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如何整齐地将长方程式排列在一起

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如何整齐地将长方程式排列在一起

我有七个不同的方程式，我想将它们左对齐。

下面是我用来对齐方程的代码：

\begin{equation}
\phi_{1} \; = \; n_{20} + n_{02}
\end{equation}

\begin{equation}
\phi_{2} \; = \; (n_{20} - n_{02})^2 + 4n_{11}^2
\end{equation}

\begin{equation}
\phi_{3} \; = \; n_{30} - n_{12}^2 + 3n_{21} - n_{03}^2
\end{equation}

\begin{equation}
\phi_{4} \; = \; n_{30} + n_{12}^2 + 3n_{21} + n_{03}^2
\end{equation}

\begin{multline}
\phi_{5} \; = \; (n_{30} - 3n_{12})(n_{30} + n_{12})[(n_{30} + n_{12}^2) -3(n_{30} + n_{12})^2] + (3n_{12} - n_{03})(n_{21} + n_{03})[3(n_{30} + n_ {12})^2 - (n_{21} + n_{03})^2]
\end{multline}

\begin{equation}
\phi_{6} \; = \; (n_{20} - n_{02})[(n_{30} + n_{12}^2) - (n_{21} + n_{03})^2] + 4n_{11}(n_{30} + n_{12})(n_{21} + n_{03})
\end{equation}

\begin{equation}
\phi_{7} \; = \; (3n_{21} - n_{03})(n_{30} + n_{12})[(n_{30} + n_{12})^2 - 3(n_{21} + n_{03})^2] + (3n_{12} - n_{30})(n_{21} + n_{03})[3(n_{30} + n_{12})^2 - (n_{21} + n_{03}^2)]
\end{equation}

我希望方程式左对齐并在每一行上均匀分布，也就是说，如果方程式太长，它应该转到下一行。

答案1

单一align环境似乎是正确的，另外还有方程式 5、6 和 7 的额外换行符；这些方程式的后半部分\quad相对于前半部分缩进（缩进量为）。请注意，我对符号进行了对齐=，而不是完全左对齐。

在此处输入图片描述

\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{align}
\phi_{1} &= n_{20} + n_{02}\\
\phi_{2} &= (n_{20} - n_{02})^2 + 4n_{11}^2\\
\phi_{3} &= n_{30} - n_{12}^2 + 3n_{21} - n_{03}^2\\
\phi_{4} &= n_{30} + n_{12}^2 + 3n_{21} + n_{03}^2\\
\phi_{5} &= (n_{30} - 3n_{12})(n_{30} + n_{12})[(n_{30} + n_{12}^2) -3(n_{30} + n_{12})^2] \notag\\
&\quad+ (3n_{12} - n_{03})(n_{21} + n_{03})[3(n_{30} + n_ {12})^2 - (n_{21} + n_{03})^2]\\
\phi_{6} &= (n_{20} - n_{02})[(n_{30} + n_{12}^2) - (n_{21} + n_{03})^2] \notag\\
&\quad+ 4n_{11}(n_{30} + n_{12})(n_{21} + n_{03})\\
\phi_{7} &= (3n_{21} - n_{03})(n_{30} + n_{12})[(n_{30} + n_{12})^2 - 3(n_{21} + n_{03})^2] \notag\\
&\quad+ (3n_{12} - n_{30})(n_{21} + n_{03})[3(n_{30} + n_{12})^2 - (n_{21} + n_{03}^2)]
\end{align}
\end{document}

答案2

您可以使用align和split：

\documentclass{article}
\usepackage{amsmath}

\begin{document}

\begin{align}
\phi_{1} &= n_{20} + n_{02}
\\
\phi_{2} &= (n_{20} - n_{02})^2 + 4n_{11}^2
\\
\phi_{3} &= n_{30} - n_{12}^2 + 3n_{21} - n_{03}^2
\\
\phi_{4} &= n_{30} + n_{12}^2 + 3n_{21} + n_{03}^2
\\
\begin{split}
\phi_{5} &= (n_{30} - 3n_{12})(n_{30} + n_{12})[(n_{30} + n_{12}^2) -3(n_{30} + n_{12})^2] \\
         &\qquad+ (3n_{12} - n_{03})(n_{21} + n_{03})[3(n_{30} + n_ {12})^2 - (n_{21} + n_{03})^2]
\end{split}
\\
\begin{split}
\phi_{6} &= (n_{20} - n_{02})[(n_{30} + n_{12}^2) - (n_{21} + n_{03})^2] \\
         &\qquad+ 4n_{11}(n_{30} + n_{12})(n_{21} + n_{03})
\end{split}
\\
\begin{split}
\phi_{7} &= (3n_{21} - n_{03})(n_{30} + n_{12})[(n_{30} + n_{12})^2 - 3(n_{21} + n_{03})^2] \\
         &\qquad+ (3n_{12} - n_{30})(n_{21} + n_{03})[3(n_{30} + n_{12})^2 - (n_{21} + n_{03}^2)]
\end{split}
\end{align}

\end{document}

在此处输入图片描述

align与有什么区别\notag？ a 中的方程编号split垂直居中（除非tbtags将选项传递给amsmath）。

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