T1 libertine 和 listings 的间距问题

Question

考虑 MWE

\documentclass{article}

\usepackage[T1]{fontenc}
\usepackage{libertine}

\usepackage{listings}


\lstset{
  columns=[l]flexible,
  breaklines,
  % fontadjust,
  keepspaces,
  basicstyle={\sffamily}, % \ttfamily
}
\begin{document}

\begin{lstlisting}
bla(M) = f(Q, C)
{P}
\end{lstlisting}

\end{document}

我得到了可怕的间隔

通过注释\usepackage[T1]{fontenc}第二行是固定的（括号不同）

或者，我可以手动修复字距调整，只需滥用该literate选项即可

\begin{lstlisting}[
  literate={
    {Q}{{\kern -.25ex Q\kern .25ex}}1
    {M}{{\kern -.2ex M\kern .2ex}}1
    {C}{{\kern -.2ex C\kern .2ex}}1
    {\}}{{\kern .4ex\}}}1
    {\{}{{\{\kern -.4ex}}1
}]
bla(M) = f(Q, C)
{P}
\end{lstlisting}

获取

我怎样才能彻底修复字距调整？软件包之间的沟通错误在哪里发生？

Answer 1

对列使用另一种设置。

\documentclass{article}

\usepackage[T1]{fontenc}
\usepackage{libertine}

\usepackage{listings}


\lstset{
  columns=[l]flexible,
  breaklines,
  % fontadjust,
  keepspaces,
  basicstyle={\sffamily}, % \ttfamily
}
\begin{document}

\begin{lstlisting}
bla(M) = f(Q, C)
{P}    = f
\end{lstlisting}

\lstset{columns=fullflexible}
\begin{lstlisting}
bla(M) = f(Q, C)
{P}    = f
\end{lstlisting}


\lstset{columns=spaceflexible}
\begin{lstlisting}
bla(M) = f(Q, C)
{P}    = f
\end{lstlisting}

\lstset{columns=fixed}
\begin{lstlisting}
bla(M) = f(Q, C)
{P}    = f
\end{lstlisting}

\end{document}