请考虑以下示例：
\documentclass[
a4paper,
12pt
]{article}
\usepackage{ragged2e,array}
\usepackage{xfp}
\def\mlr{1.2}
\newcommand*\saenk[1]{\raisebox{\fpeval{-0.5*\mlr}ex}{#1}}
\newcommand*\mc[3]{\multicolumn{#1}{#2}{\saenk{\textbf{#3}}}}
\begin{document}
\begin{center}
\Large
\begin{tabular}{
|>{\RaggedLeft\arraybackslash}m{0.7cm}
|>{\centering\arraybackslash}m{6cm}
|>{\centering\arraybackslash}m{3cm}|
}
\hline \mc{2}{|c}{Opgave} & \mc{1}{|c|}{Facit} \\[\mlr ex]
\hline 1. & $3x - 7 = 2$ & \saenk{$x = 3$} \\[\mlr ex]
\hline 2. & $10 = 7 + x \div 4$ & \saenk{$x = 12$} \\[\mlr ex]
\hline 3. & $2x - 5 = 9$ & \saenk{$x = 7$} \\[\mlr ex]
\hline 4. & $2x + 5 = 3x + 9$ & \saenk{$x = -4$} \\[\mlr ex]
\hline 5. & $7x - 22 = x + 8$ & \saenk{$x = 5$} \\[\mlr ex]
\hline 6. & $24x - 16 = 32$ & \saenk{$x = 2$} \\[\mlr ex]
\hline 7. & $3x + 18 = 12$ & \saenk{$x = -2$} \\[\mlr ex]
\hline 8. & $18 = 2x + 8$ & \saenk{$x = 5$} \\[\mlr ex]
\hline 9. & $3x + 100 = 250$ & \saenk{$x = 50$} \\[\mlr ex]
\hline 10. & $21 = 4x + 9$ & \saenk{$x = 3$} \\[\mlr ex]
\hline 11. & $4x - 10 + 2x = 4x$ & \saenk{$x = 5$} \\[\mlr ex]
\hline 12. & $2x - 5 = 9$ & \saenk{$x = 7$} \\[\mlr ex]
\hline
\end{tabular}
\end{center}
\end{document}
我如何自动对齐第二列和第三列的表达式=？
答案1
以下示例使用列特定的对齐方式，设置升埃夫特H和side 和r右H和s收件箱的一侧=。第一次需要进行两次编译：
\documentclass{article}
\usepackage{ragged2e,array,collcell,eqparbox}
\newcommand*\mc[3]{\multicolumn{#1}{#2}{\textbf{#3}}}
\makeatletter
\def\mycol{}
\newcommand{\processeq}[1]{%
\@processeq#1\relax
\eqmakebox[lhs\mycol][r]{$\lhs$}%
${}={}$%
\eqmakebox[rhs\mycol][l]{$\rhs$}%
}
\def\@processeq$#1=#2$\relax{\def\lhs{#1}\def\rhs{#2}}
\makeatother
\begin{document}
\begin{center}
\Large\renewcommand{\arraystretch}{1.2}%
\begin{tabular}{
|>{\RaggedLeft\arraybackslash}m{0.7cm}
|>{\centering\arraybackslash\def\mycol{left}\collectcell\processeq}m{6cm}<{\endcollectcell}
|>{\centering\arraybackslash\def\mycol{right}\collectcell\processeq}m{3cm}<{\endcollectcell}|
}
\hline \mc{2}{|c}{Opgave} & \mc{1}{|c|}{Facit} \\
\hline 1. & $3x - 7 = 2$ & $x = 3$ \\
\hline 2. & $10 = 7 + x \div 4$ & $x = 12$ \\
\hline 3. & $2x - 5 = 9$ & $x = 7$ \\
\hline 4. & $2x + 5 = 3x + 9$ & $x = -4$ \\
\hline 5. & $7x - 22 = x + 8$ & $x = 5$ \\
\hline 6. & $24x - 16 = 32$ & $x = 2$ \\
\hline 7. & $3x + 18 = 12$ & $x = -2$ \\
\hline 8. & $18 = 2x + 8$ & $x = 5$ \\
\hline 9. & $3x + 100 = 250$ & $x = 50$ \\
\hline 10. & $21 = 4x + 9$ & $x = 3$ \\
\hline 11. & $4x - 10 + 2x = 4x$ & $x = 5$ \\
\hline 12. & $2x - 5 = 9$ & $x = 7$ \\
\hline
\end{tabular}
\end{center}
\end{document}
答案2
array由于该表主要包含数学知识，因此您可以使用来节省一些输入内容。
\documentclass[a4paper,12pt]{article}
\usepackage{ragged2e,array}
\usepackage{xfp,booktabs}
\begin{document}
\Large
\renewcommand{\arraystretch}{1.2}
\setlength{\arraycolsep}{10pt}
\newcommand*\mc[3]{\multicolumn{#1}{#2}{\textbf{#3}}}
\[
\begin{array}{|r|l|l|} \hline
\mc{2}{|c|}{Opgave} & \mc{1}{c|}{Facit}\\ \hline
1. & 3x - 7 = 2 & x = 3 \\ \hline
2. & 10 = 7 + x \div 4 & x = 12 \\ \hline
3. & 2x - 5 = 9 & x = 7 \\ \hline
4. & 2x + 5 = 3x + 9 & x = -4 \\ \hline
5. & 7x - 22 = x + 8 & x = 5 \\ \hline
6. & 24x - 16 = 32 & x = 2 \\ \hline
7. & 3x + 18 = 12 & x = -2 \\ \hline
8. & 18 = 2x + 8 & x = 5 \\ \hline
9. & 3x + 100 = 250 & x = 50 \\ \hline
10. & 21 = 4x + 9 & x = 3 \\ \hline
11. & 4x - 10 + 2x = 4x & x = 5 \\ \hline
12. & 2x - 5 = 9 & x = 7 \\ \hline
\end{array}
\]
\end{document}
答案3
这很简单，但结果确实很难看。诀窍是将其定义=为对齐点。
但是，您可以找到一些简化输入的想法（查看\bigstrut）。
\documentclass[
a4paper,
12pt
]{article}
\usepackage{array}
\newcommand{\bigstrut}{%
\vrule height 1.2\ht\strutbox depth 1.2\dp\strutbox width 0pt
}
\begin{document}
\begin{center}
\newcommand{\equals}{=}
\catcode`==4
\Large
\begin{tabular}{
|>{\bigstrut}r
|>{$}r<{\equals{}$}@{}>{$}l<{$}
|>{$}r<{\equals{}$}@{}>{$}l<{$}|
}
\hline \multicolumn{3}{|c|}{\bfseries Opgave} & \multicolumn{2}{c|}{\bfseries Facit} \\
\hline 1. & 3x - 7 = 2 & x = 3 \\
\hline 2. & 10 = 7 + x \div 4 & x = 12 \\
\hline 3. & 2x - 5 = 9 & x = 7 \\
\hline 4. & 2x + 5 = 3x + 9 & x = -4 \\
\hline 5. & 7x - 22 = x + 8 & x = 5 \\
\hline 6. & 24x - 16 = 32 & x = 2 \\
\hline 7. & 3x + 18 = 12 & x = -2 \\
\hline 8. & 18 = 2x + 8 & x = 5 \\
\hline 9. & 3x + 100 = 250 & x = 50 \\
\hline 10. & 21 = 4x + 9 & x = 3 \\
\hline 11. & 4x - 10 + 2x = 4x & x = 5 \\
\hline 12. & 2x - 5 = 9 & x = 7 \\
\hline
\end{tabular}
\end{center}
\end{document}
我该如何排版？左对齐，没有垂直线，只有几条水平线。
\documentclass[
a4paper,
12pt
]{article}
\usepackage{array,booktabs}
\begin{document}
\begin{center}
\Large
\begin{tabular}{@{} r >{$}l<{$} @{\qquad} >{$}l<{$} @{}}
\toprule
& \multicolumn{1}{l}{\bfseries Opgave} & \multicolumn{1}{@{}l}{\bfseries Facit} \\
\midrule
1. & 3x - 7 = 2 & x = 3 \\
\addlinespace
2. & 10 = 7 + x \div 4 & x = 12 \\
\addlinespace
3. & 2x - 5 = 9 & x = 7 \\
\addlinespace
4. & 2x + 5 = 3x + 9 & x = -4 \\
\addlinespace
5. & 7x - 22 = x + 8 & x = 5 \\
\addlinespace
6. & 24x - 16 = 32 & x = 2 \\
\addlinespace
7. & 3x + 18 = 12 & x = -2 \\
\addlinespace
8. & 18 = 2x + 8 & x = 5 \\
\addlinespace
9. & 3x + 100 = 250 & x = 50 \\
\addlinespace
10. & 21 = 4x + 9 & x = 3 \\
\addlinespace
11. & 4x - 10 + 2x = 4x & x = 5 \\
\addlinespace
12. & 2x - 5 = 9 & x = 7 \\
\bottomrule
\end{tabular}
\end{center}
\end{document}
