尽管存在差异，但可对齐 itemize 中的项目

Question

在这种情况下，我该如何对齐这两个项目：

    \documentclass{article}
    \usepackage{amsthm}
    \newtheorem{theorem}{Theorem}
    \begin{document}
    \begin{theorem} 
    here is my theorem.
        \begin{itemize} 
            \item[(a)-(f)] Same as Conditions (a)-(f) of Lamma 1.
            \item[(g)]  a new Condition.
         \end{itemize}
    \end{theorem} 
     \end{document}

在当前情况下，第一项中的 (a) 与第二项中的 (g) 不对齐。我还希望这些项出现在定理内部，而不是与定理具有相同的缩进。

Answer 1

如果只是针对特殊情况，请尝试以下操作：

\documentclass{article}

\begin{document}
 \begin{itemize} 
    \item[(a)-(f)] Same as Conditions (a)-(f) of Lamma 1.
    \item[(g)\phantom{-(f)}]  a new Condition.
    \end{itemize}
\end{document}

或这个：

\documentclass{article}

\begin{document}
 \begin{itemize} 
    \item[\hbox to 1cm{(a)-(f)}] Same as Conditions (a)-(f) of Lamma 1.
    \item[\hbox to 1cm{(g)}]  a new Condition.
    \end{itemize}
\end{document}

针对已编辑的问题尝试此操作：

\documentclass{article}
\usepackage{amsthm,enumitem}%%added enumitem
\newtheorem{theorem}{Theorem}

\begin{document}
\begin{theorem} 
here is my theorem.
    \begin{itemize}[leftmargin=.5in]
        \item[\hbox to 1cm{(a)-(f)}] Same as Conditions (a)-(f) of Lamma 1.
        \item[\hbox to 1cm{(g)}]  a new Condition.
     \end{itemize}
\end{theorem} 
 \end{document}