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eqparbox 导致 \hline 和 \hdashline 出现错误

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eqparbox 导致 \hline 和 \hdashline 出现错误

编译下面的 MWE 时，我收到错误“未定义控制序列 \hline”和“未定义控制序列 \hdashline”。该问题是由eqparbox包，因为代码在没有它的情况下也能很好地编译 - 除了在算法部分对齐注释（这正是我使用的原因eqparbox）。单独编译表和算法（见下文）不会出现任何错误。

\documentclass[12pt]{report}
\usepackage{arydshln}
\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{trimspaces}
\usepackage{eqparbox}
\renewcommand{\algorithmiccomment}[1]{\hfill\eqparbox{COMMENT}{\% #1}}

\begin{document}

\begin{table}[htbp]
\caption{A simple table with horizontal and dashed horizontal lines.}
\label{tab:Simple}
\begin{center}
\begin{tabular}{l|c|c|c|c|c|c|}
      & \textbf{A} & \textbf{B} & \textbf{C} & \textbf{D} & \textbf{E} & \textbf{F} \\
    \hline
    \textbf{A} & 0 & 1 & 0 & 0 & 1 & 1 \\
    \hdashline
    \textbf{B} & 1 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{C} & 0 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{D} & 0 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{E} & 1 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{F} & 1 & 0 & 0 & 0 & 0 & 0 \\
    \hline
\end{tabular}
\end{center}
\end{table}

\begin{algorithm}
\caption{Euclid's algorithm}\label{alg:Euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}
\Comment{The g.c.d. of a and b}
\State $r \gets a \bmod b$
\While{$r \neq 0$}
\Comment{We have the answer if r is 0}
    \State $a \gets b$
    \State $b \gets r$
    \State $r \gets a \bmod b$
\EndWhile\label{euclidendwhile}
\State \textbf{return} $b$
\Comment{The gcd is b}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\end{document}

关于如何解决此问题的任何想法，以便表格看起来像：

\documentclass[12pt]{report}
\usepackage{arydshln}

\begin{document}

\begin{table}[htbp]
\caption{A simple table with horizontal and dashed horizontal lines.}
\label{tab:Simple}
\begin{center}
\begin{tabular}{l|c|c|c|c|c|c|}
      & \textbf{A} & \textbf{B} & \textbf{C} & \textbf{D} & \textbf{E} & \textbf{F} \\
    \hline
    \textbf{A} & 0 & 1 & 0 & 0 & 1 & 1 \\
    \hdashline
    \textbf{B} & 1 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{C} & 0 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{D} & 0 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{E} & 1 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{F} & 1 & 0 & 0 & 0 & 0 & 0 \\
    \hline
\end{tabular}
\end{center}
\end{table}

\end{document}

算法如下：

\documentclass[12pt]{report}
\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{trimspaces}
\usepackage{eqparbox}
\renewcommand{\algorithmiccomment}[1]{\hfill\eqparbox{COMMENT}{\% #1}}

\begin{document}

\begin{algorithm}
\caption{Euclid's algorithm}\label{alg:Euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}
\Comment{The g.c.d. of a and b}
\State $r \gets a \bmod b$
\While{$r \neq 0$}
\Comment{We have the answer if r is 0}
    \State $a \gets b$
    \State $b \gets r$
    \State $r \gets a \bmod b$
\EndWhile\label{euclidendwhile}
\State \textbf{return} $b$
\Comment{The gcd is b}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\end{document}

答案1

只需调整加载顺序，使其eqparbox位于之前arydshln：

示例输出

\documentclass[12pt]{report}
\usepackage{algorithm}
\usepackage{algpseudocode}
\usepackage{trimspaces}
\usepackage{eqparbox}
\usepackage{arydshln}
\renewcommand{\algorithmiccomment}[1]{\hfill\eqparbox{COMMENT}{\% #1}}

\begin{document}

\begin{table}[htbp]
\caption{A simple table with horizontal and dashed horizontal lines.}
\label{tab:Simple}
\begin{center}
\begin{tabular}{l|c|c|c|c|c|c|}
      & \textbf{A} & \textbf{B} & \textbf{C} & \textbf{D} & \textbf{E} & \textbf{F} \\
    \hline
    \textbf{A} & 0 & 1 & 0 & 0 & 1 & 1 \\
    \hdashline
    \textbf{B} & 1 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{C} & 0 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{D} & 0 & 0 & 1 & 0 & 1 & 0 \\
    \hdashline
    \textbf{E} & 1 & 1 & 0 & 1 & 0 & 0 \\
    \hdashline
    \textbf{F} & 1 & 0 & 0 & 0 & 0 & 0 \\
    \hline
\end{tabular}
\end{center}
\end{table}

\begin{algorithm}
\caption{Euclid's algorithm}\label{alg:Euclid}
\begin{algorithmic}[1]
\Procedure{Euclid}{$a,b$}
\Comment{The g.c.d.\ of $a$ and $b$}
\State $r \gets a \bmod b$
\While{$r \neq 0$}
\Comment{We have the answer if $r$ is $0$}
    \State $a \gets b$
    \State $b \gets r$
    \State $r \gets a \bmod b$
\EndWhile\label{euclidendwhile}
\State \textbf{return} $b$
\Comment{The g.c.d.\ is $b$}
\EndProcedure
\end{algorithmic}
\end{algorithm}

\end{document}

请注意，我还修复了您特定评论中的标记，添加了数学模式并修复了缩写点后的间距。

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