我需要减少公式后的垂直间距。拆分公式后,垂直间距增加了。
代码:
Objective Function
\setlength\belowdisplayskip{10pt plus 1pt minus 10pt}
\setcounter{equation}{0}
\begin{align}
\begin{split}
\text{minimize} \qquad & \space F1:\Bigg [\sum_{t\in T} \left(UU_t + OU_t \right)\Bigg] + \\
&\qquad F2: \Bigg[\sum_{p\in P} w^i_p X_p + \sum_{k} \frac{1}{k} \left( \sum_{p\in p} \sum_{t\in T} w^e_p Y_{pt} + \sum_{p\in p} \sum_{t\in T} w^t_p \eta_{pt}\ + \right. \\
& \qquad \left. \sum_{p\in p} \sum_{t\in T} w^u_p \Omega_{pt}\ + \sum_{p\in p} \sum_{t\in T} w^q_p \Delta_{pt}\ \right) \Bigg]
\end{split}
\end{align}
答案1
我建议您按照下列方式重写整个表达式:
\documentclass{article}
\usepackage{mathtools}
\begin{document}
Objective Function $F=F_1+F_2$, where
\begin{align}
F_1 &= \sum_{t\in T} (UU_t + OU_t)\\
\shortintertext{and}
F_2 &= \sum_{p\in P} w^i_p X_p + \sum_{k}
\frac{1}{k} \biggl(\,\sum_{p\in p} \sum_{t\in T} w^e_p Y_{pt} + \sum_{p\in p} \sum_{t\in T} w^t_p \eta_{pt} \notag\\
& \qquad +\sum_{p\in p} \sum_{t\in T} w^u_p \Omega_{pt}\ + \sum_{p\in p} \sum_{t\in T} w^q_p \Delta_{pt} \biggr)
\end{align}
\end{document}