分割和对齐内的对齐

Question

我希望(Kollo Skewness)与右侧对齐(Row Sums)，同时(Orthogonality)保持(4.16)在第三行和第四行之间。

这是我的代码

\begin{align} 
    &\mathbf{L}_{mn}'\mathbf{L}_{mn}  = m \mathbf{I}_n & \text{(Orthogonality)}\\
    &\mathbf{1}_m^{'} \mathbf{L}_{mn}  = \mathbf{0}'_n & \text{(Row Sums)} \\
    \begin{split} \label{eq:kollo:b}
        &\mathbf{b} = m^{-1} \left[ s_1 \mathbf{c}_1 + \dots + s_m \mathbf{c}_m  \right]  \text{(Kollo skewness)}\\
        &\text{where} \quad s_k = \left(c_{1k} + \dots + c_{nk}  \right)^2 = \left( \mathbf{1}' \mathbf{c}_k \right)^2 
    \end{split}
\end{align}

这个问题可能在其他地方也得到解答了。如果是这样，请告诉我那里。我找不到它。

这是一个最小示例

\documentclass[12pt,a4paper]{report}
\usepackage{amsmath,amsfonts,amsthm}
\setlength{\topmargin}{1.5cm}
\setlength{\headheight}{15pt}
\setlength{\headsep}{20pt}
\setlength{\topskip}{12pt}
\setlength{\evensidemargin}{0pt}
\setlength{\oddsidemargin}{0pt}
\setlength{\textheight}{240mm}
\setlength{\textwidth}{160mm}
\setlength{\voffset}{-2cm}
\setlength{\parindent}{0pt}
\setlength{\parskip}{6pt}


\begin{document}
\begin{align} 
    &\mathbf{L}_{mn}'\mathbf{L}_{mn}  = m \mathbf{I}_n & \text{(Orthogonality)}\\
    &\mathbf{1}_m^{'} \mathbf{L}_{mn}  = \mathbf{0}'_n & \text{(Row Sums)} \\
    \begin{split} \label{eq:kollo:b}
        &\mathbf{b} = m^{-1} \left[ s_1 \mathbf{c}_1 + \dots + s_m \mathbf{c}_m  \right]  \text{(Kollo skewness)}\\
        &\text{where} \quad s_k = \left(c_{1k} + \dots + c_{nk}  \right)^2 = \left( \mathbf{1}' \mathbf{c}_k \right)^2 
    \end{split}
\end{align}
\end{document}

Answer 1

这里有两种不同的可能对齐方式，用aligned而不是split：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[T1]{fontenc}
\usepackage{fourier}
\usepackage{mathtools}
\usepackage{cleveref}

\begin{document}

\begin{align}
    &\mathbf{L}_{mn}'\mathbf{L}_{mn} = m \mathbf{I}_n & \text{(Orthogonality)}\\
    &\mathbf{1}_m^{'} \mathbf{L}_{mn} = \mathbf{0}'_n & \text{(Row Sums)} \\
     & \begin{aligned}[t] \label{eq:kollo:b}
        &\mathbf{b} = m^{-1} \left[ s_1 \mathbf{c}_1 + \dots + s_m \mathbf{c}_m \right]\\
        &\quad\text{where} \quad s_k = \left(c_{1k} + \dots + c_{nk} \right)^2 = \left( \mathbf{1}' \mathbf{c}_k \right)^2
    \end{aligned} & \text{(Kollo skewness)}
\end{align}

\Cref{eq:kollo:b}

\begin{align}
    &\mathbf{L}_{mn}'\mathbf{L}_{mn} = m \mathbf{I}_n & & \text{(Orthogonality)}\\
    &\mathbf{1}_m^{'} \mathbf{L}_{mn} = \mathbf{0}'_n & & \text{(Row Sums)} \\
     & \begin{aligned}[t] \label{eq:kollo:c}
        &\mathbf{b} = m^{-1} \left[ s_1 \mathbf{c}_1 + \dots + s_m \mathbf{c}_m \right]\\
        &\quad\text{where} \quad s_k = \left(c_{1k} + \dots + c_{nk} \right)^2 = \left( \mathbf{1}' \mathbf{c}_k \right)^2
    \end{aligned} & & \text{(Kollo skewness)}
\end{align}

\end{document} 

Answer 2

从 Bernard 的回答中，我看到他如何将 & 放在嵌套之外，这aligned对我也有同样的效果split。这样我的第二个要求，即在第 3 行和第 4 行之间进行编号仍然得到满足。

\begin{align} 
    &\mathbf{L}_{mn}'\mathbf{L}_{mn}  = m \mathbf{I}_n & \text{(Orthogonoalitly)}\\
    &\mathbf{1}_m^{'} \mathbf{L}_{mn}  = \mathbf{0}'_n & \text{(Row Sums)} \\
    \begin{split} \label{eq:kollo:b}
        &\mathbf{b} = m^{-1} \left[ s_1 \mathbf{c}_1 + \dots + s_m \mathbf{c}_m  \right]  \\
        &\quad \text{where} \quad s_k = \left(c_{1k} + \dots + c_{nk}  \right)^2 = \left( \mathbf{1}' \mathbf{c}_k \right)^2 
    \end{split} & \text{(Kollo skewness)}
\end{align}