circuitikz旋转变压器

Question

不使用示波器是否可以旋转变压器？代码：

\documentclass{standalone}
\usepackage[utf8]{inputenc}

\usepackage[siunitx]{circuitikz}

\begin{document}
    \begin{circuitikz}
        \draw
            (0,0) node [transformer](t1){}
            (0,-3.5) node [transformer, rotate = 30](t2){}
        ;
        \begin{scope}[shift = {(3.5,-1.75)}, rotate=30, transform shape]
            \draw
                (0,0) node [transformer](t3){}
            ;
        \end{scope}
        \draw
            (t1.B1) to [R]
            ++(right:2)
            (t2.B1) to [R]
            ++(right:2)
            (t3.B1) to [R]
            ++(right:2)
        ;
    \end{circuitikz}
\end{document}

输出：

Answer 1

抱歉。我从这里。然后我意识到“变换形状”这个词。然后我尝试将其作为直接参数，并且成功了。代码：

\documentclass{standalone}
\usepackage[utf8]{inputenc}

\usepackage[siunitx]{circuitikz}

\begin{document}
    \begin{circuitikz}
        \draw
            (0,0) node [transformer](t1){}
            (0,-3.5) node [transformer, rotate = 30](t2){}
            (3.5,-1.75) node [transformer, rotate = 30, transform shape](t3){}
        ;
        \draw
            (t1.B1) to [R]
            ++(right:2)
            (t2.B1) to [R]
            ++(right:2)
            (t3.B1) to [R]
            ++(right:2)
        ;
    \end{circuitikz}
\end{document}

输出：