在 Tikz 中绘制线条

Question

我对 Tikz 还比较陌生，正在尝试绘制一个带有线条的图表。这是我的 MWE

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix,positioning}
\usetikzlibrary{decorations.pathreplacing}

\begin{document}
\[
\begin{tikzpicture}
\draw (0,0.9) -- (3.0,0.9) -- (3.0,-0.9) -- (0,-0.9) -- (0,0.9);
\draw (1.0,-0.9) -- (1.0,0.9);
\draw (2.0,-0.9) -- (2.0,0.9);
\path (1.1,0.6) node (p9) {};
\path (1.1,0.2) node (p10) {};
\path (1.1,-0.2) node (p11) {};
\path (1.1,-0.6) node (p12) {};
\path (1.9,0.6) node (p13) {};
\path (1.9,0.2) node (p14) {};
\path (1.9,-0.2) node (p15) {};
\path (1.9,-0.6) node (p16) {};
\path (2.1,0.6) node (p17) {};
\path (2.1,0.2) node (p18) {};
\path (2.1,-0.2) node (p19) {};
\path (2.1,-0.6) node (p20) {};
\path (2.9,0.6) node (p21) {};
\path (2.9,0.2) node (p22) {};
\path (2.9,-0.2) node (p23) {};
\path (2.9,-0.6) node (p24) {};
\draw  (p9) to [bend left=10] (p17);
\draw  (p10) to [bend left=10] (p18);
\draw  (p11) to [bend left=10] (p19);
\draw  (p12) to [bend left=10] (p20);
\draw  (p13) to [bend right=10] (p21);
\draw  (p14) to [bend right=10] (p22);
\draw  (p15) to [bend right=10] (p23);
\draw  (p16) to [bend right=10] (p24);
\end{tikzpicture}
\]
\end{document}

输出结果如下

有人能解释为什么曲线似乎没有击中正确的节点吗？

编辑：为了澄清情况，问题在于为什么这些线似乎没有到达相关节点的中心。以下答案已解决此问题。

Answer 1

曲线与节点相交，但即使是空节点也有宽度和高度。为了说明这一点，绘制了第二张图中的节点。也许您想定义coordinates 而不是node像第三张图中那样定义 s：

代码：

\documentclass[margin=5mm,tikz]{standalone}

\usepackage{tikz}

\begin{document}
\begin{tikzpicture}[
  green!40!black,
  colored/.style={fill=#1!20,draw=#1!50!black!50}
]
\draw[help lines, step=0.5] (0,0)grid(2,1);
\path (0.5,0.5) node (p1) {};
\path (1,0.5) node (p2) {};
\draw (p1) to [bend left=10] (p2);
%
\begin{scope}[yshift=-1.1cm]
\draw[help lines, step=0.5] (0,0)grid(2,1);
\path (0.5,0.5) node[colored=red] (p3) {};
\path (1,0.5) node[colored=blue] (p4) {};
\draw (p3) to [bend left=10] (p4);
\end{scope}

\draw[dotted](p1.east)--(p3.east)(p2.west)--(p4.west);
%
\begin{scope}[yshift=-2.2cm]
\draw[help lines, step=0.5] (0,0)grid(2,1);
\path (0.5,0.5) coordinate (p5);
\path (1,0.5) coordinate (p6);
\draw (p5) to [bend left=10] (p6);
\end{scope}
\end{tikzpicture}
\end{document}

Answer 2

没有理由将您的 tikz 图片放在显示的数学环境中（即删除括号 \[ \]）。

当您使用“to”时，tikz 将绘制一条连接到节点外部边界的边（未在图片中绘制但仍在计算）比较：

\documentclass{scrartcl}
\usepackage{tikz}
\begin{document}
\begin{tikzpicture}
\node[draw](x){};
\node[draw](y) at (2cm,0){};
\draw (x) to [bend left=10] (y);
\draw[red] (x.center) to [bend right=10] (y.center);
\end{tikzpicture}
\end{document}

PS：请尝试实际制作一个最小工作示例，并更精确地说明问题是什么。我不确定我是否理解了你在问什么。;)

Answer 3

我同意 @Echsecutor 的评论，不清楚你想要的结果是什么。为了用你的例子来说明那个发帖人的观点，看看根据你指定终点的方式绘制线条的不同。

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{matrix,positioning}
\usetikzlibrary{decorations.pathreplacing}
\begin{document}
\[
\begin{tikzpicture}
\draw (0,0.9) -- (3.0,0.9) -- (3.0,-0.9) -- (0,-0.9) -- (0,0.9);
\draw (1.0,-0.9) -- (1.0,0.9);
\draw (2.0,-0.9) -- (2.0,0.9);
\path (1.1,0.6) node (p9) {};
\path (1.1,0.2) node (p10) {};
\path (1.1,-0.2) node (p11) {};
\path (1.1,-0.6) node (p12) {};
\path (1.9,0.6) node (p13) {};
\path (1.9,0.2) node (p14) {};
\path (1.9,-0.2) node (p15) {};
\path (1.9,-0.6) node (p16) {};
\path (2.1,0.6) node (p17) {};
\path (2.1,0.2) node (p18) {};
\path (2.1,-0.2) node (p19) {};
\path (2.1,-0.6) node (p20) {};
\path (2.9,0.6) node (p21) {};
\path (2.9,0.2) node (p22) {};
\path (2.9,-0.2) node (p23) {};
\path (2.9,-0.6) node (p24) {};
\draw  (p9) to [bend left=10] (p17.center);
\draw  (p10) to [bend left=10] (p18.west);
\draw  (p11) to [bend left=10] (p19.east);
\draw  (p12) to [bend left=10] (p20);
\draw  (p13) to [bend right=10] (p21);
\draw  (p14) to [bend right=10] (p22);
\draw  (p15) to [bend right=10] (p23);
\draw  (p16) to [bend right=10] (p24);
\end{tikzpicture}
\]
\end{document}

有结果