我有下表：
\documentclass{report}
\usepackage[intlimits]{amsmath}
\usepackage{floatflt}
\usepackage{caption}
\usepackage{listliketab}
\usepackage{tabularx}
\usepackage{booktabs}
\usepackage{siunitx}
\begin{document}
\begin{table}[htmb]
\caption{Koeffizienten und Exponenten der Gl. \ref{eq:BG_T_ps}} \label{tab_koeff_T_ps}
\begin{tabular}{ccclcccl}
\toprule
$i$ & $I_i$ & $J_i$ & \multicolumn{1}{c}{$n_i$} & $i$ & $I_i$ & $J_i$ & \multicolumn{1}{c}{$n_i$}\\ \midrule
\num{1} & \num{0} & \num{0} & \num{0.1747826805830} $\times 10^3$ & \num{11} & \num{1} & \num{12} & \num{0.3567211060736} $\times 10^{-9}$ \\
\num{2} & \num{0} & \num{1} & \num{0.3480693089287} $\times 10^2$ & \num{12} & \num{1} & \num{31} & \num{0.1733249699489} $\times 10^{-23}$ \\
\num{3} & \num{0} & \num{2} & \num{0.6529258497845} $\times 10$ & \num{13} & \num{2} & \num{0} & \num{0.5660890065483} $\times 10^{-3}$ \\
\num{4} & \num{0} & \num{3} & \num{0.33039981775489} & \num{14} & \num{2} & \num{1} & \num{-0.3263548313971} $\times 10^{-3}$ \\
\num{5} & \num{0} & \num{11} & \num{-0.1928138292319} $\times 10^{-6}$ & \num{15} & \num{2} & \num{2} & \num{0.4477828669063} $\times 10^{-4}$ \\
\num{6} & \num{0} & \num{31} & \num{-0.2490919724457} $\times 10^{-22}$ & \num{16} & \num{2} & \num{9} & \num{-0.5132215690850} $\times 10^{-9}$ \\
\num{7} & \num{1} & \num{0} & \num{-0.26107636489332} & \num{17} & \num{2} & \num{31} & \num{-0.4252265704220} $\times 10^{-25}$ \\
\num{8} & \num{1} & \num{1} & \num{0.22592965981586} & \num{18} & \num{3} & \num{10} & \num{0.2640044136068} $\times 10^{-12}$ \\
\num{9} & \num{1} & \num{2} & \num{-0.6425646339522} $\times 10^{-1}$ & \num{19} & \num{3} & \num{32} & \num{0.7812460045972} $\times 10^{-28}$ \\
\num{10} & \num{1} & \num{3} & \num{0.7887628927052} $\times 10^{-2}$ & \num{20} & \num{4} & \num{32} & \num{-0.3073219990366} $\times 10^{-30}$ \\
\bottomrule
\end{tabular}
\end{table}
\end{document}
我怎样才能做到这一点：
- 列 n_i 中的第一个零彼此对齐
- 列 n_i 中的所有
\times(X) 都彼此对齐 - 尾部零不会被省略
\num{}
同时？我怀疑使用 align 的 & 符号是可能的&，但是表格可能会变得很大，而且我不知道如何最有效地做到这一点。
答案1
该软件包siunitx通过列说明符支持带有数字的列S：
\documentclass{report}
\usepackage{caption}
\usepackage{booktabs}
\usepackage{siunitx}
\begin{document}
\begin{table}
\centering
\caption{Koeffizienten und Exponenten}
\label{tab_koeff_T_ps}
\begin{tabular}{
S[table-format=2.0]
S[table-format=1.0]
S[table-format=2.0]
S[table-format=1.13,
table-figures-exponent=2,
table-sign-mantissa,
table-sign-exponent]
S[table-format=2.0]
S[table-format=1.0]
S[table-format=2.0]
S[table-format=1.13,
table-figures-exponent=2,
table-sign-mantissa,
table-sign-exponent]}
\toprule
\multicolumn{1}{c}{$i$}
& \multicolumn{1}{c}{$I_i$}
& \multicolumn{1}{c}{$J_i$}
& \multicolumn{1}{c}{$n_i$}
& \multicolumn{1}{c}{$i$}
& \multicolumn{1}{c}{$I_i$}
& \multicolumn{1}{c}{$J_i$}
& \multicolumn{1}{c}{$n_i$}\\
\midrule
1 & 0 & 0 & 0.1747826805830e3 & 11 & 1 & 12 & 0.3567211060736e-9 \\
2 & 0 & 1 & 0.3480693089287e2 & 12 & 1 & 31 & 0.1733249699489e-23 \\
3 & 0 & 2 & 0.6529258497845e10 & 13 & 2 & 0 & 0.5660890065483e-3 \\
4 & 0 & 3 & 0.33039981775489 & 14 & 2 & 1 & -0.3263548313971e-3 \\
5 & 0 & 11 & -0.1928138292319e-6 & 15 & 2 & 2 & 0.4477828669063e-4 \\
6 & 0 & 31 & -0.2490919724457e-22 & 16 & 2 & 9 & -0.5132215690850e-9 \\
7 & 1 & 0 & -0.26107636489332 & 17 & 2 & 31 & -0.4252265704220e-25 \\
8 & 1 & 1 & 0.22592965981586 & 18 & 3 & 10 & 0.2640044136068e-12 \\
9 & 1 & 2 & -0.6425646339522e-1 & 19 & 3 & 32 & 0.7812460045972e-28 \\
10 & 1 & 3 & 0.7887628927052e-2 & 20 & 4 & 32 & -0.3073219990366e-30 \\
\bottomrule
\end{tabular}
\end{table}
\end{document}
