漂亮的 circuitikz 包中缺少一些组件。我尝试在问题答案的帮助下创建这些组件CircuiTikZ — 创建新组件和circuitikz 中的新组件。现在我得到了所谓的 norator 的以下结果。正如所见,连接器位于圆圈的中心。我希望它们位于圆圈的左侧和右侧。欢迎提出任何建议。
提前谢谢了
我的代码是:
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usepackage{circuitikz}
\makeatletter
% used to process styles for to-path
\def\TikzBipolePath#1#2{\pgf@circ@bipole@path{#1}{#2}}
% restore size value for bipole definitions
\pgf@circ@Rlen = \pgfkeysvalueof{/tikz/circuitikz/bipoles/length}
\makeatother
\newlength{\ResUp}
\newlength{\ResDown}
\newlength{\ResLeft}
\newlength{\ResRight}
% norator
\ctikzset{bipoles/norator/height/.initial=.35} % box height
\ctikzset{bipoles/norator/width/.initial=.35} % box width
\pgfcircdeclarebipole{} % no extra anchors
{\ctikzvalof{bipoles/norator/height}}
{norator} % component name
{\ctikzvalof{bipoles/norator/height}}
{\ctikzvalof{bipoles/norator/width}}
{ % component symbol drawing ...
\pgfsetlinewidth{\pgfkeysvalueof{/tikz/circuitikz/bipoles/thickness}\pgfstartlinewidth}
\pgfextracty{\ResUp}{\northeast} % coordinates
\pgfextracty{\ResDown}{\southwest}
\pgfextractx{\ResLeft}{\southwest}
\pgfextractx{\ResRight}{\northeast}
\pgfpathellipse{\pgfpoint{\ResUp}{0}}
{\pgfpoint{0}{\ResUp}}
{\pgfpoint{\ResUp}{0}}
\pgfpathellipse{\pgfpoint{-\ResUp}{0}}
{\pgfpoint{0}{\ResUp}}
{\pgfpoint{\ResUp}{0}}
\pgfusepath{draw} % draw it!
}
\def\circlepath#1{\TikzBipolePath{norator}{#1}}
\tikzset{norator/.style = {\circuitikzbasekey, /tikz/to path=\circlepath, l=#1}}
\begin{document}
\begin{circuitikz}[scale=0.75, european resistors]
\draw
(0,0) to [short, o-] (1,0)
to [norator] (2,0) % connect the new component
to [R, -o] (5,0)
;
\end{circuitikz}
\end{document}
答案1
好的,经过一些实验,我终于找到了一些解决方案:
我修改的值是初始高度和宽度,然后是圆心和半径。
\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usepackage{circuitikz}
\makeatletter
% used to process styles for to-path
\def\TikzBipolePath#1#2{\pgf@circ@bipole@path{#1}{#2}}
% restore size value for bipole definitions
\pgf@circ@Rlen = \pgfkeysvalueof{/tikz/circuitikz/bipoles/length}
\makeatother
\newlength{\ResUp}
\newlength{\ResDown}
\newlength{\ResLeft}
\newlength{\ResRight}
% norator
\ctikzset{bipoles/norator/height/.initial=.5} % box height
\ctikzset{bipoles/norator/width/.initial=.5} % box width
\pgfcircdeclarebipole{} % no extra anchors
{\ctikzvalof{bipoles/norator/height}}
{norator} % component name
{\ctikzvalof{bipoles/norator/height}}
{\ctikzvalof{bipoles/norator/width}}
{ % component symbol drawing ...
\pgfsetlinewidth{\pgfkeysvalueof{/tikz/circuitikz/bipoles/thickness} \pgfstartlinewidth}
\pgfextracty{\ResUp}{\northeast} % coordinates
\pgfextracty{\ResDown}{\southwest}
\pgfextractx{\ResLeft}{\southwest}
\pgfextractx{\ResRight}{\northeast}
\pgfpathellipse{\pgfpoint{\ResUp/2}{0}}
{\pgfpoint{0}{\ResUp/2}}
{\pgfpoint{\ResUp/2}{0}}
\pgfpathellipse{\pgfpoint{-\ResUp/2}{0}}
{\pgfpoint{0}{\ResUp/2}}
{\pgfpoint{\ResUp/2}{0}}
\pgfusepath{draw} % draw it!
}
\def\circlepath#1{\TikzBipolePath{norator}{#1}}
\tikzset{norator/.style = {\circuitikzbasekey, /tikz/to path=\circlepath, l=#1}}
\begin{document}
\begin{circuitikz}[scale=0.75, european resistors]
\draw
(0,0) to [short, o-] (1,0)
to [norator] (2,0) % connect the new component
to [R, -o] (5,0)
;
\end{circuitikz}
\end{document}
答案2
PSTricks 解决方案使用pst-circ
包裹:
\documentclass{article}
\usepackage{pst-circ}
\begin{document}
\begin{pspicture}[dimen = m](5.5,1)
\pnodes(0,0.5){A}(1,0.5){B}(2,0.5){C}(3,0.5){D}(5.5,0.5){E}
\wire[arrows = o-](A)(B)
\Ucc(B)(C){}
\Ucc(C)(D){}
\resistor[arrows = -o](D)(E){}
\end{pspicture}
\end{document}