如何从缓冲区中获取命令输出?目前它只是说“(缓冲区)。
这是我的脚本和调试输出:
#!/bin/bash -x
while read p; do
echo $p
{
/usr/bin/expect -d << EOF
match_max 10000
spawn ssh anthony@$p
expect "password:"
send "MyPasswordHere\r"
expect " "
send "ifconfig |grep -i eth0\r"
expect " "
puts "The output is $expect_out(buffer) "
send "exit\r"
EOF
}
done <List.txt
+ read p
+ echo localhost
localhost
+ /usr/bin/expect -d
expect version 5.45
argv[0] = /usr/bin/expect argv[1] = -d
set argc 0
set argv0 "/usr/bin/expect"
set argv ""
executing commands from command file
spawn ssh anthony@localhost
parent: waiting for sync byte
parent: telling child to go ahead
parent: now unsynchronized from child
spawn: returns {2032}
expect: does "" (spawn_id exp15) match glob pattern "password:"? no
anthony@localhost's password:
expect: does "anthony@localhost's password: " (spawn_id exp15) match glob pattern "password:"? yes
expect: set expect_out(0,string) "password:"
expect: set expect_out(spawn_id) "exp15"
expect: set expect_out(buffer) "anthony@localhost's password:"
send: sending "M00nsh0t@\r" to { exp15 }
expect: does " " (spawn_id exp15) match glob pattern " "? yes
expect: set expect_out(0,string) " "
expect: set expect_out(spawn_id) "exp15"
expect: set expect_out(buffer) " "
send: sending "ifconfig |grep -i eth0\r" to { exp15 }
expect: does "" (spawn_id exp15) match glob pattern " "? no
expect: does "\r\n" (spawn_id exp15) match glob pattern " "? no
Welcome to Ubuntu 14.04.1 LTS (GNU/Linux 3.13.0-40-generic x86_64)
* Documentation: https://help.ubuntu.com/
Last login: Sun Dec 21 09:23:38 2014 from localhost
expect: does "\r\nWelcome to Ubuntu 14.04.1 LTS (GNU/Linux 3.13.0-40-generic x86_64)\r\n\r\n * Documentation: https://help.ubuntu.com/\r\n\r\nLast login: Sun Dec 21 09:23:38 2014 from localhost\r\r\n" (spawn_id exp15) match glob pattern " "? yes
expect: set expect_out(0,string) " "
expect: set expect_out(spawn_id) "exp15"
expect: set expect_out(buffer) "\r\nWelcome "
The output is (buffer)
send: sending "exit\r" to { exp15 }
+ read p
答案1
由于您的期望脚本位于未加引号的定界符中,因此您的期望变量将作为 shell 变量进行处理。改变
puts "The output is $expect_out(buffer) "
到
puts "The output is \$expect_out(buffer) "
您看到的输出 ( The output is (buffer)
) 正是我所期望的:$expect_out
在将脚本交给预期之前,shell 已扩展为空。