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TikZ 根据节点计算入角/出角

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TikZ 根据节点计算入角/出角

我有两对节点，它们由括号分组，即带有括号修饰的路径。我想从第一个括号向第二个括号画一个箭头，垂直地从相应的括号出发并到达相应的括号。这是我尝试过的：

    \begin{tikzpicture}[x=.45cm,y=.4cm, baseline=(Fb.base),every node/.append style={font=\scriptsize}]
        \node at (0,0) {$L(ts)$};
        \node at (2,0) {$L(tsut)$};
        \node at (4,0) {$L(tu)$};
        \node at (2,1) {$L(t)$};
        \node at (2,-1) {$L(tsu)$};
        \node (Aa) at (6,0) {$L(tsu)$};
        \node (Ab) at (6,1) {$L(ts)$};
        \draw[decoration={brace}, decorate] ($(Aa)+(1,1.4)$) to node(Pa){} ($(Ab)+(1,-1.4)$);
        %
        \node (Ba) at (10,0) {$L(ts)$};
        \node at (12,0) {$L(tsut)$};
        \node at (14,0) {$L(tu)$};
        \node at (12,1) {$L(t)$};
        \node (Bb) at (12,-1) {$L(tsu)$};
        \node at (16,0) {$L(tsu)$};
        \node at (16,1) {$L(ts)$};
        \draw[decoration={brace, mirror}, decorate] ($(Ba)-(1,-.0)$) to node(Pb){} ($(Bb)-(0.7,.3)$);
        \draw[->] (Pa) to[out=0,in=235] (Pb);
    \end{tikzpicture}

最后一条路径draw生成了所需的路径。但是，in角度是手动设置的，但您可以看到它不是垂直的。如何让 TikZ 自动计算所需的角度？

答案1

let你可以用库中的语法来计算calc。我在括号的开始和结束处添加了两个辅助坐标。

在此处输入图片描述

\documentclass[border=5mm]{standalone}
\usepackage{tikz}
\usetikzlibrary{decorations.pathreplacing,calc}
\begin{document}
    \begin{tikzpicture}[x=.45cm,y=.4cm, every node/.append style={font=\scriptsize}]
        \node at (0,0) {$L(ts)$};
        \node at (2,0) {$L(tsut)$};
        \node at (4,0) {$L(tu)$};
        \node at (2,1) {$L(t)$};
        \node at (2,-1) {$L(tsu)$};
        \node (Aa) at (6,0) {$L(tsu)$};
        \node (Ab) at (6,1) {$L(ts)$};
        \draw[decoration={brace}, decorate] ($(Aa)+(1,1.4)$) to node(Pa){} ($(Ab)+(1,-1.4)$);
        %
        \node (Ba) at (10,0) {$L(ts)$};
        \node at (12,0) {$L(tsut)$};
        \node at (14,0) {$L(tu)$};
        \node at (12,1) {$L(t)$};
        \node (Bb) at (12,-1) {$L(tsu)$};
        \node at (16,0) {$L(tsu)$};
        \node at (16,1) {$L(ts)$};
        \draw[decoration={brace, mirror}, decorate] ($(Ba)-(1,-.0)$) coordinate (c1) to node(Pb){} ($(Bb)-(0.7,.3)$) coordinate (c2);
        \draw[->] 
         let
         \p1=(c1),\p2=(c2),\n1={atan2(\y2-\y1,\x2-\x1)}
         in
        (Pa) to[out=0,in=\n1-90] (Pb);
    \end{tikzpicture}
\end{document}

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