如何创建两个箭头断裂？

Question

我试图在两处断线，以实现这样的目标：

示例中的断点是圆形的，但这就是我的想法。我有以下代码，它只生成一个断点：

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{automata,positioning,arrows,arrows.meta,shapes,decorations.pathreplacing,fit,calc}
\usetikzlibrary{automata,positioning,arrows,shapes,decorations.pathreplacing,fit,calc}
\usetikzlibrary{angles,quotes}
\usetikzlibrary{decorations.pathreplacing,calc}  

\begin{document}

% Define block styles
\tikzstyle{decision} = [diamond, draw,  
    text width=4.8em, text centered, node distance=2cm, inner sep=0pt]
\tikzstyle{block} = [rectangle, draw,  
    text width=7em, text centered, rounded corners, minimum height=2em]
\tikzstyle{arrow} = [draw, -latex']
\tikzstyle{line} = [draw]
\tikzstyle{invisible4} = [rectangle]
\tikzstyle{invisible5} = [rectangle]
\tikzstyle{circular} = [draw, circle, radius=1.0cm,]

\begin{figure}[h]
    \centering
    \begin{tikzpicture}[node distance = 2cm, auto, scale=1.0]
        \node [block] (pulse) {\small P};
        \node [invisible4, below of=pulse] (aux2) {};
        \node [block, left of=aux2] (fp) {\small FP};
        \node [block, right of=aux2] (rp) {\small FP};
        \node [circular, below of=aux2] (minus) {\small -};
        \node [decision, below of=minus] (threshold) {\small $\le T$ ?};
        \node [invisible4, below of=threshold] (aux3) {};
        \node [block, left of=aux3] (fp2) {\small FP};
        \node [block, right of=aux3] (rp2) {\small RP};
        \node [invisible4, below of=aux3, node distance=1.0cm] (aux) {};
        \node [invisible5, draw=none, below of=aux, node distance=1.0cm] (aux4) {};

        \path [arrow] (pulse) |- (fp);
        \path [arrow] (pulse) |- (rp);
        \path [arrow] (fp) |- (minus);
        \path [arrow] (rp) |- (minus);
        \path [arrow] (minus) -- (threshold);
        \path [arrow] (threshold) -| node [above, near start] {yes} (fp2);
        \path [arrow] (threshold) -| node [near start] {no} (rp2);
        \path [line] (fp2) |- (aux);
        \path [line] (rp2) |- (aux);

    \end{tikzpicture}
\end{figure}

\end{document}

此代码生成此图：

我试图在连接 P 和 FP、P 和 RP 的箭头中创建两个断点，以及从底部连接并指向下方的 FP 和 RP 的箭头。我试图在它们之间创建一个辅助的不可见节点，但这个节点仍然占据空间（在图像中可以看到，线条之间的间隙）。

我怎样才能打破这些界限？

谢谢你！

Answer 1

选择中间的一个点并再次“断开”。rounded corners如果您不想要尖角，请使用选项。

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{shapes,calc,arrows}

\begin{document}
% Define block styles
\tikzstyle{decision} = [diamond, draw,  
    text width=4.8em, text centered, node distance=2cm, inner sep=0pt]
\tikzstyle{block} = [rectangle, draw,  
    text width=7em, text centered, rounded corners, minimum height=2em]
\tikzstyle{arrow} = [draw, -latex',rounded corners]
\tikzstyle{line} = [draw]
\tikzstyle{invisible4} = [rectangle]
\tikzstyle{invisible5} = [rectangle]
\tikzstyle{circular} = [draw, circle, radius=1.0cm,]

\begin{figure}[h]
    \centering
    \begin{tikzpicture}[node distance = 2cm, auto, scale=1.0]
        \node [block] (pulse) {\small P};
        \node [invisible4, below of=pulse] (aux2) {};
        \node [block, left of=aux2] (fp) {\small FP};
        \node [block, right of=aux2] (rp) {\small FP};
        \node [circular, below of=aux2] (minus) {\small -};
        \node [decision, below of=minus] (threshold) {\small $\le T$ ?};
        \node [invisible4, below of=threshold] (aux3) {};
        \node [block, left of=aux3] (fp2) {\small FP};
        \node [block, right of=aux3] (rp2) {\small RP};
        \node [invisible4, below of=aux3, node distance=1.0cm] (aux) {};
        \node [invisible5, draw=none, below of=aux, node distance=1.0cm] (aux4) {};

        \path [arrow] (pulse) |- ($(pulse)+(0,-1)$) -| (fp);
        \path [arrow] (pulse) |- ($(pulse)+(0,-1)$) -|  (rp);
        \path [arrow] (fp) |- (minus);
        \path [arrow] (rp) |- (minus);
        \path [arrow] (minus) -- (threshold);
        \path [arrow] (threshold) -| node [above, near start] {yes} (fp2);
        \path [arrow] (threshold) -| node [near start] {no} (rp2);
        \path [line] (fp2) |- (aux);
        \path [line] (rp2) |- (aux);

    \end{tikzpicture}
\end{figure}

\end{document}