这个问题与这个问题。我想在两点之间画一个箭头，箭头中间有一个开关。我按照上面链接的建议做了，但这种方法并不通用，每次我们都必须在那里玩数字才能得到我们想要的。例如，考虑以下代码：
\documentclass[12pt]{report}
\usepackage{tikz}
\usepackage{circuitikz}
\usepackage{tikz-cd}
\usetikzlibrary{arrows,decorations.markings,decorations}
\usetikzlibrary{arrows,shapes,calc,positioning}
\tikzstyle{block} = [draw,rectangle, rounded corners, minimum width=1cm, minimum height=0.8cm,text centered, line width=2pt ]
\tikzstyle{arrow} = [thick,->,>=stealth,line width=2pt]
\tikzset{addarrow/.style={decoration={markings, mark=at position 1 with {\arrow{stealth}}}, postaction={decorate}} }
\begin{document}
\begin{figure}
\begin{tikzpicture}
\node (b) at (1,1) {$A$};
\node (a) at (2.5,-1.9) {$B$};
\draw [->,>=stealth,line width=1pt] (a) to[out=105,in=-50] coordinate[pos=.35] (A) coordinate[pos=.55] (B) (b) ;
\fill[white] ( [yshift=-2mm] A) rectangle ( [yshift=1mm] B);
\draw [line width=1pt] (A) to[cspst] (B);
\end{tikzpicture}
\end{figure}
\end{document}
输出如下。
可以看出，开关没有完全连接到线路。我们该如何解决这个问题？为什么代码中有 0.35 和 -2mm（坐标 [pos=.35]，[yshift=-2mm]）？
答案1
有几种方法可以改善开关和线条之间的连接。一种是在连接点处添加点。另一种是将填充圆的半径减小约线宽的一半。
\documentclass[12pt]{report}
\usepackage{tikz}
\usepackage{circuitikz}
\usepackage{tikz-cd}
\usetikzlibrary{arrows,decorations.markings,decorations}
\usetikzlibrary{arrows,shapes,calc,positioning}
\tikzstyle{block} = [draw,rectangle, rounded corners, minimum width=1cm, minimum height=0.8cm,text centered, line width=2pt ]
\tikzstyle{arrow} = [thick,->,>=stealth,line width=2pt]
\tikzset{addarrow/.style={decoration={markings, mark=at position 1 with {\arrow{stealth}}}, postaction={decorate}} }
\begin{document}
\begin{figure}
\begin{tikzpicture}
\node (b) at (1,1) {$A$};
\node (a) at (2.5,-1.9) {$B$};
\draw [->,>=stealth,line width=1pt] (a) to[out=105,in=-50] coordinate[pos=.35] (A) coordinate[pos=.55] (B) (b) ;
\fill[white] let \p1=($(A)-(B)$), \n2={.5*veclen(\x1,\y1)-.25pt}
in ($(A)!.5!(B)$) circle(\n2);
\draw [line width=.5pt] (A) to[cspst,*-*] (B);
\end{tikzpicture}
\end{figure}
\end{document}
