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相互耦合和 Circuitikz？

tag-icon • tag-icon circuitikz
相互耦合和 Circuitikz？

我拼命想画出两个电感器之间的互耦，如下所示：

两个弯曲箭头之间的 M。

或者

弯曲箭头上方的 M。

其中实际重点是两个线圈的互耦 M。当我在网上搜索时，我浏览了这两张图片，它们是电路讲座的一部分。显然，它们是使用 Circuitikz 完成的，但我无法确定作者并直接询问他。

例如，我想在这两个线圈之间添加相互的：

\documentclass{article}

\usepackage{tikz}
\usepackage[siunitx,europeanresistors,cuteinductors,americanvoltages,americancurrents]{circuitikz}

\begin{document}

\begin{figure}[h!]
\centering
\begin{circuitikz}
  \draw (0,0)
  to[sV=$V_0$] (0,2)
  to[L=$L_1$] (2,2)
  to[short] (2,0)
  to[L=$L_2$] (0,0) ;
\end{circuitikz}
 \caption{Two coils without mutual coupling.}
\end{figure}

\end{document}

提前致谢！

答案1

这是一种可能的解决方案。amssymb 用于环路电流。

在此处输入图片描述

代码

\documentclass{article}

\usepackage{tikz}
\usepackage[siunitx,cuteinductors,americanvoltages,americancurrents]{circuitikz}
\usepackage{latexsym,amssymb,amsmath}
\begin{document}

\begin{circuitikz} 
\draw (0,0) to [R=$R_1$] (2,0) -| (3,-1) to [L,l_=$L_1$] (3,-3) |- (-1,-4) to [V,l=$v_g$] (-1,0) -- (0,0)
(1,-2) node[scale=6]{$\circlearrowright$}
(1,-2) node{$I_1$};
\draw (5,0) to [short] (7,0) -| (8,-1) to [R=$R_2$,] (8,-3) |- (4,-4) to [L,l_=$L_2$] (4,0) -- (4,0) --(5,0)
(6,-2) node[scale=6]{$\circlearrowleft$}
(6,-2) node{$I_2$};
\draw [fill=black] (2.5,-1)node(a){} circle (2pt);
\draw [fill=black] (4.5,-3)node(b){} circle (2pt);
\draw [<->,>=stealth] (a)  to [bend left] node[pos=0.5,fill=white] {M} ++(2,0);
\end{circuitikz}

\vspace{1cm}

\begin{circuitikz} 
\draw (0,0) to [R=$R_1$,i=$I_1$] (2,0) -| (3,-1) to [L,l_=$L_1$] (3,-3) |- (-1,-4)   to [V,v=$v_g$] (-1,0) -- (0,0)
(1,-2) node[scale=1.5]{$M\frac{di_2}{dt}L_1\frac{di_1}{dt}$};
\draw(1,-0.5)node{-} to [open] (1,-3.5)node(){+}; % adding polarities
\draw(2,-0.5)node{+} to [open] (2,-3.5)node(){-}; % adding polarities
\draw (5,0) to [short,i<=$I_2$] (7,0)  -| (8,-1)   to [R=$R_2$,] (8,-3) |- (4,-4)   to [L,l_=$L_2$] (4,0)  -- (4,0) --(5,0) 
(6,-2) node[scale=1.5]{$L_2\frac{di_2}{dt}M\frac{di_1}{dt}$};
\draw(5,-0.5)node{+} to [open] (5,-3.5)node(){-}; % adding polarity
\draw(6,-0.5)node{-} to [open] (6,-3.5)node(){+}; % adding polarity

\draw [fill=black] (2.5,-1)node(a){} circle (2pt);
\draw [fill=black] (4.5,-3)node(b){} circle (2pt);
\draw [<->,>=stealth] (a)  to [bend left] node[pos=0.5,fill=white] {M} ++(2,0);
\end{circuitikz}
\end{document}

答案2

杰西为您的耦合问题提供了答案，展示了如何使用tikz绘制圆形箭头，以便您拥有匹配的箭头以及控制颜色的能力：

在此处输入图片描述

参考：

代码：

\documentclass{article}

\usepackage{tikz}
\usepackage[siunitx,europeanresistors,cuteinductors,americanvoltages,americancurrents]{circuitikz}

\usepackage{calc}

%% https://tex.stackexchange.com/questions/29841/how-to-put-a-symbol-inside-a-circle-arrow/29856#29856
\makeatletter
\newlength\@SizeOfCirc%
\newcommand{\CricArrowRight}[2][]{%
    \setlength{\@SizeOfCirc}{\maxof{\widthof{#2}}{\heightof{#2}}}%
    \tikz [x=1.0ex,y=1.0ex,line width=.20ex, draw=black, fill=black, -stealth, #1]%
        \draw [anchor=center]%
            node (0,0) {#2}%
            (0,1.2\@SizeOfCirc) arc (85:-240:1.2\@SizeOfCirc);%
}%
\newcommand{\CricArrowLeft}[2][]{\CricArrowRight[xscale=-1,#1]{#2}}%
\makeatother

\begin{document}
\begin{circuitikz} 
\draw (0,0) to [R=$R_1$] (2,0) -| (3,-1) to [L,l_=$L_1$] (3,-3) |- (-1,-4) to [V,l=$v_g$] (-1,0) -- (0,0)
(1,-2) node{\CricArrowRight[draw=cyan, fill=cyan, text=red]{$I_1$}};
\draw (5,0) to [short] (7,0) -| (8,-1) to [R=$R_2$,] (8,-3) |- (4,-4) to [L,l_=$L_2$] (4,0) -- (4,0) --(5,0)
(6,-2) node{\CricArrowLeft{$I_2$}};
\draw [fill=black] (2.5,-1)node(a){} circle (2pt);
\draw [fill=black] (4.5,-3)node(b){} circle (2pt);
\draw [<->,>=stealth] (a)  to [bend left] node[pos=0.5,fill=white] {M} ++(2,0);
\end{circuitikz}
\end{document}

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