我想知道 中是否有一种多路开关的符号circuitikz
。也就是说,像“spdt”(单刀双掷)这样的开关,但具有更多的切换位置。对于以下电路,我需要九个位置之类的东西。
答案1
这是一个可能的解决方案,对于重复节点生成和线路连接,foreach
使用多个命令。dot
为旋转开关定义了一个使用两个参数调用的样式,以便添加内部标签以方便接线。#1 = 位置,#2 = 标签。
代码
\documentclass[tikz,border=10pt]{standalone}
\usetikzlibrary{shapes,positioning,decorations.markings}
\usepackage{circuitikz}
\begin{document}
\tikzset{dot/.style args={#1#2}{decoration={
markings, mark=at position #1 with
{\draw[thin,black,fill=white] circle (1pt)coordinate(#2){};}}
,preaction={decorate}
}}
\begin{circuitikz}
% black dots on the left
\path [postaction={decorate,decoration={markings,
mark=between positions 0 and 1 step 0.125 with
{\draw[thin,black,fill=black] circle (1pt);}}}] (0,1) -- (0,-1);
% rotary switch on the right
\foreach \p/\l in{0/1,0.125/2,0.25/3,0.375/4,0.5/5,
0.625/6,0.750/7,0.875/8,0.99/9}{
\path [dot={\p}{a\l}] (1,0.5) to [out=180, in=180,looseness=1.5] (1,-0.5);
}
% pointer
\draw[->,red] (1,0) -- (0.65,0.15);
\draw (1,0) to[short,*-o] (1.5,0)node(a){};
\draw(-0.5,1)node[below]{\tiny +}to[short,o-] (0,1);
% wires
\foreach \x\y in {1/1,0.75/2,0.5/3,0.25/4,0/5,
-0.25/6,-0.5/7,-0.75/8,-1/9} {
\draw[] (0,\x) --++(0.5,0) -- (a\y);
}
\draw(-0.5,-1)node[below]{\tiny $-$} to[short,o-] (0,-1);
\draw (0,1)--(0,-1);
\foreach \y in {0.875,0.625,0.375,0.125,-0.125,-0.375,-0.625,-0.875}{
\draw[gray] (-2pt,\y)--(2pt,\y);
}
% neutral wire
\draw (0,0) --(-0.8,0) --(-0.8,-1.5) to[short,-o](1.5,-1.5)node(b){};
\draw[->] (a) --node[right](){\tiny Vac} (b);
% To remove the overwriting lines
\foreach \p/\l in{0/1,0.125/2,0.25/3,0.375/4,0.5/5,
0.625/6,0.750/7,0.875/8,0.99/9}{
\path [dot={\p}{a\l}] (1,0.5) to [out=180, in=180,looseness=1.5] (1,-0.5);
}
\end{circuitikz}
\end{document}