\begin{multicols}{2}
\begin{align*}
Q_1&=Size\;\;of\;\;\left({\frac{N}{4}}\right)\;\;{th}\;item\\
&=Size\;\;of\;\;{\frac{200}{4}}\;\;{th}\;item\\
&=Size\;\;of\;\;50^{th}\;item
\end{align*}
$\therefore Q_1$ lies in the class $35-37$.
\begin{align*}
Q_1&= L + \frac{\frac{N}{4} - c.f}{f} \times i\\
L&=35,\;\;N/4=50,\;\;c.f=14,\;\;f=62,\;\;i=2\\
Q_1&=35+\frac{50-14}{62}\times 2=35+1.16=36.16
\end{align*}
\begin{align*}
Q_3&=Size\;\;of\;\;3\left(\frac{N}{4}\right)\;\;{th}\;item\\
&=Size\;\;of\;\;{\frac{3\times 200}{4}}\;\;{th}\;item\\
&=Size\;\;of\;\;150^{th}\;item
\end{align*}
$\therefore Q_3$ lies in the class $38-40$.
\begin{align*}
Q_3&= L + \frac{\frac{3N}{4} - c.f}{f} \times i\\
L&=38,\;\;3N/4=150,\;\;c.f=76,\;\;f=99,\;\;i=2\\
Q_3&=38+\frac{150-76}{99}\times 2=38+1.49=39.49
\end{align*}
\end{multicols}
答案1
我认为你在滥用multicols
环境 - 不要这样做!更好的解决方案是创建两个并排的minipage
环境,每个环境的宽度为0.5\textwidth
,并且每个环境都包含一个align*
环境。
另外,请熟悉包\text
的宏amsmath
;它用于在方程式中排版非数学材料的片段。
\documentclass{article}
\usepackage{amsmath,amssymb,geometry}
\begin{document}
\noindent
\begin{minipage}{0.5\textwidth}
\begin{align*}
Q_1&=\text{Size of $(N/4)$\textsuperscript{th} item}\\
&=\text{Size of $(200/4)$\textsuperscript{th} item}\\
&=\text{Size of 50\textsuperscript{th} item}\\
\intertext{$\therefore Q_1$ lies in the class 35--37.}
Q_1&= L + \frac{N/4 - c\cdot f}{f} \times i\\
L&=35,\ N/4=50,\ c\cdot f=14,\ f=62,\ i=2\\
Q_1&=35+\frac{50-14}{62}\times 2=35+1.16=36.16
\end{align*}
\end{minipage}% % no whitespace between the "minipage" environments
\begin{minipage}{0.5\textwidth}
\begin{align*}
Q_3&=\text{Size of $(3N/4)$\textsuperscript{th} item}\\
&=\text{Size of $(3\cdot 200/4)$\textsuperscript{th} item}\\
&=\text{Size of 150\textsuperscript{th} item}\\
\intertext{$\therefore Q_3$ lies in the class 38--40.}
Q_3&= L + \frac{3N/4 - c\cdot f}{f} \times i\\
L&=38,\ 3N/4=150,\ c\cdot f=76,\ f=99,\ i=2\\
Q_3&=38+\frac{150-76}{99}\times 2=38+1.49=39.49
\end{align*}
\end{minipage}
\end{document}