如何在 tikz 中创建围绕节点的非矩形边框？

Question

我有以下 MWE。

我想画一条边框没有包括 $y_3$（或 .tex 文件中的 s3）——因此它将是一个矩形，其左上角被改变，以便绕过 s3。有没有办法创建这样的边框，基本上是一个矩形多边形，围绕一组节点？

（编辑：我尝试使用 tikz 文件中的最后一个命令来执行此操作。）

\documentclass{article}

\usepackage{tikz}

\usetikzlibrary{fit,chains}

\begin{document}

\begin{tikzpicture}[node distance=2cm]

  \node(s1) {$y_1$};
  \node(s2) [right of = s1] {$y_2$};
  \node(s3) [right of = s2]{$y_{3}$};
  \node(s4) [right of = s3]{$y_4$};
  \node(s5) [right of = s4]{$y_5$};

\draw [->] (s1) -- (s2) ;
\draw [->] (s2) -- (s3) ;
\draw [->] (s3) -- (s4) ;
\draw [->] (s4) -- (s5) ;


  \node(x1) [below of = s1]{$x_1$};
  \node(x2) [right of = x1] {$X_2$};
  \node(x3) [right of = x2] {$X_3$};
  \node(x4) [right of = x3] {$X_4$};
  \node(x5) [right of = x4] {$X_5$};

\draw [->] (s1) -- (x1) ;
\draw [->] (s2) -- (x2) ;
\draw [->] (s3) -- (x3) ;
\draw [->] (s4) -- (x4) ;
\draw [->] (s5) -- (x5) ;

\node[rectangle,draw=red, fit=(x3) (x4) (x5) (s4) (s5),inner sep=3mm,line width=1mm](rect2) {};

\end{tikzpicture}
\end{document}

Answer 1

如果node您接受非自动绘制的线...

\documnentclass{article}

\usepackage{tikz}

\usetikzlibrary{fit,chains, calc}

\begin{document}

\begin{tikzpicture}[node distance=2cm]

  \node(s1) {$y_1$};
  \node(s2) [right of = s1] {$y_2$};
  \node(s3) [right of = s2]{$y_{3}$};
  \node(s4) [right of = s3]{$y_4$};
  \node(s5) [right of = s4]{$y_5$};

\draw [->] (s1) -- (s2) ;
\draw [->] (s2) -- (s3) ;
\draw [->] (s3) -- (s4) ;
\draw [->] (s4) -- (s5) ;


  \node(x1) [below of = s1]{$x_1$};
  \node(x2) [right of = x1] {$X_2$};
  \node(x3) [right of = x2] {$X_3$};
  \node(x4) [right of = x3] {$X_4$};
  \node(x5) [right of = x4] {$X_5$};

\draw [->] (s1) -- (x1) ;
\draw [->] (s2) -- (x2) ;
\draw [->] (s3) -- (x3) ;
\draw [->] (s4) -- (x4) ;
\draw [->] (s5) -- (x5) ;

\node[rectangle,draw=red, fit=(x3) (x4) (x5) (s4) (s5),inner sep=3mm,line width=1mm](rect2) {};

\draw[blue, line width=1mm] (x3.south west)-|(s5.north east) --($(s3.north)!0.5!(s4.north)$)|-($(s3.west)!0.5!(x3.west)$)--cycle;
\end{tikzpicture}
\end{document}