枚举和多列中的 \vfill 问题

Question

我正在尝试使用多列和枚举制作一个大型练习列表，事情是，当我仅使用枚举和 vfill 时，vfill 可以正常工作，但是当我使用多列时，vfill 不会添加它应该添加的空间。

\begin{multicols}{2}
\begin{enumerate}
\begin{large}
\item  $\dfrac{2}{8}=\dfrac{1}{4} $ \vfill
\item  $\dfrac{2}{6}=\dfrac{1}{3} $ \vfill
\item  $\dfrac{4}{6}=\dfrac{2}{3} $ \vfill
\item  $\dfrac{2}{8}=\dfrac{1}{4} $ \vfill
\item  $\dfrac{6}{8}=\dfrac{3}{4} $ \vfill
\item  $\dfrac{2}{10}=\dfrac{1}{5} $ \vfill
\item  $\dfrac{4}{10}=\dfrac{2}{5} $ \vfill
\item  $\dfrac{4}{14}=\dfrac{2}{7} $ \vfill
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ \vfill
\item  $\dfrac{8}{22}=\dfrac{4}{11} $ \vfill
\item  $\dfrac{6}{26}=\dfrac{3}{13} $ \vfill
\item  $\dfrac{12}{14}=\dfrac{6}{7} $ \vfill
\item  $\dfrac{8}{10}=\dfrac{4}{5} $ \vfill
\item  $\dfrac{8}{14}=\dfrac{4}{7} $ \vfill
\item  $\dfrac{16}{18}=\dfrac{8}{9} $ \vfill
\columnbreak 
\item  $\dfrac{14}{16}=\dfrac{7}{8} $ \vfill
\item  $\dfrac{20}{22}=\dfrac{10}{11} $ \vfill
\item  $\dfrac{22}{24}=\dfrac{11}{12} $ \vfill
\item  $\dfrac{2}{12}=\dfrac{1}{6} $ \vfill
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ \vfill
\item  $\dfrac{2}{16}=\dfrac{1}{8} $ \vfill
\item  $\dfrac{10}{22}=\dfrac{5}{11} $ \vfill
\item  $\dfrac{14}{32}=\dfrac{7}{16} $ \vfill
\item  $\dfrac{10}{14}=\dfrac{5}{7} $ \vfill
\item  $\dfrac{6}{10}=\dfrac{3}{5} $ \vfill
\item  $\dfrac{16}{22}=\dfrac{8}{11} $ \vfill
\item  $\dfrac{22}{26}=\dfrac{11}{13} $ \vfill
\item  $\dfrac{2}{20}=\dfrac{1}{10} $ \vfill
\item  $\dfrac{14}{24}=\dfrac{7}{12} $ \vfill
\item  $\dfrac{26}{28}=\dfrac{13}{14} $ \vfill
\end{large}
\end{enumerate} 
\end{multicols}

输出如下

我该如何解决这个问题，我认为 columnbreak 做了一些不允许\vfill正常工作的事情

Answer 1

请始终发布完整的文档。项目间分隔是列表的一个参数：

\documentclass{article}
\usepackage{enumitem,multicol,amsmath}
\begin{document}
\begin{multicols}{2}\large
\begin{enumerate}[itemsep=9pt]

\item  $\dfrac{2}{8}=\dfrac{1}{4} $ 
\item  $\dfrac{2}{6}=\dfrac{1}{3} $ 
\item  $\dfrac{4}{6}=\dfrac{2}{3} $ 
\item  $\dfrac{2}{8}=\dfrac{1}{4} $ 
\item  $\dfrac{6}{8}=\dfrac{3}{4} $ 
\item  $\dfrac{2}{10}=\dfrac{1}{5} $ 
\item  $\dfrac{4}{10}=\dfrac{2}{5} $ 
\item  $\dfrac{4}{14}=\dfrac{2}{7} $ 
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ 
\item  $\dfrac{8}{22}=\dfrac{4}{11} $ 
\item  $\dfrac{6}{26}=\dfrac{3}{13} $ 
\item  $\dfrac{12}{14}=\dfrac{6}{7} $ 
\item  $\dfrac{8}{10}=\dfrac{4}{5} $ 
\item  $\dfrac{8}{14}=\dfrac{4}{7} $ 
\item  $\dfrac{16}{18}=\dfrac{8}{9} $ 

\item  $\dfrac{14}{16}=\dfrac{7}{8} $ 
\item  $\dfrac{20}{22}=\dfrac{10}{11} $ 
\item  $\dfrac{22}{24}=\dfrac{11}{12} $ 
\item  $\dfrac{2}{12}=\dfrac{1}{6} $ 
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ 
\item  $\dfrac{2}{16}=\dfrac{1}{8} $ 
\item  $\dfrac{10}{22}=\dfrac{5}{11} $ 
\item  $\dfrac{14}{32}=\dfrac{7}{16} $ 
\item  $\dfrac{10}{14}=\dfrac{5}{7} $ 
\item  $\dfrac{6}{10}=\dfrac{3}{5} $ 
\item  $\dfrac{16}{22}=\dfrac{8}{11} $ 
\item  $\dfrac{22}{26}=\dfrac{11}{13} $ 
\item  $\dfrac{2}{20}=\dfrac{1}{10} $ 
\item  $\dfrac{14}{24}=\dfrac{7}{12} $ 
\item  $\dfrac{26}{28}=\dfrac{13}{14} $ 

\end{enumerate} 
\end{multicols}

\end{document}

或者自动填充，但不自动平衡

\documentclass[twocolumn]{article}
\usepackage{enumitem,amsmath}
\begin{document}

\begin{enumerate}[itemsep=\fill]

\item  $\dfrac{2}{8}=\dfrac{1}{4} $ 
\item  $\dfrac{2}{6}=\dfrac{1}{3} $ 
\item  $\dfrac{4}{6}=\dfrac{2}{3} $ 
\item  $\dfrac{2}{8}=\dfrac{1}{4} $ 
\item  $\dfrac{6}{8}=\dfrac{3}{4} $ 
\item  $\dfrac{2}{10}=\dfrac{1}{5} $ 
\item  $\dfrac{4}{10}=\dfrac{2}{5} $ 
\item  $\dfrac{4}{14}=\dfrac{2}{7} $ 
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ 
\item  $\dfrac{8}{22}=\dfrac{4}{11} $ 
\item  $\dfrac{6}{26}=\dfrac{3}{13} $ 
\item  $\dfrac{12}{14}=\dfrac{6}{7} $ 
\item  $\dfrac{8}{10}=\dfrac{4}{5} $ 
\item  $\dfrac{8}{14}=\dfrac{4}{7} $ 
\item  $\dfrac{16}{18}=\dfrac{8}{9} $ 

\newpage

\item  $\dfrac{14}{16}=\dfrac{7}{8} $ 
\item  $\dfrac{20}{22}=\dfrac{10}{11} $ 
\item  $\dfrac{22}{24}=\dfrac{11}{12} $ 
\item  $\dfrac{2}{12}=\dfrac{1}{6} $ 
\item  $\dfrac{2}{14}=\dfrac{1}{7} $ 
\item  $\dfrac{2}{16}=\dfrac{1}{8} $ 
\item  $\dfrac{10}{22}=\dfrac{5}{11} $ 
\item  $\dfrac{14}{32}=\dfrac{7}{16} $ 
\item  $\dfrac{10}{14}=\dfrac{5}{7} $ 
\item  $\dfrac{6}{10}=\dfrac{3}{5} $ 
\item  $\dfrac{16}{22}=\dfrac{8}{11} $ 
\item  $\dfrac{22}{26}=\dfrac{11}{13} $ 
\item  $\dfrac{2}{20}=\dfrac{1}{10} $ 
\item  $\dfrac{14}{24}=\dfrac{7}{12} $ 
\item  $\dfrac{26}{28}=\dfrac{13}{14} $ 

\end{enumerate} 


\end{document}