7pt]{%
  \stackon[1.5pt]{\displaystyle\stretchrel*{\sum}{\sum_{i_x}}}{\scriptstyle n}%
  }{\scriptstyle i=1}#1}{\rule{0ex}{3ex}}%
}
\begin{document}
\[ 
0 = \ssum{m(X_i,\hat\theta_n)} + \ssum{m(X_i,\theta_0)} +
\stretchleftright{\{}{\ssum{\frac{\partial m(X_i,\hat\theta_n^*)}{\partial\theta^T}}}{\}}%
(\hat\theta_n - \theta_0)
\]
\end{document}

enter image description here

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