我正在尝试编写宏来呈现几种类型的引用，并且除了方程式之外，它们都可以正常工作。\namecref{eq:1}给我“??”而不是方程式，并\nameref{eq:1}给我封闭环境的描述而不是空字符串。下面的文档包含我的宏和示例文本，显示了问题。
\documentclass{amsart}
\usepackage{ifthen}
% This should be the last package
\usepackage [colorlinks] {hyperref}
\usepackage{cleveref}
\newcommand \fullref [1]
{ \ifthenelse {\equal{\nameref{#1}}{}}
{\cref{#1}}
{\cref{#1} (\nameref{#1})}
}
\newcommand \fullrefrange [2]
{\namecrefs{#1}
\ifthenelse {\equal{\nameref{#1}}{}}
{\ref{#1}}
{\ref{#1} (\nameref{#1})}
to
\ifthenelse {\equal{\nameref{#2}}{}}
{\ref{#2}}
{\ref{#2} (\nameref{#2})}
}
\newcommand \Pageref [1]
{ \ifthenelse {\equal{\nameref{#1}}{}}
{\cref{#1} on p.~\pageref{#1}}
{\cref{#1} (\nameref{#1}) on p.~\pageref{#1}}
}
\newcommand \refrange [2]
{
\ref{#1}
to
\ref{2}
}
\newtheorem{theorem}{Theorem}[section]
\newtheorem{lemma}[theorem]{Lemma}
\theoremstyle{definition}
\newtheorem{corollary}{Corollary}
\newtheorem{definition}[theorem]{Definition}
\newtheorem{example}[theorem]{Example}
\newtheorem{xca}[theorem]{Exercise}
\theoremstyle{remark}
\newtheorem{remark}[theorem]{Remark}
\numberwithin{equation}{section}
\begin{document}
\begin{definition}[A definition]
\label{def:1}
This is a definition.
\end{definition}
\begin{lemma}[A lemma]
\label{lem:1}
This is a lemma.
\begin{enumerate}
\item
\label{it:rishon}
first
\item
\label{it:sheini}
second
\end{enumerate}
\end{lemma}
\begin{corollary}[A corollary]
\label{cor:1}
This is a corollary.
\end{corollary}
\begin{corollary}[Another corollary]
\label{cor:2}
This is another corollary.
\end{corollary}
\begin{theorem}[A theorem]
\label{thm:1}
This is a theorem.
\begin{subequations}
\begin{equation}
\label{eq:1}
first
\end{equation}
\begin{equation}
\label{eq:2}
second
\end{equation}
\end{subequations}
\end{theorem}
\begin{flushleft}
autoref\{cor:1\} = \autoref{cor:1} \\
cref\{cor:1\} = \cref{cor:1} \\
crefrange\{cor:1\}\{cor:2\} = \crefrange{cor:1}{cor:2} \\
fullrefrange\{cor:1\}\{cor:2\} = \fullrefrange{cor:1}{cor:2}
\end{flushleft}
\begin{flushleft}
autoref\{def:1\} = \autoref{def:1} \\
cref\{def:1\} = \cref{def:1} \\
fullref\{def:1\} = \fullref{def:1} \\
namecref\{def:1\} = \namecref{def:1} \\
namecrefs\{def:1\} = \namecrefs{def:1}
\end{flushleft}
\begin{flushleft}
crefrange\{eq:1\}\{eq:2\} = \crefrange{eq:1}{eq:2} \\
fullref\{eq:1\} = \fullref{eq:1} \\
fullrefrange\{eq:1\}\{eq:2\} = \fullrefrange{eq:1}{eq:2} \\
labelcref\{eq:1\} = \labelcref{eq:1} \\
namecref\{eq:1\} = \namecref{eq:1} \\
namecrefs\{eq:1\} = \namecrefs{eq:1} \\
nameref\{eq:1\} = \nameref{eq:1}
\end{flushleft}
\begin{flushleft}
autoref\{it:sheini\} = \autoref{it:sheini} \\
cref\{it:sheini\} = \cref{it:sheini} \\
cref\{it:rishon,it:sheini\} = \cref{it:rishon,it:sheini} \\
crefrange\{it:rishon\}\{it:sheini\} = \crefrange{it:rishon}{it:sheini} \\
labelcref\{it:rishon\} = \labelcref{it:rishon}
\end{flushleft}
\begin{flushleft}
autoref\{lem:1\} = \autoref{lem:1} \\
cref\{lem:1\} = \cref{lem:1} \\
Pageref\{lem:1\} = \Pageref{lem:1}
\end{flushleft}
\begin{flushleft}
autoref\{thm:1\} = \autoref{thm:1} \\
cref\{thm:1\} = \cref{thm:1}
\end{flushleft}
\end{document}
答案1
您需要提供说明
\crefname{equation}{equation}{equations}
\crefname{subequation}{equation}{equations}
加载包后cleveref。
对于定理类环境，没有必要这样做，因为它cleveref足够聪明（抱歉，无法抗拒双关语），可以从各种指令中确定theorem、lemma、等环境的“名称”。由于和环境没有这样的设置，因此您需要通过指令提供所需的信息。definition\newtheoremequationsubequation\crefname
MWE：
\documentclass{article} % or: "amsart"
\usepackage{ifthen}
\usepackage{amsthm,amsmath} % not required if "amsart" document class is used
% These should be the last two packages to be loaded:
\usepackage [colorlinks] {hyperref}
\usepackage{cleveref}
% Further setup instructions
\crefname{equation}{equation}{equations}
\crefname{subequation}{equation}{equations}
\newtheorem{theorem}{Theorem}[section]
\numberwithin{equation}{section}
% Custom cross-referencing macros
\newcommand \fullref [1]
{
\ifthenelse {\equal{\nameref{#1}}{}}{\cref{#1}}{\cref{#1} (\nameref{#1})}
}
\newcommand \fullrefrange [2]
{\namecrefs{#1}
\ifthenelse {\equal{\nameref{#1}}{}}{\ref{#1}}{\ref{#1} (\nameref{#1})}
to
\ifthenelse {\equal{\nameref{#2}}{}}{\ref{#2}}{\ref{#2} (\nameref{#2})}
}
\newcommand \Pageref [1]
{ \ifthenelse {\equal{\nameref{#1}}{}}
{\cref{#1} on p.~\pageref{#1}}{\cref{#1} (\nameref{#1}) on p.~\pageref{#1}}
}
\newcommand \refrange [2]{\ref{#1} to \ref{2}}
\begin{document}
\setcounter{section}{1}
\begin{theorem}[A theorem] \label{thm:1}
This is a theorem.
\begin{subequations}
\begin{equation}\label{eq:1} \textnormal{first} \end{equation}
\begin{equation}\label{eq:2} \textnormal{second}\end{equation}
\end{subequations}
\end{theorem}
\noindent
\begin{tabular}{@{}ll}
\verb+\crefrange{eq:1}{eq:2}+& \crefrange{eq:1}{eq:2} \\
\verb+\fullref{eq:1}+ & \fullref{eq:1} \\
\verb+\fullrefrange{eq:1}{eq:2}+& \fullrefrange{eq:1}{eq:2}\\
\verb+\labelcref{eq:1}+ & \labelcref{eq:1} \\
\verb+\namecref{eq:1}+ & \namecref{eq:1} \\
\verb+\namecrefs{eq:1}+ & \namecrefs{eq:1} \\
\verb+\nameref{eq:1}+ & \nameref{eq:1}
\end{tabular}
\end{document}