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我想修改下面的模板，以便每张纸打印出 1 个问题。例如：问题 1 在第 1-3 页，问题 2 在第 5-6 页，第 4 页上没有任何内容。另一个示例：问题 1 在第 1-2 页，问题 2 在第 3-5 页，第 6 页上没有任何内容，问题 3 在第 7 页。

模板是

\documentclass[letterpaper,12pt,twoside]{article}

\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage[letterpaper, top = 1.5in, left = 1in, right = 1in, bottom = 1.5in]  
\usepackage{fancyhdr}       
\usepackage{amsfonts,amsmath,amsthm,amssymb}
\usepackage{parskip}

\title{}
\author{Author}     
\date{\today}               

\makeatletter               
\let\Author\@author         
\let\Date\@date             
\makeatother

\newcommand{\Problem}{\relax}
\newcounter{problemcount}
\newcommand{\nextproblem}[1]{\renewcommand{\Problem}{#1}\setcounter{equation {0}\setcounter{page}{0}}

\pagestyle{fancy}
\lhead{\Problem}
\chead{}
\rhead{
\Author
\\
Class
\\
Section
\\
\Date
}

\renewcommand{\headrulewidth}{0.4pt}
\setlength{\headheight}{56.2pt}
\setlength{\parindent}{0pt}

\makeatother

\begin{document}
\nextproblem{Problem 1}
\begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}
\newpage

\nextproblem{Problem 2}\begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}

\end{document}

答案1

这修复了您的示例，稍微清理了序言并实现了\cleardoublepage：

\documentclass[letterpaper,12pt,twoside]{article}

\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage[top = 1.5in, left = 1in, right = 1in, bottom = 1.5in, headheight=56.2pt]{geometry}% tell geometry about the head height
\usepackage{fancyhdr}
\usepackage{amsfonts,amsmath,amsthm,amssymb}
\usepackage{parskip}% already sets parindent to zero - no need to do it yourself later as well
\usepackage{kantlipsum}

\title{}
\author{Author}
\date{\today}

\makeatletter
\let\Author\@author% consider using the titling package if you need commands like this
\let\Date\@date
\makeatother

\newcommand{\Problem}{\relax}
\newcounter{problemcount}
\newcommand{\nextproblem}[1]{%
  \cleardoublepage
  \renewcommand{\Problem}{#1}%
  \setcounter{equation}{0}}% if you want problem 2 on pages 5-6, better not reset the page count to zero!

\pagestyle{fancy}
\lhead{\Problem}
\chead{}
\rhead{
  \Author
  \\
  Class
  \\
  Section
  \\
  \Date
}

\makeatother

\begin{document}
  \nextproblem{Problem 1}
  \begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}
  \kant[1-8]

  \nextproblem{Problem 2}\begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}
  \kant[9-14]

\end{document}

问题 1 在第 1-3 页，空白页 4，问题 2 在第 5-6 页

更新

受 Christopher Hupfer 建议的启发，本文尝试进一步整理代码。由于您不太清楚自己想要做什么，因此这可能不是您想要的。但是，它至少应该能给您一些启发。

我按照 Christopher Hupfer 的建议使用。我\newtheorem没有创建额外的宏，而是习惯于将命令附加到环境的开始和结束。然后，标题使用问题编号，该编号会自动管理。在此版本中，第 4 页完全是空的 - 甚至没有页眉或页脚。如果您不想要这样，请删除。我还习惯于确保等中的值始终可用，并调整了标题以使用该包提供的宏。\nextproblemetoolboxproblemamsthm\thispagestyle{empty}titling\author

\documentclass[letterpaper,12pt,twoside]{article}

\usepackage[utf8]{inputenc}
\usepackage[english]{babel}
\usepackage[top = 1.5in, left = 1in, right = 1in, bottom = 1.5in, headheight=56.2pt]{geometry}% tell geometry about the head height
\usepackage{fancyhdr}
\usepackage{amsfonts,amsmath,amsthm,amssymb}
\usepackage{parskip}% already sets parindent to zero - no need to do it yourself later as well
\usepackage{etoolbox,titling}
\usepackage{kantlipsum}

\title{}
\author{Author}
\date{\today}

\newtheorem{problem}{Problem}
\newcommand{\nextproblem}[1]{%
  \cleardoublepage\thispagestyle{fancy}%
  \setcounter{equation}{0}}% if you want problem 2 on pages 5-6, better not reset the page count to zero!

\AtBeginEnvironment{problem}{%
  \cleardoublepage
  \setcounter{equation}{0}}
\AtEndEnvironment{problem}{%
  \clearpage
  \thispagestyle{empty}}

\pagestyle{fancy}
\lhead{Problem \theproblem}
\chead{}
\rhead{
  \theauthor
  \\
  Class
  \\
  Section
  \\
  \thedate
}

\begin{document}
  \begin{problem}
    \begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}
    \kant[1-8]
  \end{problem}

  \begin{problem}
    \begin{proof}\begin{align*}1+1&=2\\2&=2\end{align*}\end{proof}
    \kant[9-14]
  \end{problem}
\end{document}

可能使用更简洁的代码实现

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