我想使用“tcbraster”拆分我的文档，但它不起作用
我指的是分页，类似于你在@Christian Hupfer 在这篇文章中所做的那样 将页面拆分为两个相互独立的内容
我尝试减少我的代码：
\documentclass[11pt,a4paper]{report} \usepackage[margin=0.5in]{geometry} \usepackage{multicol} \usepackage[french]{babel} \usepackage{fontspec} \usepackage{graphicx} \usepackage{amsthm,amssymb,amsfonts,mathtools} \newcommand{\centerbox}[1]% #1 = text {\bgroup% use local definitions \parskip=0pt \sbox0{\fbox{#1}} \dimen0=\dimexpr 0.5\textwidth - 0.5\wd0\relax \par\noindent\rule{\dimen0}{0.8pt}\box0\rule{\dimen0}{0.8pt}\par \egroup} \usepackage{xhfill} \usepackage{fancyhdr} %\usepackage{xcolor} %\usepackage{tcolorbox} \usepackage[svgnames]{xcolor} %\usepackage[most]{tcolorbox} \tcbuselibrary{skins,breakable,xparse} \usepackage{tikz} \usetikzlibrary{shapes,arrows,fit,calc,positioning} \tikzset{box/.style={draw, rectangle, thick, text centered, minimum height=3em}} \tikzset{line/.style={draw, thick, -latex'}} \newlength\TextBoxWd% width of the text boxes \newlength\TextBoxSep% separation of the text boxes \newlength\TextBoxHt% height of the text boxes \setlength\TextBoxWd{\marginparwidth} \setlength\TextBoxSep{\marginparsep} \setlength\TextBoxHt{2cm} \newcommand\ThickTitleRule{\xrfill[0.5ex]{3pt}} \newcommand\Title[4]{% \begingroup \setlength\parindent{0pt}% \par \makebox[\linewidth]{% % \fbox{\parbox[t][\TextBoxHt][c]{\TextBoxWd}{\raggedright#3}}\hspace{\TextBoxSep}% \parbox[t]{\textwidth}{% \leavevmode \centering \ThickTitleRule\quad{\scshape\bfseries\itshape#1}\quad\ThickTitleRule\par \vskip-0.2\baselineskip \rule{\textwidth}{2pt}\par\vskip-.8\baselineskip% Thick horizontal line \rule{\textwidth}{0.4pt}%Thin horizontal line \par\vskip0.75ex {\Large\scshape\bfseries\itshape#2\par}% Title \rule{\textwidth}{0.4pt}\par\par\vskip-.7\baselineskip% Thin horizontal line \rule{\textwidth}{2pt}% Thick horizontal line }% % \hspace{\TextBoxSep}\fbox{\parbox[t][\TextBoxHt][c]{\TextBoxWd}{\raggedright#4}}\par% }% \vskip\baselineskip \endgroup } \begin{document} \Title{Mohcine}{Educ}{}{} \bigskip \noindent\rule{\textwidth}{0.8pt} \begin{tcbraster}[raster columns=2,raster equal height=rows,raster valign=top,raster column skip=5mm] \centerbox{Exercice 1}% Soient $a$ et $b$ deux ombres réels non nuls. Montrer que : \[3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge 2\left(\frac{a}{b}+\frac{b}{a}\right)\] \centerbox{Solution de l'exercice 1} \subsection*{\fbox{Méthode 1}} \begin{description} \item[] \end{description} Soit $a,b\in\mathbb{R}^*$ Posons $t=\dfrac{a}{b}+\dfrac{b}{a}$ , on a : \[ \begin{aligned} & 3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge 2\left(\frac{a}{b}+\frac{b}{a}\right) \\ \iff & 3+\frac{a^2}{b^2}+\frac{b^2}{a^2}-2\left(\frac{a}{b}+\frac{b}{a}\right) \geq 0\\ \iff & t^{2}-2t+1\geq 0\\ \iff & \left(t-1\right)^{2}\geq 0 \end{aligned} \] comme on a $\forall t\in \mathbb{R}\quad (t-1)^{2}\geq 0$ une proposition vraie alors la proposition \[ \forall a,b\in \mathbb{R}^*\quad 3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge 2\left(\frac{a}{b}+\frac{b}{a}\right) \] est vraie \centerbox{Exercice 2}% Bla Bla Bla \centerbox{Solution de l'exercice 2} Bla bla bla \end{tcbraster} \end{document}
答案1
这是一个初步的解决方案。我没有清除所有不必要的东西。正如@ChrstianHupref 所说，环境tcbraster必须仅包含tcolorbox或相关（甚至不能包含空行！）。顺便说一句，它说的是练习 2 的解决方案，应该是 1。你应该使用带有and 的\par适当计数器。\label\ref
\documentclass[11pt,a4paper]{report}
\usepackage[margin=0.5in]{geometry}
\usepackage{multicol}
\usepackage[french]{babel}
\usepackage{fontspec}
\usepackage{graphicx}
\usepackage{amsthm,amssymb,amsfonts,mathtools}
% \newcommand{\centerbox}[1]% #1 = text
% {\bgroup% use local definitions
% \parskip=0pt
% \sbox0{\fbox{#1}}
% \dimen0=\dimexpr 0.5\textwidth - 0.5\wd0\relax
% \par\noindent\rule{\dimen0}{0.8pt}\box0\rule{\dimen0}{0.8pt}\par
% \egroup}
\usepackage[svgnames]{xcolor}
\usepackage{xhfill}
\usepackage{fancyhdr}
%\usepackage{xcolor}
\usepackage{tcolorbox}
%\usepackage[most]{tcolorbox}
\tcbuselibrary{skins,breakable,xparse,raster}
\usepackage{tikz}
\usetikzlibrary{shapes,arrows,fit,calc,positioning}
\tikzset{box/.style={draw, rectangle, thick, text centered, minimum height=3em}}
\tikzset{line/.style={draw, thick, -latex'}}
\newlength\TextBoxWd% width of the text boxes
\newlength\TextBoxSep% separation of the text boxes
\newlength\TextBoxHt% height of the text boxes
\setlength\TextBoxWd{\marginparwidth}
\setlength\TextBoxSep{\marginparsep}
\setlength\TextBoxHt{2cm}
\newcommand\ThickTitleRule{\xrfill[0.5ex]{3pt}}
\newcommand\Title[4]{%
\begingroup
\setlength\parindent{0pt}%
\par
\makebox[\linewidth]{%
% \fbox{\parbox[t][\TextBoxHt][c]{\TextBoxWd}{\raggedright#3}}\hspace{\TextBoxSep}%
\parbox[t]{\textwidth}{%
\leavevmode
\centering
\ThickTitleRule\quad{\scshape\bfseries\itshape#1}\quad\ThickTitleRule\par
\vskip-0.2\baselineskip
\rule{\textwidth}{2pt}\par\vskip-.8\baselineskip% Thick horizontal line
\rule{\textwidth}{0.4pt}%Thin horizontal line
\par\vskip0.75ex
{\Large\scshape\bfseries\itshape#2\par}% Title
\rule{\textwidth}{0.4pt}\par\par\vskip-.7\baselineskip% Thin horizontal line
\rule{\textwidth}{2pt}% Thick horizontal line
}%
% \hspace{\TextBoxSep}\fbox{\parbox[t][\TextBoxHt][c]{\TextBoxWd}{\raggedright#4}}\par%
}%
\vskip\baselineskip
\endgroup
}
\usepackage[printwatermark]{xwatermark}
%\usepackage{xcolor}
\newwatermark[allpages,color= magenta!30,angle=45,scale=3,xpos=0,ypos=0]{Mohcine }
\newtcolorbox{centerbox}[2][]{colback=white, colframe=black!75,fonttitle=\normalfont,
colbacktitle=white, coltitle=black,
enhanced, attach boxed title to top center={yshift=-3mm},
title=#2,#1}
%========================================================================================
\begin{document}
\Title{Mohcine}{Educ}{}{}
\bigskip
%\begin{LTR}
\noindent\rule{\textwidth}{0.8pt}
\begin{tcbraster}[raster columns=2,raster equal height=rows,raster valign=top]%,raster column skip=5mm]
%
\begin{centerbox}{Exercice 1}%
Soient $a$ et $b$ deux ombres réels non nuls. Montrer que :
\[
3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge
2\left(\frac{a}{b}+\frac{b}{a}\right)
\]
\end{centerbox}
%
\begin{centerbox}{Solution de l'exercice 2}
\subsection*{\fbox{Méthode 1}}
\begin{description}
\item[]
\end{description}
Soit $a,b\in\mathbb{R}^*$
Posons $t=\dfrac{a}{b}+\dfrac{b}{a}$ , on a :
\[
\begin{aligned}
& 3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge
2\left(\frac{a}{b}+\frac{b}{a}\right) \\
\iff &
3+\frac{a^2}{b^2}+\frac{b^2}{a^2}-2\left(\frac{a}{b}+\frac{b}{a}\right) \geq 0\\
\iff & t^{2}-2t+1\geq 0\\
\iff & \left(t-1\right)^{2}\geq 0
\end{aligned}
\]
comme on a $\forall t\in \mathbb{R}\quad (t-1)^{2}\geq 0$ une
proposition vraie alors la proposition
\[
\forall a,b\in \mathbb{R}^*\quad
3+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge
2\left(\frac{a}{b}+\frac{b}{a}\right)
\]
est vraie
\end{centerbox}
%
\begin{centerbox}{Exercice 2}%
\subsection*{\fbox{Méthode 2}}
\end{centerbox}
\end{tcbraster}
%\end{LTR}
\end{document}
