如何让第三个矩阵从第二行开始?由于有些项目重叠在一起,如何调整第二个矩阵的间距?
非常感谢!
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\[
F=
\begin{bmatrix}
F_ {11} & F_ {12} & 0\\
F_ {21} & F_ {22} &0 \\
0 & 0 & F_{33}
\end{bmatrix}
=
\begin{bmatrix}
1+ \dfrac{\partial u_r}{\partial r} & \dfrac{\partial u_r}{\partial z}& 0\\
\dfrac{\partial u_z}{\partial r} & 1+\dfrac{\partial u_z}{\partial z} &0 \\
0 & 0 & 1+ \dfrac{\partial u_r}{\partial r}
\end{bmatrix}
=
\begin{bmatrix}
1+ \dfrac{\partial u_1}{\partial 1} & \dfrac{\partial u_1}{\partial 2}& 0\\
\dfrac{\partial u_2}{\partial 1} & 1+\dfrac{\partial u_2}{\partial 2} &0 \\
0 & 0 & 1+ \dfrac{\partial u_1}{\partial 1}
\end{bmatrix}
\]
\end{document}
答案1
用环境来align*
代替\[
...。\]
可以增加间距,\\
用\\[<space>]
如以下 MWE 中的替换。
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{align*}
F&=
\begin{bmatrix}
F_ {11} & F_ {12} & 0\\[1ex]
F_ {21} & F_ {22} &0 \\[1ex]
0 & 0 & F_{33}
\end{bmatrix}
=
\begin{bmatrix}
1+ \dfrac{\partial u_r}{\partial r} & \dfrac{\partial u_r}{\partial z}& 0\\[2ex]
\dfrac{\partial u_z}{\partial r} & 1+\dfrac{\partial u_z}{\partial z} &0 \\[2ex]
0 & 0 & 1+ \dfrac{\partial u_r}{\partial r}
\end{bmatrix}\\[2ex]
& =
\begin{bmatrix}
1+ \dfrac{\partial u_1}{\partial 1} & \dfrac{\partial u_1}{\partial 2}& 0\\[2ex]
\dfrac{\partial u_2}{\partial 1} & 1+\dfrac{\partial u_2}{\partial 2} &0 \\[2ex]
0 & 0 & 1+ \dfrac{\partial u_1}{\partial 1}
\end{bmatrix}
\end{align*}
\end{document}
如果您需要编号方程,最好在环境split
内部使用equation
。
平均能量损失
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
\begin{split}
F&=
\begin{bmatrix}
F_ {11} & F_ {12} & 0\\[1ex]
F_ {21} & F_ {22} &0 \\[1ex]
0 & 0 & F_{33}
\end{bmatrix}
=
\begin{bmatrix}
1+ \dfrac{\partial u_r}{\partial r} & \dfrac{\partial u_r}{\partial z}& 0\\[2ex]
\dfrac{\partial u_z}{\partial r} & 1+\dfrac{\partial u_z}{\partial z} &0 \\[2ex]
0 & 0 & 1+ \dfrac{\partial u_r}{\partial r}
\end{bmatrix}\\[2ex]
& =
\begin{bmatrix}
1+ \dfrac{\partial u_1}{\partial 1} & \dfrac{\partial u_1}{\partial 2}& 0\\[2ex]
\dfrac{\partial u_2}{\partial 1} & 1+\dfrac{\partial u_2}{\partial 2} &0 \\[2ex]
0 & 0 & 1+ \dfrac{\partial u_1}{\partial 1}
\end{bmatrix}
\end{split}
\end{equation}
\end{document}