我有一个混淆矩阵，其中第一列（或本例中为第二列）具有与第一行（或本例中为第二行）相同的标签。我的问题是这些标签是数学标签，我只能提供自定义列标签，而不能提供行标签。
请参阅 MWE，我想在其中修改列的行条目，Name使其具有与列标题相同的标签。我知道只有 5 行，标签可以固定，这样事情就简单多了$A_1$。$A_5$但是，我该如何修改行条目呢？
平均能量损失
\documentclass{memoir}
\usepackage{pgfplotstable}
\usepackage{siunitx}
\usepackage{longtable}
\usepackage{multirow}
\newcommand*\rot{\rotatebox{90}}
\pgfplotsset{
compat=1.13
}
\pgfplotstableset{%
every head row/.style={before row=\toprule, after row=\midrule},
every last row/.style={after row=\bottomrule}
}
\begin{document}
\pgfplotstabletypeset[
every head row/.style={
before row={%
\toprule
& & \multicolumn{5}{c}{\textbf{Head 2}} \\
\cmidrule(lr){3-7}
},
after row/.add={}{%
\midrule
\multirow{5}{*}{\rot{\parbox{2cm}{\centering \textbf{Head 1}}}}
}
},
col sep=semicolon,
string replace={---}{\textemdash},
use comma,
header=true,
multicolumn names={c},
columns/Empty/.style={column name=,column type=l,string type},
columns/Name/.style={column name=,column type=l,string type},
columns/A1/.style={column name={$A_1$},string type,column type={S}},
columns/A2/.style={column name={$A_2$},string type,column type={S}},
columns/A3/.style={column name={$A_3$},string type,column type={S}},
columns/A4/.style={column name={$A_4$},string type,column type={S}},
columns/A5/.style={column name={$A_5$},string type,column type={S}}
]{
Empty;Name;A1;A2;A3;A4;A5
;A1;1;1;1;1;1
;A2;1;1;1;1;1
;A3;1;1;1;1;1
;A4;1;1;1;1;1
;A5;1;1;1;1;1
}%
\end{document}
编辑：
我找到了一个可能的解决方案，可以得到所需的输出。但是，我仍然好奇这是否是正确的方法，或者是否可以做得更优雅。
MWE解决方案：
\documentclass{memoir}
\usepackage{pgfplotstable}
\usepackage{siunitx}
\usepackage{longtable}
\usepackage{multirow}
\newcommand*\rot{\rotatebox{90}}
\pgfplotsset{
compat=1.13
}
\pgfplotstableset{%
every head row/.style={before row=\toprule, after row=\midrule},
every last row/.style={after row=\bottomrule}
}
\begin{document}
\pgfplotstabletypeset[
every head row/.style={
before row={%
\toprule
& & \multicolumn{5}{c}{\textbf{Head 2}} \\
\cmidrule(lr){3-7}
},
after row/.add={}{%
\midrule
\multirow{5}{*}{\rot{\parbox{2cm}{\centering \textbf{Head 1}}}}
}
},
col sep=semicolon,
string replace={---}{\textemdash},
use comma,
header=true,
multicolumn names={c},
columns/Empty/.style={column name=,column type=l,string type},
columns/Name/.style={column name=,column type=l,string type,
assign cell content/.code={%
\ifnum\pgfplotstablerow=0
\pgfkeyssetvalue{/pgfplots/table/@cell content}{$A_1$}%
\fi
\ifnum\pgfplotstablerow=1
\pgfkeyssetvalue{/pgfplots/table/@cell content}{$A_2$}%
\fi
\ifnum\pgfplotstablerow=2
\pgfkeyssetvalue{/pgfplots/table/@cell content}{$A_3$}%
\fi
\ifnum\pgfplotstablerow=3
\pgfkeyssetvalue{/pgfplots/table/@cell content}{$A_4$}%
\fi
\ifnum\pgfplotstablerow=4
\pgfkeyssetvalue{/pgfplots/table/@cell content}{$A_5$}%
\fi
},
},
columns/A1/.style={column name={$A_1$},string type,column type={S}},
columns/A2/.style={column name={$A_2$},string type,column type={S}},
columns/A3/.style={column name={$A_3$},string type,column type={S}},
columns/A4/.style={column name={$A_4$},string type,column type={S}},
columns/A5/.style={column name={$A_5$},string type,column type={S}}
]{
Empty;Name;A1;A2;A3;A4;A5
;A1;1;1;1;1;1
;A2;1;1;1;1;1
;A3;1;1;1;1;1
;A4;1;1;1;1;1
;A5;1;1;1;1;1
}%
\end{document}
答案1
这是使用 的一种可能性collcell；假设标题的形式为<letter><digits>，包含一个字母。
\documentclass{memoir}
\usepackage{pgfplotstable}
\usepackage{siunitx}
\usepackage{longtable}
\usepackage{multirow}
\usepackage{collcell}
\pgfplotsset{compat=1.13}
\pgfplotstableset{%
every head row/.style={before row=\toprule, after row=\midrule},
every last row/.style={after row=\bottomrule}
}
\newcommand*\rot{\rotatebox{90}}
\newcommand{\rowhead}[1]{\dorowhead#1\relax}
\def\dorowhead#1#2\relax{$#1_{#2}$}
\begin{document}
\pgfplotstabletypeset[
every head row/.style={
before row={%
\toprule
& & \multicolumn{5}{c}{\textbf{Head 2}} \\
\cmidrule(lr){3-7}
},
after row/.add={}{%
\midrule
\multirow{5}{*}{\rot{\parbox{2cm}{\centering \textbf{Head 1}}}}
},
},
col sep=semicolon,
string replace={---}{\textemdash},
use comma,
header=true,
multicolumn names={c},
columns/Empty/.style={column name=,column type=l,string type},
columns/Name/.style={column name=,column type=>{\collectcell\rowhead}l<{\endcollectcell},string type},
columns/A1/.style={column name={$A_1$},string type,column type={S}},
columns/A2/.style={column name={$A_2$},string type,column type={S}},
columns/A3/.style={column name={$A_3$},string type,column type={S}},
columns/A4/.style={column name={$A_4$},string type,column type={S}},
columns/A5/.style={column name={$A_5$},string type,column type={S}}
]{
Empty;Name;A1;A2;A3;A4;A5
;A1;1;1;1;1;1
;A2;1;1;1;1;1
;A3;1;1;1;1;1
;A4;1;1;1;1;1
;A5;1;1;1;1;1
}
\end{document}
