矩阵

Question 1

以下是我对该图的看法。matrix of nodes我使用的是而不是使用nodes multipart。

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning,arrows,shapes.multipart,shapes.geometric,arrows.meta}
\tikzset{multi/.style={
rectangle split,rectangle split horizontal, rectangle split parts=6,align=center,
text width=2cm,
draw=black!15!yellow,
fill=yellow!20}
}
\begin{document}
\begin{tikzpicture}[rounded corners,very thick,-Stealth]
\node(A) [draw=black!15!green,very thick,fill=green!30,minimum height=1cm,rounded corners] {Full Data Set};
\node(B) [multi,below=1cm of A]{%
Middle
\nodepart{two}
Bottom\\Support
\nodepart{three}
Bottom\\Carry
\nodepart{four}
Bottom\\Other
\nodepart{five}
Top
\nodepart{six}
Jungle
};
\node(C)[circle,draw=purple!70!blue,below=1 cm of B,fill=purple!30] {EFA};
\node(D)[multi,below=1cm of C]{%
Middle
\nodepart{two}
Bottom\\Support
\nodepart{three}
Bottom\\Carry
\nodepart{four}
Bottom\\Other
\nodepart{five}
Top
\nodepart{six}
Jungle
};
\node(E)[diamond,draw=purple!70!blue,below=of D,fill=purple!30,sharp corners={}] {L/R};

\foreach \x in {one,two,three,four,five,six}{
\draw(A.south) -- ++(0,-1.5ex) -| (B.\x\space north);
\draw(B.\x\space south) -- ++(0,-4.ex) -| (C.north);
\draw(C.south) -- ++(0,-1.5ex) -| (D.\x\space north);
\draw(D.\x\space south) -- ++(0,-4.ex) -| (E.north);
}
\end{tikzpicture}
\end{document}

Answer

以下是我对该图的看法。matrix of nodes我使用的是而不是使用nodes multipart。

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning,arrows,shapes.multipart,shapes.geometric,arrows.meta}
\tikzset{multi/.style={
rectangle split,rectangle split horizontal, rectangle split parts=6,align=center,
text width=2cm,
draw=black!15!yellow,
fill=yellow!20}
}
\begin{document}
\begin{tikzpicture}[rounded corners,very thick,-Stealth]
\node(A) [draw=black!15!green,very thick,fill=green!30,minimum height=1cm,rounded corners] {Full Data Set};
\node(B) [multi,below=1cm of A]{%
Middle
\nodepart{two}
Bottom\\Support
\nodepart{three}
Bottom\\Carry
\nodepart{four}
Bottom\\Other
\nodepart{five}
Top
\nodepart{six}
Jungle
};
\node(C)[circle,draw=purple!70!blue,below=1 cm of B,fill=purple!30] {EFA};
\node(D)[multi,below=1cm of C]{%
Middle
\nodepart{two}
Bottom\\Support
\nodepart{three}
Bottom\\Carry
\nodepart{four}
Bottom\\Other
\nodepart{five}
Top
\nodepart{six}
Jungle
};
\node(E)[diamond,draw=purple!70!blue,below=of D,fill=purple!30,sharp corners={}] {L/R};

\foreach \x in {one,two,three,four,five,six}{
\draw(A.south) -- ++(0,-1.5ex) -| (B.\x\space north);
\draw(B.\x\space south) -- ++(0,-4.ex) -| (C.north);
\draw(C.south) -- ++(0,-1.5ex) -| (D.\x\space north);
\draw(D.\x\space south) -- ++(0,-4.ex) -| (E.north);
}
\end{tikzpicture}
\end{document}

Question 2

这不是一棵树。因此，选择forest它作为绘制它的方法并不一定是明智的。如果只涉及与树的轻微偏差，forest则可以很有意义。但是此图涉及的偏差多于非偏差，因此forest不是最佳选择。

尽管如此，如果您出于某种原因确实希望使用该包来绘制非树，我肯定会尝试forest在一张图片中使用的功能来完成此操作。

我提出两种解决方案。第一种使用matrix of nodes。第二种使用forest。

矩阵

这个想法是使用矩阵绘制黄色框，然后使用这些节点自动获得的名称来放置其余三个节点。由于矩阵的节点以系统方式自动命名，因此很容易循环并绘制箭头。

\documentclass[border=10pt]{standalone}
\usepackage{tikz}
\usetikzlibrary{arrows.meta, positioning, matrix, shapes.geometric}
\begin{document}
\begin{tikzpicture}[thick, >/.tip=Stealth, my node/.style={font=\sffamily, draw,  fill=#1!15, thick}]
  \matrix (m) [matrix of nodes, every node/.append style={my node=yellow, minimum height=7ex, anchor=center, text centered, text width=15mm}]
  {
    Middle & Bottom support & Bottom carry & Bottom other & Top & Jungle \\[15ex]
    Middle & Bottom support & Bottom carry & Bottom other & Top & Jungle \\
  } ;
  \node (r) [above=7.5ex of  m-1-3.north east, anchor=center, my node=green] {Full data set};
  \node (e) [above= 7.5ex of m-2-3.north east, anchor=center, my node=red, circle] {EPA};
  \node (t) [below= 7.5ex of m-2-3.south east, anchor=center, my node=red, diamond] {LR};
  \begin{scope}[rounded corners, ->]
    \foreach \i in {1,...,6} {
      \draw (r.south) -- ++(0,-1.5ex) -| (m-1-\i.north);
      \draw (e.south) -- ++(0,-1.5ex) -| (m-2-\i.north);
      \draw (m-1-\i.south) -- ++(0,-1.5ex) -| (e.north); 
      \draw (m-2-\i.south) -- ++(0,-1.5ex) -| (t.north); 
    }
  \end{scope}
\end{tikzpicture}
\end{document}

森林

在这种情况下，黄色层是重复的，因此，如果不使用的forest功能将树的片段从一个地方复制到另一个地方，那就太可惜了。repeat aunts是一种将节点的所有姑母重复为该节点的子节点的样式。join aunts将节点连接到其所有姑母。not a tree只是设置树的样式：按级别着色等等。我只是不知道该怎么称呼它，所以就这样not a tree称呼了。

结果是

\begin{forest}
  not a tree,
  [Full data set
    [Middle]
    [Bottom\\support]
    [Bottom\\carry]
    [
      [EPA, repeat aunts, join aunts [ [LR, join aunts]]]
    ]
    [Bottom\\other]
    [Top]
    [Jungle]
  ]
\end{forest}

产生以下非树结果

完整代码：

\documentclass[border=10pt]{standalone}
\usepackage[edges]{forest}
\usetikzlibrary{arrows.meta}
\forestset{
  declare keylist={copy list a}{},
  declare keylist={copy list b}{},
  declare keylist={join list}{},
  not a tree/.style={
    forked edges,
    for tree={
      edge+={thick, rounded corners, -Stealth},
      thick,
      draw,
      font=\sffamily,
      align=c, 
      parent anchor=children,
      child anchor=parent,
      anchor=parent,
      l sep'+=10pt,
      fork sep'+=5pt,
    },
    where level=0{fill=green}{ if={> O_= {!u.n children}{1}} {fill=pink, circle}{fill=yellow}, },
    delay={ where content={}{phantom, before computing xy={tempdima/.min={>O{min y}}{siblings},  l-/.register=tempdima }}{} },
  },
  repeat aunts/.style={
    before typesetting nodes={tempkeylista'=, tempkeylistb'=, for nodewalk={fake=u,siblings}{%append={[, phantom]},
        if={ > OOw+n< {n}{!u.n children}{(##1+1)/2}}{ tempkeylista/.option=name }{ tempkeylistb/.option=name }
      }, copy list a/.register=tempkeylista, copy list b/.register=tempkeylistb, split option={copy list a}{,}{prepend'}, split option={copy list b}{,}{append'} }
  },
  join aunts/.style={
    before drawing tree={
      tempkeylista'=,
      for nodewalk={fake=u, siblings}{tempkeylista/.option=name},
      join list/.register=tempkeylista,
      tikz+/.process={ OOw2 {join list} {fork sep} { \draw  [thick, rounded corners, Stealth-]\foreach \i in {##1} { (.child anchor) -- ++(0,##2) -| (\i.parent anchor) }; } },
    }
  }
}
\begin{document}
\begin{forest}
  not a tree,
  [Full data set
    [Middle]
    [Bottom\\support]
    [Bottom\\carry]
    [
      [EPA, repeat aunts, join aunts [,  phantom[LR, join aunts]]]
    ]
    [Bottom\\other]
    [Top]
    [Jungle]
  ]
\end{forest}
\end{document}

Answer