☰

如何绘制3结和4结SQUID？

tag-icon • tag-icon tikz-pgf symbols circuitikz
如何绘制3结和4结SQUID？

更新

感谢 John Kormylo，我能够使用以下四个组件绘制 4 结 SQUID： 4 连接鱿鱼构建块 http://www.tau.ac.il/~suhuvale/squid4elem.png

整个 SQUID 4 连接鱿鱼构建块 http://www.tau.ac.il/~suhuvale/squid4jcombined.png 使用以下代码绘制

\documentclass{article}
\usepackage{tikz}
\usepackage{circuitikz}`

\newlength{\ResUp} \newlength{\ResDown}
\newlength{\ResLeft} \newlength{\ResRight}
\newlength{\ResLen} \newlength{\ResRadius}
\newlength{\whereamix} \newlength{\whereamiy}

\makeatletter
\def\TikzBipolePath#1#2{\pgf@circ@bipole@path{#1}{#2}}
\def\CircDirection{\pgf@circ@direction}

\pgf@circ@Rlen = \pgfkeysvalueof{/tikz/circuitikz/bipoles/length}
\setlength{\ResLen}{\pgf@circ@Rlen}
\makeatother

%%%%%%%%%%%%%%%%%%%%%%% squid4 %%%%%%%%%%%%%%%%%%%%%%%%%
\ctikzset{bipoles/squid4/height/.initial=.6}
\ctikzset{bipoles/squid4/width/.initial=.6}

\pgfcircdeclarebipole{}{\ctikzvalof{bipoles/squid4/height}}
{squid4}
{\ctikzvalof{bipoles/squid4/height}}
{\ctikzvalof{bipoles/squid4/width}}
{
\pgfsetlinewidth{\ctikzvalof{bipoles/thickness}\pgfstartlinewidth}
\pgfextractx{\ResRight}{\northeast}
\pgfextracty{\ResUp}{\northeast}
\pgfextractx{\ResLeft}{\southwest}
\pgfextracty{\ResDown}{\southwest}

\pgfpathmoveto{\pgfpoint{1\ResLeft}{0\ResDown}}
\pgfpatharc{0}{-90}{1\ResLeft}%{\pgfpoint{0cm}{0.8\ResUp}}
\pgfpathmoveto{\pgfpoint{0\ResLeft}{-1\ResDown}}
\pgfpatharc{-90}{-45}{1\ResLeft}

\pgfpathlineto{\pgfpoint{0.35\ResLeft}{0.707\ResUp}}
\pgfpathlineto{\pgfpoint{1.064\ResLeft}{0.707\ResUp}}
\pgfpathmoveto{\pgfpoint{0.707\ResLeft}{-0.35\ResDown}}
\pgfpathlineto{\pgfpoint{0.707\ResLeft}{1.064\ResUp}}
\pgfusepath{draw}   
}

\def\mysquidpath#1{\TikzBipolePath{squid4}{#1}}
\tikzset{squid4/.style = {\circuitikzbasekey, /tikz/to path=\mysquidpath, l=#1}}

\begin{document}
\begin{circuitikz}[scale=1] 
\draw (1,1) to [squid4, i^>=$I_1$] (-1,-1); 
\draw (-1,-1) to [squid4, i^<=$I_1$] (1,1); 
\draw (1,-1) to [squid4, i^<=$I_2$] (-1,1); 
\draw (-1,1) to [squid4, i^>=$I_2$] (1,-1); 
\end{circuitikz} \\
\end{document}

我对 3 结 SQUID 仍有疑问。如能得到任何帮助，我将不胜感激。

我正在使用 circuitikz 绘制包含 SQUID 磁力计的电路图。该包包含乌贼标准 2 结 S​​QUID 的符号。使用代码： \documentclass{article} \usepackage{tikz} \usepackage{circuitikz} \begin{document} \begin{circuitikz}[scale=1] \draw (0,1.8) to [squid, l^=$J_1$, i^>=$I_2$] (0,-0.5) (0,1.8) to [squid, l_=$J_2$, i>^=$I_1$] (0,-0.5); \end{circuitikz} \end{document}

我可以画出 SQUID：

2 结 S​​QUID http://www.tau.ac.il/~suhuvale/SQUID2JJ.png

现在，我想画一个像这样的 3 结 SQUID：

3 结 SQUID http://www.tau.ac.il/~suhuvale/SQUID3JJ.png

以及像这样的4结SQUID：

4 结 SQUID http://www.tau.ac.il/~suhuvale/SQUID4JJ.png

我该如何绘制这些符号？

答案1

squid由于中有一个 2 结 S​​QUID circuitikz，因此建议的解决方案修改squid为\squidthree和\squidfourviarenewcommand语法以绘制 OP 中显示的符号。每个符号都有内部输入/输出标签，称为a1,b1,c1和a2,b2,c2,d2逆时针，以便它们可用于连接 在此处输入图片描述

代码

\documentclass[border=1cm]{standalone}  
\usepackage{tikz}
\usepackage[american,siunitx]{circuitikz}

\newcommand{\squidthree}[1] 
{  % #1 = name , 
\draw[thick] (#1) circle (12pt);
\draw (#1) ++(0,12pt)    coordinate(a1);
\draw (#1) ++(-135:12pt) coordinate(b1);
\draw (#1) ++(-45:12pt)  coordinate(c1);
\draw[rotate=60,line width=1pt]   (#1)  
+(0,16pt)node[above left]{\tiny${J}_{1}$} -- +(0,8pt)  
+(-4pt,12pt) -- +(4pt,12pt);
\draw[rotate=-60,line width=1pt]  (#1)  
+(0,16pt)node[above right]{\tiny${J}_{3}$} -- +(0,8pt) 
+(-4pt,12pt) -- +(4pt,12pt);
\draw[rotate=0,line width=1pt]    (#1)  
+(0,-16pt)node[below]{\tiny${J}_{2}$} -- +(0,-8pt) 
+(-4pt,-12pt) -- +(4pt,-12pt);
}


\newcommand{\squidfour}[1] 
{  % #1 = name , 
\draw[thick] (#1) circle (12pt);
\draw (#1) ++(90:12pt)  coordinate(a2);
\draw (#1) ++(180:12pt) coordinate(b2);
\draw (#1) ++(270:12pt) coordinate(c2);
\draw (#1) ++(0:12pt)   coordinate(d2);
\draw[rotate=45,line width=1pt]   (#1)  
+(0,16pt)node[above left]  {\tiny${J}_{1}$} -- +(0,8pt)  
+(0,-16pt)node[below right]{\tiny${J}_{3}$} -- +(0,-8pt) 
+(-4pt,12pt) -- +(4pt,12pt)  
+(-4pt,-12pt) -- +(4pt,-12pt);
\draw[rotate=-45,line width=1pt]  (#1)  
+(0,16pt)node[above right]{\tiny${J}_{4}$} -- +(0,8pt)   
+(0,-16pt)node[below left]{\tiny${J}_{2}$} -- +(0,-8pt) 
+(-4pt,12pt)  -- +(4pt,12pt)  
+(-4pt,-12pt) -- +(4pt,-12pt);
}

\begin{document}  

\begin{circuitikz}[scale=1] 

\node at (0,2) {2-junc SQUID};

\draw (0,1) to [squid, l^=$J_1$, i^>=$I_2$] (0,-1) 
         (0,1) to [squid, l_=$J_2$, i>^=$I_1$] (0,-1); 

\node at (3,2) {3-junc SQUID};

\path (3,1) to[squid,color=white,name=S1](3,-1);
\squidthree{S1} % at (2,0)
\draw (3,1.3) to[short,i=$I_1$]      (a1);
\draw (b1)    to[short,i_=$I_1-I_2$] (2,-1);
\draw (c1)    to[short,i=$I_2$]      (4,-1);

\node at (6,2){4-junc SQUID};

\path (6,1) to[squid,color=white,name=S2](6,-1);
\squidfour{S2}  % at (4,0)
\draw (6,1.3) to[short,i=$I_1$](a2);
\draw (4.7,0) to[short,i=$I_2$](b2);
\draw (c2)    to[short,i=$I_1$](6,-1.3);
\draw (d2)    to[short,i=$I_2$](7.3,0);

\end{circuitikz} 

\end{document}

相关内容