如何在不同的环境下保持数字顺序？

Question

在尝试进行如下枚举时，您可以提出一个问题，但接下来，您可以列出一个问题列表，我一直分别使用枚举包和任务包进行水平枚举，但我怎样才能将两者结合起来并保持问题的顺序？

我在想也许可以使用计数器，但我不太确定如何在枚举和任务环境中实现它，如能得到任何帮助我将不胜感激，提前谢谢了。

Answer 1

解决方案是tasks使用resume键。对于跨越一行中剩余列的项目，请使用 命令\task*。对于跨越所有列的项目，请使用\tasks!：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[showframe]{geometry}
\usepackage{amsmath}

\usepackage{tasks}
\settasks{counter-format =tsk[1]., label-format=\bfseries, label-offset=1em, label-width = 0.67em, item-indent = 1.67em, before-skip =0.5ex}

\begin{document}

\begin{tasks}(3)
\task* In section 1.1 we guessed solutions to the exponential growth model $d\mkern1.5mu P/d\mkern1.5mu t = k P$, where $k$ is a constant (see page 6). Using the fact that this equation is separable, derive these solutions by separating variables.\medskip
\end{tasks}
In Exercises 5–24, find the general solution of the differential equation specified. (You may not be able to reach the ideal answer of an equation with only the dependent variable on the left and only the independent variable on the right, but get as far as you can.)

\begin{tasks}[resume](3)
\task $\dfrac{dy}{dt} = ty^2$
\task $\dfrac{dy}{dt} = t^4y$
\task $\dfrac{dy}{dt} = 2y + 1$
\task $\dfrac{dy}{dt} = 2-y$
\task $\dfrac{dy}{dt} = e^{-y}$
\task $\dfrac{dy}{dt} = 1 + x^2$
\end{tasks}

\end{document} 

Answer 2

更新：我意识到我原来的答案有一个缺陷，那就是不能引用项目的编号。这个问题在以下提案中得到了修复，该提案基于这个答案。

\documentclass{article}
\usepackage{paralist}
\usepackage{tabto}
\newcounter{problems}


\makeatletter
\def\zinparaenum{%  
  \ifnum\@enumdepth>\thr@@
    \@toodeep
  \else
    \advance\@enumdepth\@ne
    \edef\@enumctr{enum\romannumeral\the\@enumdepth}%
  \fi
  \@ifnextchar[{\@enumlabel@{\@zinparaenum@}[}{\@zinparaenum@}}
\def\@zinparaenum@{%
  \usecounter{\@enumctr}%
  \@namedef{p@\@enumctr}{}%
  \def\@itemlabel{\csname label\@enumctr\endcsname}%
  \let\@item\pl@item
  \def\makelabel##1{##1}%
  \ignorespaces\setcounter{enumi}{\value{problems}}}
\def\endzinparaenum{\setcounter{problems}{\value{enumi}}\ignorespacesafterend}
\makeatother

\begin{document}

\NumTabs{1}
\begin{zinparaenum}[\bf 1.]
\noindent\item How many marmots live in the Alps?
\end{zinparaenum}

\medskip

In problems \ref{first}--\ref{last} solve the differential equation\dots\\
\NumTabs{3}
\begin{zinparaenum}[\bf 1.]
\item text\label{first}
\tab\item text
\tab\item text
\tab\item text
\tab\item text
\tab\item text   \label{last}
\end{zinparaenum}

\end{document}

这可能更接近你想要的。（我还将数字加粗。）在最好的世界中，我可以将两个答案结合起来，这样你就不必输入 s \tab，但看起来我们并不是生活在最好的世界中。

原始答案：这是基于这个答案。

\documentclass{article}

\setlength{\parindent}{0mm}

\usepackage{paralist}
\usepackage{tabto}
\newcounter{problems}

\newenvironment{tabbedenum}[1]
 {\NumTabs{#1}\inparaenum\let\latexitem\item
 \setcounter{enumi}{\theproblems}
  \def\item{\def\item{\tab\latexitem}\latexitem}}
 {\setcounter{problems}{\theenumi}\endinparaenum}

\begin{document}
\begin{tabbedenum}{1}
\item How many marmots live in Switzerland?
\end{tabbedenum}


\begin{tabbedenum}{3}
\item text
\item text
\item text
\item text
\item text
\item text
\end{tabbedenum}

\end{document}