我想使用groupplots
并设置一个变量来有条件地绘制图表。以下是最小的非工作示例:
\documentclass{article}
\usepackage{pgfplots}
\usetikzlibrary{calc}
\usepgfplotslibrary{groupplots}
\def\a{1}
\begin{document}
\begin{tikzpicture
\begin{groupplot}[group style={group size=1 by \a},height=3cm,width=6cm]
\ifnum\a>0{ %
\nextgroupplot[title=One]
\addplot coordinates {(0,0) (1,1) (2,2)};
\ifnum\a>1{ %
\nextgroupplot[title=Two]
\addplot coordinates {(0,2) (1,1) (2,0)};
\ifnum\a>2{ %
\nextgroupplot[title=Three]
\addplot coordinates {(0,2) (1,1) (2,1)};
\ifnum\a>3{ %
\nextgroupplot[title=Four]
\addplot coordinates {(0,2) (1,1) (1,0)};
}\fi
}\fi
}\fi
}\fi
\end{groupplot}
\node (title) at (0,0) {THE Title};
\end{tikzpicture}
\end{document}
失败原因:
! Extra }, or forgotten \endgroup.
l.24 }
\fi
不确定是不是因为嵌套的\ifnum
s,还是因为\nextgroupplot
;如果第一个\nextgroupplot
被注释掉,错误现在是:
! Undefined control sequence.
l.11 \addplot
coordinates {(0,0) (1,1) (2,2)};
可以进行这种有条件的群体地块绘制吗?
答案1
删除构造中的组使用groupplot
。我添加了一些缩进,并更正了小类型(}
环境开头缺失tikzpicture
):
\documentclass{article}
\usepackage{pgfplots}
\usetikzlibrary{calc}
\usepgfplotslibrary{groupplots}
\def\a{3}
\begin{document}
\begin{tikzpicture}
\begin{groupplot}[group style={group size=1 by \a},height=3cm,width=6cm]
\ifnum\a>0
\nextgroupplot[title=One]
\addplot coordinates {(0,0) (1,1) (2,2)};
\ifnum\a>1
\nextgroupplot[title=Two]
\addplot coordinates {(0,2) (1,1) (2,0)};
\ifnum\a>2
\nextgroupplot[title=Three]
\addplot coordinates {(0,2) (1,1) (2,1)};
\ifnum\a>3
\nextgroupplot[title=Four]
\addplot coordinates {(0,2) (1,1) (1,0)};
\fi
\fi
\fi
\fi
\end{groupplot}
\end{tikzpicture}
\end{document}