如何绘制偏移边框到 tikz 节点？

Question

如何制作如附图所示的偏移边框。这看起来应该很容易用 tikz 完成。我可以使用节点的“double”选项，但我不知道如何继续附加箭头。

添加：

与此同时，我得到了以下结果：

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning,decorations.markings,arrows}

\begin{document}

\tikzstyle{border_arrow} = [%
  decoration={markings,mark=at position 1 with {\arrow[scale=2,line width=.25pt,red!50]{open triangle 60}}}, %
  red!50, double distance=4.4pt, shorten >= 9.5pt, shorten <= .45mm, %
line width=.5pt, %
  preaction = {decorate}, %
  postaction = {draw,line width=4.4pt, white,shorten >= 8.5pt, shorten <= 1pt}]
\tikzstyle{my_node} = [double,double distance=1mm, inner sep=3mm, text width=2.5cm, align=center,line width=.5pt,font=\sffamily\footnotesize\color{white},draw=red!50, fill=red!50]

\begin{tikzpicture}
\node (data1) [my_node] {Commercial Starting Material};
\node [right=of data1] (A) {}; % phantom node to avoid overlapping
\draw[border_arrow] (data1.east|-A.west) -- (A.west);
\node (data2) [right of=A, my_node,xshift=.6cm] {A $\to$ B $\to$ C $\to$ D};
\end{tikzpicture}

\end{document}

如果有人有更简单的方法来实现类似的结果，我很高兴听到这个消息。

Answer 1

我尝试重现您提供的图像：

我的代码是从头编写的::

\documentclass[tikz,
                border=3mm]{standalone}
\usetikzlibrary{calc,
                fit,
                positioning,
                shapes}

\begin{document}
\begin{tikzpicture}[
 node distance = 0mm and 12mm,
 databox/.style = {inner sep=3mm, text width=2.4cm, align=center, fill=red,
                   font=\sffamily\footnotesize\bfseries\color{white}
                   },
arrowbox/.style = {arrow box, arrow box  arrows={east:12mm},
                   arrow box shaft width=5mm, arrow box head extend=3mm,
                   draw=red, very thick, inner sep=3mm
                   }
                    ]
\node (data1)   [databox]   {Commercial Starting Material};
\node (A1)      [arrowbox, fit=(data1)] {};
%
\node (data2)   [databox, right=of A1.east]
                            {A $\to$ B $\to$ C $\to$ D};
\node (A2)      [arrowbox, fit=(data2)] {};
\end{tikzpicture}
\end{document}

Answer 2

基于matrix具有arrowbox样式并包含databox节点的替代解决方案。

我以为matrix节点总是矩形的，但现在我知道它可以容纳shape我们想要的任何东西。矩阵仅排列内部节点。

总部位于扎科的代码：

\documentclass[tikz, border=3mm]{standalone}
\usetikzlibrary{positioning, shapes}

\begin{document}
\begin{tikzpicture}[
     node distance = 0mm and 12mm,
     databox/.style = {rectangle, %<---- added
                   inner sep=3mm, text width=2.4cm,  
                   align=center, fill=red,
                   font=\sffamily\footnotesize\bfseries\color{white}
                   },
     arrowbox/.style = {arrow box, arrow box  arrows={east:12mm},
                   arrow box shaft width=5mm, arrow box head extend=3mm,
                   draw=red, very thick, inner sep=3mm,
                   minimum width=36mm, minimum height=15mm
                   }
                    ]
\matrix[arrowbox] (A1) {\node[databox] {Commercial Starting Material};\\};
\matrix[arrowbox, right=of A1.east] (A1) {%
      \node[databox] {A $\to$ B $\to$ C $\to$ D};\\};
\end{tikzpicture}
\end{document}