我的最低工作示例:
\documentclass{report}
\usepackage{amsmath}
\begin{document}
\begin{align}
x_1 = \alpha,\, x_2 = q,\, u = \delta \\
f_1(x_1) &= C_1 \left [ \phi_{z1}(x_1) + \phi_{z2}(x_1)M \right ] \\
f_2(x_1) &= C_2 \left [ \phi_{m1}(x_1) + \phi_{m2}(x_1)M \right ] \\
g_1 = C_1 b_z,\, g_2 = C_2 b_m \\
C_1 = \frac{\bar{q}S}{mV_T},\, C_2 = \frac{\bar{q}Sd}{I_{yy}}
\end{align}
\end{document}
结果:
我想要的是:
答案1
据我了解,您希望将C_1
最后一行移至左侧。(如果不是,只需删除\!
)。但是,我建议将 替换,\,
为,\quad
。
\documentclass{report}
\usepackage{amsmath}
\begin{document}
\begin{align}
&x_1 = \alpha,\, x_2 = q,\, u = \delta \\
&f_1(x_1) = C_1 \left [ \phi_{z1}(x_1) + \phi_{z2}(x_1)M \right ] \\
&f_2(x_1) = C_2 \left [ \phi_{m1}(x_1) + \phi_{m2}(x_1)M \right ] \\
&g_1= C_1 b_z,\, g_2 = C_2 b_m \\
&\!C_1 = \frac{\bar{q}S}{mV_T},\, C_2 = \frac{\bar{q}Sd}{I_{yy}}
\end{align}
\end{document}
答案2
Przemyslaw 的答案给出了您想要的输出,但是如果您的方程组变得更加复杂(例如,您想要对齐具有不同对齐点的两组方程),那么您可以aligned
在内部使用gather
您想要对齐的两个方程:
\documentclass{report}
\usepackage{amsmath}
\begin{document}
\begin{gather}
x_1 = \alpha,\, x_2 = q,\, u = \delta \\
\begin{aligned}
f_1(x_1) &= C_1 \left [ \phi_{z1}(x_1) + \phi_{z2}(x_1)M \right ] \\
f_2(x_1) &= C_2 \left [ \phi_{m1}(x_1) + \phi_{m2}(x_1)M \right ] \\
\end{aligned}\\
g_1 = C_1 b_z,\, g_2 = C_2 b_m \\
C_1 = \frac{\bar{q}S}{mV_T},\, C_2 = \frac{\bar{q}Sd}{I_{yy}}
\end{gather}
\end{document}