电力电子逆变器的乳胶代码

Question

我需要一个代码才能获得以下电路图。

Answer 1

下面是一个使用的示例circuitikz：

\documentclass{article}

\usepackage{tikz}
\usepackage{circuitikz}

\begin{document}

\tikzset{full Schottky diode/.append style={bipoles/length=.4cm}}
\tikzset{american voltages}
\tikzset{american inductors}
\tikzset{european resistors}
\begin{circuitikz}
    % TRANSISTORS
    \draw
        (0,2) node[nigfete] (t1) {}
        (0,0) node[nigfete] (t2) {}
        (2,2) node[nigfete] (t3) {}
        (2,0) node[nigfete] (t4) {};
    \draw
        (t1.S) to[short] (t2.D)
        (t3.S) to[short] (t4.D);
    % DIODES and transistor labels
    \foreach \num in {1,2,3,4} {
        \node[anchor=south] at (t\num.G) {$T_\num$};
        \draw (t\num.S)++(0,0.5) -- ++(0.3,0) to[sD*] ($(t\num.D)+(0.3,-0.5)$) -- ++(-0.3,0);
    }          
    % BATTERY connection
    \draw
        (t4.S) to[short,-*] (t2.S) to[short] ($(t2.S)+(-2,0)$)
        to[battery,l=$U$] ($(t1.D)+(-2,0)$) to[short,-*] (t1.D) to[short] (t3.D);
    % RL
    \draw
        (t1.S) to[short,*-] ($(t1.S)+(3,0)$) to[short] ($(t1.D)+(3,0)$) coordinate (p1)
        to[R,l_=$R$] ++(2,0) to[L,l_=$L$,i>^=$i_L$] ++(3,0) coordinate (p);
    \draw
        (t4.D) to[short,*-] ($(t4.D)+(1,0)$) to[short] ($(t4.S)+(1,0)$) coordinate (n1)
        to[short] ++(5,0) coordinate (n);
    % C
    \draw
        (p) to[C,l=$C$,i>^=$i_C$,v<=$U_C$] (n);
    % LOAD
    \draw
        (p) to[short,*-]($(p)+(2,0)$) to[R,l=$LOAD$,i>^=$i_o$] ($(n)+(2,0)$) to[short,-*] (n);
    % U_i
    \draw
        (p1) to[open,v^=$U_i$] (n1);
\end{circuitikz}

\end{document}

\documentclass{article}

\usepackage{tikz}
\usepackage{circuitikz}

\begin{document}

\tikzset{diode/.append style={bipoles/length=1cm}}
\tikzset{polar capacitor/.append style={bipoles/length=.7cm}}
\tikzset{inductor/.append style={bipoles/length=1cm}}
\tikzset{american voltages}
\tikzset{american inductors}
\tikzset{cute inductors}

\begin{circuitikz}
    \ctikzset{label/align = straight}
    % UPPER PART
    \draw
        (0,0) to[battery] (0,2) to[D]
        (2,2) coordinate (l11) to [L,l=$L_1$] ++(2,0) coordinate (l12);
    % LOWER PART
    \draw
        (0,0) to[short] 
        (2,0) coordinate (l21) to[L,l_=$L_2$] ++(2,0) coordinate (l22);
    % the crossing point of the capacitors
    \coordinate (c) at ($(l11)+(1,-1)$);
    % CAPACITORS
    \draw 
        (l22) to[short,*-] (c) to[pC,l=$C_1$,-*] (l11);
    \draw
        (l21) to[short,*-] (c) to[pC,l_=$C_2$,-*] (l12);
    % 3-PHASE INVERTER
    \foreach \n in {0,1,2} {
        \draw
            (l22) to[short] ++(\n+1,0) to[cspst] ++(0,.75) to[short] ++(0,.5) coordinate (p\n)
            to[cspst] ++(0,.75) to (l12);
        \draw ($(p\n)+(0,-\n*.25)$) to[short,*-o] ++(3.5-\n,0) coordinate (o\n);
    }
    % LABELS
    \node[anchor=north] at (o2) {\parbox{1.5cm}{\scriptsize To AC load or motor}};
    \node[anchor=north] at ($(c)+(0,2.5)$) {\scriptsize Z Source};
    \node[anchor=north] at ($(p1)+(0,2.5)+(0,-.25)$) {\scriptsize 3-Phase Inverter};
    \node[anchor=north west] at ($(0,0)+(0,2.5)+(0,1)$) {\parbox{2cm}{\scriptsize DC-Voltage Source}};
\end{circuitikz}

\end{document}