答案1
用 Ti 绘制这个可能最容易钾Z。
\documentclass[a4paper]{article}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\coordinate (O) at (0,0);
\draw[-latex] (O) -- (8,0);
\draw[-latex] (O) -- (0,4);
\coordinate[label=left:$P$] (P) at (1,0.2);
\coordinate[label=right:$Q$] (Q) at (7.5,3.6);
\draw[blue,-latex] (P) -- (Q);
\draw plot[domain=1:7.5,variable=\x] ({1+6.5*(1-cos((\x-1)*(90/6.5)))},
{0.2+3.4*sin((\x-1)*(90/6.5))});
\draw[red,-latex] ({1+6.5*(1-cos((4-1)*(90/6.5)))},
{0.2+3.4*sin((4-1)*(90/6.5)}) --++(2,1.1) node[midway,above,black]{$v$};
\draw[dotted] ({1+6.5*(1-cos((4-1)*(90/6.5)))},
{0.2+3.4*sin((4-1)*(90/6.5)}) -- ++(2,0)-- ++(0,1.1);
\coordinate (v) at (4,3.4);
\draw[dotted] (O-|P)node[below]{$f(a)$} -- (P) -- (O|-P)node[left]{$g(b)$};
\draw[dotted] (O-|Q)node[below]{$f(b)$} --
node[pos=0.3,left]{$\displaystyle \frac{g'(c)}{f'(c)}=
\frac{g(b)-g(a)}{f(b)-f(a)}$} (Q) -- (O|-Q)node[left]{$g(a)$};
\draw[dotted] (O|-P) -- (P-|Q);
\end{tikzpicture}
\end{document}
把这当作一种欢迎礼物,并在发布下一个问题时遵循 Stefan Pinnow 的建议。