我使用算法包在 latex 中创建伪代码源。我有一个包含许多简短 if 语句的源。每次都将 END(来自 EndIf)放在新行中,这会导致布局冗长:
\documentclass[11pt,a4paper,leqno,fleqn]{article}
\usepackage{algpseudocode}
\usepackage[Algorithmus]{algorithm}
\begin{document}
\begin{algorithm}
\caption{WHILE-Modulo}
\begin{algorithmic}[1]
\Require f($x_1,x_2$)
\State $x_z := 1$
\While{$x_z \not = 0$}
\If{$x_z = 1$} \If{$x_1 = 0$} $x_z = 10$ \EndIf \EndIf
\If{$x_z = 2$} $x_3 := x_1 \dot{-}x_2$\EndIf
\If{$x_z = 3$} $x_4 := x_2 \dot{-}x_1$\EndIf
\If{$x_z = 4$} \If{$x_3 = 0$} $x_z = 7$\EndIf \EndIf
\If{$x_z = 5$} $x_1 := x_3$\EndIf
\If{$x_z = 6$} $x_z = 2$\EndIf
\If{$x_z = 7$} \If{$x_4 = 0$} $x_z = 9$\EndIf \EndIf
\If{$x_z = 8$} $x_z = 10$\EndIf
\If{$x_z = 9$} $x_1 := x_1 \dot{-} x_2$\EndIf
\If{$x_z = 10$} $x_z = 0$\EndIf
\If{$x_z = 11$} $x_z = 0$\EndIf
\EndWhile
\end{algorithmic}
\end{algorithm}
\end{document}
导致这样的输出:
但是,我希望单个 If 语句位于一行中,类似于:
您有什么想法吗?我非常感谢您的所有意见
答案1
您可以使用以下命令创建自己的“中级 IF”(或单行 IF)语句:
\documentclass{article}
\usepackage{algpseudocode}
\usepackage[Algorithmus]{algorithm}
\algnewcommand{\IIf}[1]{\State\algorithmicif\ #1\ \algorithmicthen}
\algnewcommand{\EndIIf}{\unskip\ \algorithmicend\ \algorithmicif}
\begin{document}
\begin{algorithm}
\caption{WHILE-Modulo}
\begin{algorithmic}[1]
\Require f($x_1,x_2$)
\State $x_z := 1$
\While{$x_z \not = 0$}
\If{$x_z = 1$} \IIf{$x_1 = 0$} $x_z = 10$ \EndIIf \EndIf
\IIf{$x_z = 2$} $x_3 := x_1 \dot{-}x_2$\EndIIf
\IIf{$x_z = 3$} $x_4 := x_2 \dot{-}x_1$\EndIIf
\If{$x_z = 4$} \IIf{$x_3 = 0$} $x_z = 7$\EndIIf \EndIf
\IIf{$x_z = 5$} $x_1 := x_3$\EndIIf
\IIf{$x_z = 6$} $x_z = 2$\EndIIf
\If{$x_z = 7$} \IIf{$x_4 = 0$} $x_z = 9$\EndIIf \EndIf
\IIf{$x_z = 8$} $x_z = 10$\EndIIf
\IIf{$x_z = 9$} $x_1 := x_1 \dot{-} x_2$\EndIIf
\IIf{$x_z = 10$} $x_z = 0$\EndIIf
\IIf{$x_z = 11$} $x_z = 0$\EndIIf
\EndWhile
\end{algorithmic}
\end{algorithm}
\end{document}