我正在尝试为我的 Beamer 主题设置背景。我想要一个带有圆角东北角的白色矩形。我使用了提供的代码。我的外部主题如下所示：
\mode<presentation>
\definecolor{mygray}{RGB}{240,240,240}
\tikzset{
rectangle with rounded corners north west/.initial=4pt,
rectangle with rounded corners south west/.initial=4pt,
rectangle with rounded corners north east/.initial=4pt,
rectangle with rounded corners south east/.initial=4pt,
}
\makeatletter
\pgfdeclareshape{rectangle with rounded corners}{
\inheritanchorborder[from=rectangle]
\savedmacro{\neoffset}{
\pgfkeysgetvalue{/tikz/rectangle with rounded corners north east}{\pgf@rectc}
\let\neoffset\pgf@rectc
}
\savedmacro{\nwoffset}{
\pgfkeysgetvalue{/tikz/rectangle with rounded corners north west}{\pgf@rectc}
\let\nwoffset\pgf@rectc
}
\savedmacro{\seoffset}{
\pgfkeysgetvalue{/tikz/rectangle with rounded corners south east}{\pgf@rectc}
\let\seoffset\pgf@rectc
}
\savedmacro{\swoffset}{
\pgfkeysgetvalue{/tikz/rectangle with rounded corners south west}{\pgf@rectc}
\let\swoffset\pgf@rectc
}
\savedanchor{\north}{
\pgf@y=.5\ht\pgfnodeparttextbox
\pgf@x=0pt
\setlength{\pgf@ya}{\pgfshapeminheight}
\ifdim\pgf@y<.5\pgf@ya
\pgf@y=.5\pgf@ya
\fi
}
\savedanchor{\south}{
\pgf@y=-.5\ht\pgfnodeparttextbox
\pgf@x=0pt
\setlength{\pgf@ya}{\pgfshapeminheight}
\ifdim\pgf@y>-.5\pgf@ya
\pgf@y=-.5\pgf@ya
\fi
}
\savedanchor{\east}{
\pgf@y=0pt
\pgf@x=.5\wd\pgfnodeparttextbox
\addtolength{\pgf@x}{2ex}
\setlength{\pgf@xa}{\pgfshapeminwidth}
\ifdim\pgf@x<.5\pgf@xa
\pgf@x=.5\pgf@xa
\fi
}
\savedanchor{\west}{
\pgf@y=0pt
\pgf@x=-.5\wd\pgfnodeparttextbox
\addtolength{\pgf@x}{-2ex}
\setlength{\pgf@xa}{\pgfshapeminwidth}
\ifdim\pgf@x>-.5\pgf@xa
\pgf@x=-.5\pgf@xa
\fi
}
\savedanchor{\northeast}{
\pgf@y=.5\ht\pgfnodeparttextbox % height of the box
\pgf@x=.5\wd\pgfnodeparttextbox % width of the box
\addtolength{\pgf@x}{2ex}
\setlength{\pgf@xa}{\pgfshapeminwidth}
\ifdim\pgf@x<.5\pgf@xa
\pgf@x=.5\pgf@xa
\fi
\setlength{\pgf@ya}{\pgfshapeminheight}
\ifdim\pgf@y<.5\pgf@ya
\pgf@y=.5\pgf@ya
\fi
}
\savedanchor{\southwest}{
\pgf@y=-.5\ht\pgfnodeparttextbox
\pgf@x=-.5\wd\pgfnodeparttextbox
\addtolength{\pgf@x}{-2ex}
% \pgf@x=0pt
\setlength{\pgf@xa}{\pgfshapeminwidth}
\ifdim\pgf@x>-.5\pgf@xa
\pgf@x=-.5\pgf@xa
\fi
\setlength{\pgf@ya}{\pgfshapeminheight}
\ifdim\pgf@y>-.5\pgf@ya
\pgf@y=-.5\pgf@ya
\fi
}
\anchor{text}{%
\northeast%
\pgf@x=-.5\wd\pgfnodeparttextbox%
\pgfmathsetlength{\pgf@y}{-.5ex}
}
\anchor{north east}{
\northeast
\pgfmathsetmacro{\nw}{(1-sin(45))*\neoffset}
\addtolength{\pgf@x}{-\nw pt}
\addtolength{\pgf@y}{-\nw pt}
}
\anchor{center}{
\pgf@x=0pt
\pgf@y=0pt
}
\anchor{south west}{
\southwest
\pgfmathsetmacro{\nw}{(1-sin(45))*\swoffset}
\addtolength{\pgf@x}{\nw pt}
\addtolength{\pgf@y}{\nw pt}
}
\anchor{north west}{
\northeast
\pgfmathsetmacro{\temp@x}{\pgf@x}
\southwest
\pgfmathsetmacro{\temp@xtwo}{\pgf@x}
\northeast
\pgfmathsetmacro{\xdiff}{\temp@x-\temp@xtwo}
\def\pgf@xa{\pgf@x-\xdiff}
\
\pgfmathsetmacro{\nw}{(1-sin(45))*\nwoffset}
\def\pgf@xaa{\pgf@xa+\nw}
\def\pgf@yaa{\pgf@y-\nw}
\pgfpoint{\pgf@xaa}{\pgf@yaa}
}
\anchor{south east}{
\southwest
\pgfmathsetmacro{\temp@x}{\pgf@x}
\northeast
\pgfmathsetmacro{\temp@xtwo}{\pgf@x}
\southwest
\pgfmathsetmacro{\xdiff}{\temp@x-\temp@xtwo}
\def\pgf@xa{\pgf@x-\xdiff}
\pgfmathsetmacro{\nw}{(1-sin(45))*\seoffset}
\def\pgf@xaa{\pgf@xa-\nw}
\def\pgf@yaa{\pgf@y+\nw}
\pgfpoint{\pgf@xaa}{\pgf@yaa}
}
\anchor{south}{\south}
\anchor{north}{\north}
\anchor{east}{\east}
\anchor{west}{\west}
\backgroundpath{% this is new
% store lower right in xa/ya and upper right in xb/yb
\southwest \pgf@xa=\pgf@x \pgf@ya=\pgf@y
\northeast \pgf@xb=\pgf@x \pgf@yb=\pgf@y
% construct main path
\pgfkeysgetvalue{/tikz/rectangle with rounded corners north west}{\pgf@rectc}
\pgfsetcornersarced{\pgfpoint{\pgf@rectc}{\pgf@rectc}}
\pgfpathmoveto{\pgfpoint{\pgf@xa}{\pgf@ya}}
\pgfpathlineto{\pgfpoint{\pgf@xa}{\pgf@yb}}
\pgfkeysgetvalue{/tikz/rectangle with rounded corners north east}{\pgf@rectc}
\pgfsetcornersarced{\pgfpoint{\pgf@rectc}{\pgf@rectc}}
\pgfpathlineto{\pgfpoint{\pgf@xb}{\pgf@yb}}
\pgfkeysgetvalue{/tikz/rectangle with rounded corners south east}{\pgf@rectc}
\pgfsetcornersarced{\pgfpoint{\pgf@rectc}{\pgf@rectc}}
\pgfpathlineto{\pgfpoint{\pgf@xb}{\pgf@ya}}
\pgfkeysgetvalue{/tikz/rectangle with rounded corners south west}{\pgf@rectc}
\pgfsetcornersarced{\pgfpoint{\pgf@rectc}{\pgf@rectc}}
\pgfpathclose
}
}
\makeatother
\setbeamertemplate{background}{
\begin{tikzpicture}
\useasboundingbox (0,0) rectangle(\the\paperwidth,\the\paperheight);
\fill[color=mygray] (0,0) rectangle (\the\paperwidth,\the\paperheight);
\node[
fill = white,
shape = rectangle with rounded corners,
minimum height= 9.4 cm,
minimum width = 12.6 cm,
rectangle with rounded corners north west = 0pt,
rectangle with rounded corners south west = 0pt,
rectangle with rounded corners north east = 5pt,
rectangle with rounded corners south east = 0pt,
](0,0) {};
\end{tikzpicture}
}
\mode<all>
因此，不要得到这样的背景：
tex 文档如下所示：
\documentclass{beamer}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\title{There Is No Largest Prime Number}
\date[ISPN ’80]{27th International Symposium of Prime Numbers}
\author[Euclid]{Euclid of Alexandria \texttt{[email protected]}}
\usetheme{mytheme}
\begin{document}
\begin{frame}
\end{frame}
\end{document}
和 beamerthememytheme.sty：
\mode<presentation>
% Required packages
\RequirePackage{tikz}
\RequirePackage{graphicx}
% Settings
\useinnertheme{mytheme}
\useoutertheme{mytheme}
\usecolortheme{mytheme}
% Presentation
\beamertemplatenavigationsymbolsempty
\setbeamertemplate{blocks}[rounded][shadow=false]
\mode<all>
答案1
我认为问题在于 的定义northeast，尤其是在pgf@x=.5\pgf@xa和中\pgf@y=.5\pgf@ya，因为这只占了页面的一半。因此，请尝试不使用.5
\savedanchor{\northeast}{
\pgf@y=.5\ht\pgfnodeparttextbox % height of the box
\pgf@x=.5\wd\pgfnodeparttextbox % width of the box
\addtolength{\pgf@x}{2ex}
\setlength{\pgf@xa}{\pgfshapeminwidth}
\ifdim\pgf@x<.5\pgf@xa
\pgf@x=\pgf@xa
\fi
\setlength{\pgf@ya}{\pgfshapeminheight}
\ifdim\pgf@y<.5\pgf@ya
\pgf@y=\pgf@ya
\fi
}
