我需要绘制乳胶中紫杉醇的化学结构式
答案1
紫杉醇:化学结构式。
\documentclass{article}
\usepackage{chemfig}
\begin{document}
\chemfig{
% 1
-[:264.4]% 2
=_[:325.3]% 3
-[:345]% 4
(
<[:52.5]O% 59
-[:112.5]% 60
(
-[:52.5]% 62
)
=[:172.5]O% 61
)
-[:300]% 5
(
=[:7.5]O% 6
)
-[:255]% 7
(
<[:22.5]% 58
)
-[:330]% 8
(
<[:30,,,1]OH% 57
)
-[:270]% 9
>[:210]% 10
-[:150]% 11
(
-[:240]% 51
-[:330]O% 52
-[:60]% -> 10
)
(
<:[:175]O% 53
-[:235]% 54
(
-[:295]% 56
)
=[:175]O% 55
)
>[:90]% 12
(
-[:30]% -> 7
)
-[:165]% 13
(
<:[:232.5]O% 42
-[:172.5]% 43
(
-[:232.5]% 45
=_[:292.5]% 46
-[:232.5]% 47
=_[:172.5]% 48
-[:112.5]% 49
=_[:52.5]% 50
-[:352.5]% -> 45
)
=[:112.5]O% 44
)
-[:120]% 14
(
-[:75]% 15
(
-[:170]% 16
)
(
-[:115]% 17
)
-[:30]% -> 3
)
(
<[:219.8,,,2]HO% 41
)
-[:139.7]% 18
-[:81.6]% 19
(
-[:23.4]% -> 2
)
<:[:142.5]O% 20
-[:202.5]% 21
(
=[:262.5]O% 22
)
-[:142.5]% 23
(
<[:82.5,,,1]OH% 40
)
-[:202.5]% 24
(
-[:142.5]% 25
=_[:202.5]% 26
-[:142.5]% 27
=_[:82.5]% 28
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=_[:322.5]% 30
-[:262.5]% -> 25
)
<[:262.5,,,1]NH% 31
-[:202.5,,1]% 32
(
=[:142.5]O% 33
)
-[:262.5]% 34
=_[:322.5]% 35
-[:262.5]% 36
=_[:202.5]% 37
-[:142.5]% 38
=_[:82.5]% 39
(
-[:22.5]%
)
}
\end{document}