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更新：自动着色

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更新：自动着色

我正在尝试用 Ti 重新创建以下图像钾Z：

通缉

（请忽略黑色部分，我把它弄乱了。有些是正确的，有些则不正确。我正在寻找适用于任何情况的通用答案。）

我已经成功制作了同心圆、射线和标签。我只希望得到颜色方面的内容。

\begin{center}
  \begin{tikzpicture}
    %Circles 
    \foreach \r in {1, 3, 5}
      \draw[Black, thick] (0,0) circle (\r);    
    %Rays
    \foreach \a in {0, 45,...,359}
      \draw[thick,Black] (0, 0) -- (\a:5);
    %Angle labels  
    \draw (0: 5.5) node {$110$};
    \draw (45: 5.5) node {$010$};
    \draw (90: 5.5) node {$000$};
    \draw (135: 5.5) node {$001$};
    \draw (180: 5.5) node {$011$};
    \draw (225: 5.5) node {$111$};
    \draw (270: 5.5) node {$101$};
    \draw (315: 5.5) node {$100$};
    %Central point
    \draw[fill=black] (0,0) circle(0.7mm);
  \end{tikzpicture}
\end{center}

输出

答案1

更新：自动着色

“手工”获得正确的颜色很困难，因此我重新编写了示例，以根据它们所代表的二进制代码自动为适当的扇区着色。代码现在短多了：

\documentclass{article}
\usepackage{tikz}
\usepackage{xstring}
\def\sector#1#2#3#4#5{%
\fill[#5] (#1) -- (#3:#2) arc (#3:#4:#2) -- cycle;
}

% Define colors for bits 1 and 0
\colorlet{color1}{red!70!black!70}
\colorlet{color0}{white}

\begin{document}
\begin{tikzpicture}
    \foreach \code [count=\i from=1] in {110,010,000,001,011,111,101,100} {
      \node at (\i*45:5.5) {\code}; % Label each code
      % Draw sectors from outside to inside
      \foreach \r in  {5,3,1} {
         \StrRight{\code}{1}[\bit]         % Get the rightmost bit
         \StrGobbleRight{\code}{1}[\code]  % Get the remaining left bits
         \xdef\code{\code}  % Set them for the next iteration
         \sector{0,0}{\r}{45*\i}{45*\i-45}{color\bit, draw=black, thick}
       }
    }
\end{tikzpicture}
\end{document}

并且结果没有出现以前的错误:-)

结果

仅供参考，以下是

以前的答案已过时

这是一个快速而粗略的解决方案。以下宏允许您填充圆形扇区：

\def\sector#1#2#3#4#5{%
% #1  center
% #2  radius
% #3  start angle
% #4  end angle
% #5  drawing options
\draw[#5] (#1) -- (#3:#2) arc (#3:#4:#2) -- cycle;
}

现在，你可以用红色绘制一些圆形扇区，从外环开始，一直到内环，并与一些其他白色扇区重叠。这不是最有效或最优雅的方法，但它很容易理解和编写代码：

\documentclass{article}
\usepackage{tikz}
\def\sector#1#2#3#4#5{%
% #1  center
% #2  radius
% #3  start angle
% #4  end angle
% #5  drawing options
\draw[#5] (#1) -- (#3:#2) arc (#3:#4:#2) -- cycle;
}

\colorlet{myred}{red!70!black!70}

\begin{document}

\begin{tikzpicture}
    % Colour sectors
    % External ring
    \foreach \s/\c in {2/myred,4/myred,5/myred} {
      \sector{0,0}{5}{\s*45}{\s*45+45}{fill=\c}
    }
    % Middle ring
    \foreach \s/\c in {0/myred,2/white,3/myred,5/white,7/myred} {
      \sector{0,0}{3}{\s*45}{\s*45+45}{fill=\c}
    }
    % Inner ring
    \foreach \s/\c in {0/white,4/myred,5/myred,6/myred} {
      \sector{0,0}{1}{\s*45}{\s*45+45}{fill=\c}
    }

    %Circles 
    \foreach \r in {1, 3, 5}
      \draw[black, thick] (0,0) circle (\r);    
    %Rays
    \foreach \a in {0, 45,...,359}
      \draw[thick,black] (0, 0) -- (\a:5);
    %Angle labels  
    \draw (0: 5.5) node {$110$};
    \draw (45: 5.5) node {$010$};
    \draw (90: 5.5) node {$000$};
    \draw (135: 5.5) node {$001$};
    \draw (180: 5.5) node {$011$};
    \draw (225: 5.5) node {$111$};
    \draw (270: 5.5) node {$101$};
    \draw (315: 5.5) node {$100$};
    %Central point
    \draw[fill=black] (0,0) circle(0.7mm);
\end{tikzpicture}

\end{document}

结果

答案2

您需要arc(版本 3.0.0)tikz手册第 153 页中描述的操作。为了好玩，这里有一个简单的命令，它用给定的颜色在两个给定角度和半径之间的区域上色：

\documentclass{article}

\newcommand{\coloursector}[5]{%
  \fill[#5] (#1:#3) arc[start angle=#1, end angle=#2, radius=#3] -- (#2:#4) arc[start angle=#2, end angle=#1, radius=#4] -- cycle;
}

\usepackage{tikz}

\begin{document}
\begin{center}
  \begin{tikzpicture}
    \coloursector{135}{180}{1}{3}{red!50!white}

    %Circles 
    \foreach \r in {1, 3, 5}
      \draw[black, thick] (0,0) circle (\r);    
    %Rays
    \foreach \a in {0, 45,...,359}
      \draw[thick,black] (0, 0) -- (\a:5);
    %Angle labels  
    \draw (0: 5.5) node {$110$};
    \draw (45: 5.5) node {$010$};
    \draw (90: 5.5) node {$000$};
    \draw (135: 5.5) node {$001$};
    \draw (180: 5.5) node {$011$};
    \draw (225: 5.5) node {$111$};
    \draw (270: 5.5) node {$101$};
    \draw (315: 5.5) node {$100$};

    %Central point
    \draw[fill=black] (0,0) circle(0.7mm);
  \end{tikzpicture}
\end{center}
\end{document}

角度 135 和 180 以及半径 1 和 3 之间的位为浅红色

答案3

PSTricks 解决方案使用以下宏语法：

\Ring[<segment color>]
     {<piece number in ring, counted anticlockwise>}
     {<ring number, counted from the centre>}

\Label[<label segment, counted anticlockwise>]{<label>}

现在来看看代码：

\documentclass{article}

% packages
\usepackage{pstricks-add}
\usepackage{xfp}

% macros
\def\Ring[#1]#2#3{%
  \psRing[
    fillstyle = solid,
    fillcolor = #1
  ](0,0)[\fpeval{(#2-1)*360/\Segments},\fpeval{#2*360/\Segments}]{\fpeval{#3-1}}{#3}%
}
\def\Label[#1]#2{%
  \uput[\fpeval{(#1-1)*360/\Segments}]%
       (\fpeval{\Radius*cos((#1-1)*2*pi/\Segments)},\fpeval{\Radius*sin((#1-1)*2*pi/\Segments)}){#2}%
}

% constants
\def\Segments{8}
\def\Radius{3}

\begin{document}

% drawing
\begin{pspicture}(-\Radius.7,-\Radius.45)(\Radius.7,\Radius.45)
  % 1st (innermost) ring
  \Ring[white]{1}{1}
  \Ring[white]{2}{1}
  \Ring[red]{3}{1}
  \Ring[brown!50!black]{4}{1}
  \Ring[red]{5}{1}
  \Ring[red]{6}{1}
  \Ring[red]{7}{1}
  \Ring[brown!50!black]{\Segments}{1}
  % 2nd ring
  \Ring[red]{1}{2}
  \Ring[white]{2}{2}
  \Ring[white]{3}{2}
  \Ring[red]{4}{2}
  \Ring[red]{5}{2}
  \Ring[white]{6}{2}
  \Ring[white]{7}{2}
  \Ring[red]{\Segments}{2}
  % 3rd ring
  \Ring[white]{1}{\Radius}
  \Ring[white]{2}{\Radius}
  \Ring[white]{3}{\Radius}
  \Ring[brown!50!black]{4}{\Radius}
  \Ring[red]{5}{\Radius}
  \Ring[red]{6}{\Radius}
  \Ring[white]{7}{\Radius}
  \Ring[white]{\Segments}{\Radius}
  % labels
  \Label[1]{$110$}
  \Label[2]{$010$}
  \Label[3]{$000$}
  \Label[4]{$001$}
  \Label[5]{$011$}
  \Label[6]{$111$}
  \Label[7]{$101$}
  \Label[\Segments]{$100$}
\end{pspicture}

\end{document}

输出

答案4

您可以通过画一条粗（2厘米）的线来“填充”；）

\documentclass[tikz,border=7mm]{standalone}
\begin{document}
  \begin{tikzpicture}
    % "fill" with 2cm thick red line
    \foreach \s/\e/\r in {3/6/5,3/5/3,2/8/1,-1/1/3}
      \draw[red,line width=2cm] (45*\s:\r) arc(45*\s:45*\e:\r);

    % Circles
    \draw[thick] (0,0) foreach \r in {2,4,6}{circle (\r)};

    % Rays
    \foreach[count=\i] \a in {110,010,000,001,011,111,101,100}
      \draw[thick] (0, 0) -- (45*\i:6) node[pos=1.1]{$\a$};

    % Central point
    \node[scale=3]{.};
  \end{tikzpicture}
\end{document}

在此处输入图片描述

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