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旧答案

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旧答案

我正在尝试绘制一个类似于这个的图形Warrington, GS (2005). 概率的杂耍. 美国数学月刊, 112(2), 105-118，使用 LaTeX 中的 TiKz 包

一只忙碌的猫

我知道如何创建矩形作为节点，并用箭头连接节点。但是，我不知道如何在节点内绘制白色和黑色圆圈。这是我的一些代码：

\begin{figure}
\begin{center}
\begin{tikzpicture}[scale=2.5,->,>=stealth',shorten >=1pt,auto,inner sep=2pt,semithick,bend angle=20]
    \node[rectangle,draw] (A) at (0,0)  {Rectangle};
    \node[rectangle,draw] (B) at (1,0)  {Rectangle};    
    \node[rectangle,draw] (C) at (2,0)  {Rectangle};
    \node[rectangle,draw] (D) at (3,0)  {Rectangle};
    \node[rectangle,draw] (E) at (4,0)  {Rectangle};
    \path (A) edge [bend right,looseness=0.9] node[swap] {$1$}            (B)
          (B) edge [bend right,looseness=0.9] node[swap] {$\dfrac{1}{4}$} (A)
              edge [bend right,looseness=0.9] node[swap] {$\dfrac{3}{4}$} (C)
          (C) edge [bend right,looseness=0.9] node[swap] {$\dfrac{1}{2}$} (B)
              edge [bend right,looseness=0.9] node[swap] {$\dfrac{1}{2}$} (D)
          (D) edge [bend right,looseness=0.9] node[swap] {$\dfrac{3}{4}$} (C)
              edge [bend right,looseness=0.9] node[swap] {$\dfrac{1}{4}$} (E)
          (E) edge [bend right,looseness=0.9] node[swap] {$1$}            (D);
  \end{tikzpicture}
  \caption{Transition}
  \end{center}
  \end{figure}

答案1

这里有一个可能的解决方案，其中包含一些tabular节点文本：

\documentclass{article}
\usepackage{amsmath}
\usepackage{array}
\newcolumntype{C}{>{$}c<{$}}
\usepackage{tikz}
\usetikzlibrary{arrows.meta, positioning}
\tikzset{
    mynode/.style ={
        draw,
        rectangle,
        scale=.5
    },
    mydescr/.style={
        swap,
        text height=3.6ex,
        text depth=2ex
    },
}

\begin{document}
\begin{figure}
    \centering
        \begin{tikzpicture}[->,>=Stealth,shorten >=1pt,auto,inner sep=2pt,semithick,bend angle=20]
        \node[mynode] (A) {\begin{tabular}{*4C}
            \smile & \bullet & \bullet & \bullet \\
            \end{tabular}};
        \node[mynode, right=of A] (B) {\begin{tabular}{*4C}
            \bullet & \smile & \bullet & \bullet \\
            \end{tabular}};    
        \node[mynode, right=of B] (C) {\begin{tabular}{*4C}
            \bullet & \bullet & \smile & \bullet \\
            \end{tabular}};
        \node[mynode, right=of C] (D) {\begin{tabular}{*4C}
            \bullet & \bullet & \bullet & \smile \\
            \end{tabular}};
        \node[mynode, right=of D] (E)  {\begin{tabular}{*4C}
            \smile & \bullet & \bullet & \bullet \\
            \end{tabular}};
        \path (A) edge [bend right,looseness=0.9] node[mydescr] {$1$}            (B)
        (B) edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{1}{4}$} (A)
        edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{3}{4}$} (C)
        (C) edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{1}{2}$} (B)
        edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{1}{2}$} (D)
        (D) edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{3}{4}$} (C)
        edge [bend right,looseness=0.9] node[mydescr] {$\dfrac{1}{4}$} (E)
        (E) edge [bend right,looseness=0.9] node[mydescr] {$1$}            (D);
        \end{tikzpicture}
        \caption{Transition}
\end{figure}
\end{document}

在此处输入图片描述

答案2

另一种方法是使用\pic。的参数定义pic四个符号中的哪一个不绘制为项目符号。

我还稍微简化了箭头绘制。我没有bend right,looseness=1为每个edge和swap指定每个节点，而是将这些选项添加到 中一次。我添加了库，\path而不是，这样您就可以使用简写。node {foo}quotesedge["foo"]

代码输出

\documentclass[border=10pt]{standalone}
\usepackage{tikz,amsmath} 
\usetikzlibrary{quotes} % to use the "<label>" syntax for to-paths, e.g. (a) to["foo"] (b)
\tikzset{
  juggle/.pic={
     \foreach \x in {1,...,4}
       {
        \ifnum \x=#1
           \draw (\x cm/3-4pt,0) to[bend right] ++(8pt,0);
         \else
            \fill (\x/3,0) circle[radius=2pt];
         \fi
        }
        \node[draw,above right,name=-outline,minimum width=1.6cm,minimum height=5mm] at (0,-0.25) {};
   }
} 

\begin{document}
\begin{tikzpicture}[
  arr/.style={
    -stealth,
    shorten >=3pt,
    shorten <=3pt,
    swap
  }
]
\pic (A) at (0,0) {juggle=1};
\pic (B) at (2,0) {juggle=2};
\pic (C) at (4,0) {juggle=3};
\pic (D) at (6,0) {juggle=4};
\pic (E) at (8,0) {juggle=1};

\path [swap,-stealth,bend right=45] % set looseness here as well, if needed
      (A-outline) edge ["$1$"]            (B-outline)
      (B-outline) edge ["$\dfrac{1}{4}$"] (A-outline)
                  edge ["$\dfrac{3}{4}$"] (C-outline)
      (C-outline) edge ["$\dfrac{1}{2}$"] (B-outline)
                  edge ["$\dfrac{1}{2}$"] (D-outline)
      (D-outline) edge ["$\dfrac{3}{4}$"] (C-outline)
                  edge ["$\dfrac{1}{4}$"] (E-outline)
      (E-outline) edge ["$1$"]            (D-outline);
\end{tikzpicture}
\end{document}

旧答案

代码输出

\documentclass[border=2pt]{standalone}
\usepackage{tikz,amsmath} 
\usetikzlibrary{quotes} % to use the "<label>" syntax for to-paths, e.g. (a) to["foo"] (b)
\tikzset{
  juggle/.pic={
     \foreach \x in {1,...,4}
       {
        \ifnum \x=#1
           \draw (\x cm/2-4pt,0) to[bend right] ++(8pt,0);
         \else
            \fill (\x/2,0) circle[radius=2pt];
         \fi
        }
        \node[draw,above right,name=-outline,minimum width=2cm,minimum height=5mm] at (0.25,-0.25) {};
   }
} 

\begin{document}
\begin{tikzpicture}[
  arr/.style={
    -stealth,
    shorten >=3pt,
    shorten <=3pt,
    swap
  }
]

\pic (A) at (0,0)    {juggle=3};
\pic (B) at (4,0)    {juggle=1};
\pic (C) at (2,1.5)  {juggle=4};
\pic (D) at (2,-1.5) {juggle=2};

\draw [arr] (D-outline) to["1"] (C-outline);
\draw [arr] (A-outline) to["4"] (D-outline);
\draw [arr] (D-outline) to["4"] (B-outline);
\draw [arr] (B-outline) to["0"] (C-outline);
\draw [arr] (A-outline) to["2"] (C-outline);
\draw [arr] (C-outline.south west) to["4"] (A-outline.140);
\draw (C-outline) edge[every loop/.append style={-stealth},loop above,"3"] (C-outline);
\end{tikzpicture}
\end{document}

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