我该如何解决仅用一个荣誉来写公式的问题？

Question

我应该写出以下公式： 这是代码：

\begin{equation}
 Q_{sp}=\left\{\stackrel{\frac{\kappa_{0}\kappa_{1}\dots \kappa_{Zp-1}}{\mu_{1}\mu_{2}\dots\mu_{Zp} (1+\sum^{n}_{l=1} \frac{\kappa_{0}\kappa_{1}
\dots \kappa_{l-1}}{\mu_{1}\mu_{2}\dots \mu_{l}})} \dots 1\leq Zp\leq number\_pol}{\frac{1}{1+\sum^{n}_{l=1}\frac{\kappa_{0}\kappa_{1} 
\dots \kappa_{l-1}}{\mu_{1}\mu_{2}\dots \mu_{l}}} \dots Zp=0} 
\end{equation}

我如何解决只用一个荣誉来写而不犯这个错误的问题

!Missing  \right. inserted

Answer 1

来自 AMSmath 包手册第 8 页的示例。

\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation*}
\left.
\begin{aligned}
  B’&=-\partial\times E,\\
  E’&=\partial\times B - 4\pi j,
\end{aligned}
\right\}
\qquad \text{Maxwell’s equations}
\end{equation*}
\end{document}

用你的方程解：

\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation}
 Q_{sp}=\left\{\stackrel{\frac{\kappa_{0}\kappa_{1}\dots \kappa_{Zp-1}}{\mu_{1}\mu_{2}\dots\mu_{Zp} (1+\sum^{n}_{l=1} \frac{\kappa_{0}\kappa_{1}\dots \kappa_{l-1}}{\mu_{1}\mu_{2}\dots \mu_{l}})} \dots 1\leq Zp\leq number\_pol}{\frac{1}{1+\sum^{n}_{l=1}\frac{\kappa_{0}\kappa_{1} \dots \kappa_{l-1}}{\mu_{1}\mu_{2}\dots \mu_{l}}} \dots Zp=0}\right.
\end{equation}
\end{document}

Answer 2

这是一个解决方案dcases，并对垂直间距进行了一些改进：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{lmodern}
\usepackage{mathtools}

\begin{document}

\begin{equation}
  Q_{sp}=\begin{dcases}\stackrel{\frac{\kappa_{0}\kappa_{1} ... \kappa_{Zp-1}}{\mu_{1}\mu_{2} ... \mu_{Zp} \bigl(1+\sum^n_{l=1} \frac{\kappa_{0}\kappa_{1}
    \dotsm \kappa_{l-1}\mathstrut}{\mu_{1}\mu_{2} ... \mu_{l}}\bigr)} ... 1\leq Zp\leq \text{number\_pol}}{\frac{\strut1}{1+\sum^n_{l=1}\frac{\kappa_{0}\kappa_{1}
     ... \kappa_{l-1}}{\mu_{1}\mu_{2} ... \mu_{l}}} ... Zp=0}
  \end{dcases}
\end{equation}

\end{document}