使用 \foreach 绘制网格线

Question

我正在尝试在正方形内绘制网格线。这是我的代码：

\documentclass{article}
\usepackage{pgfplots}
\pgfplotsset{compat=1.15}

\begin{document}

\begin{figure}[ht]

\centering

\begin{tikzpicture}[scale=1.25,line width=1pt]
\begin{axis}[
color= white,
xmin=-28.9, 
xmax=28.9, 
ymin=-28.9, 
ymax=28.9, 
axis equal image, 
axis lines=middle,
]

\foreach \x in {-24,..., 24}
    {\draw[thin, gray] (\x,-24) -- (\x,24);}

\draw[black, thin] (-24,-24) -- (-24,24) -- (24,24) -- (24, -24) -- 
(-24,-24);

\node[black, below] at (24,-24) {$(1,0)$};

\node[black, below] at (-24,-24) {$(0,0)$};

\node[black, above] at (-24,24) {$(0,1)$};

\node[black, above] at (24,24) {$(1,1)$};

\end{axis}
\end{tikzpicture}

\end{figure}

\end{document}

但是，此代码无法编译。我的目标是制作一个 24 x 24 网格的正方形。

Answer 1

\pgfplotsinvokeforeach如果您使用而不是，则可以正常工作\foreach：

笔记：

• 我建议您尝试和grid内置的选项。pgfplotstikz
• 您显示的所有代码都不需要，pgfplots因此您可以消除axis环境。因此，除非有其他功能未在 MWE 中显示，否则您应该考虑axis使用 的非环境版本\foreach。

参考：

• \foreach 在轴环境中不起作用
• Tikz foreach 循环和坐标计算。

代码：pgfplots

\documentclass{article}
\usepackage{pgfplots}
\pgfplotsset{compat=1.15}

\begin{document}
%
%\begin{figure}[ht]
%
%\centering
%
\begin{tikzpicture}%[scale=1.25,line width=1pt]
\begin{axis}[
    color= white,
    xmin=-28.9, 
    xmax=28.9, 
    ymin=-28.9, 
    ymax=28.9, 
    axis equal image, 
    axis lines=middle,
]

\pgfplotsinvokeforeach {-24,...,24} {%
    \draw[thin, gray] (#1,-24) -- (#1,24);
}

\draw[black, thin] (-24,-24) -- (-24,24) -- (24,24) -- (24, -24) -- 
(-24,-24);

\node[black, below] at (24,-24) {$(1,0)$};

\node[black, below] at (-24,-24) {$(0,0)$};

\node[black, above] at (-24,24) {$(0,1)$};

\node[black, above] at (24,24) {$(1,1)$};

\end{axis}
\end{tikzpicture}%
%
%\end{figure}
%
\end{document}

代碼： 沒有pgfplots

\documentclass{article}
\usepackage{pgfplots}
\pgfplotsset{compat=1.15}

\begin{document}
\begin{tikzpicture}[scale=0.10]

\foreach \x in  {-24,...,24} {%
    \draw[thin, gray] (\x,-24) -- (\x,24);
}

\draw[black, thin] (-24,-24) -- (-24,24) -- (24,24) -- (24, -24) -- 
(-24,-24);

\node[black, below] at (24,-24) {$(1,0)$};

\node[black, below] at (-24,-24) {$(0,0)$};

\node[black, above] at (-24,24) {$(0,1)$};

\node[black, above] at (24,24) {$(1,1)$};

\end{tikzpicture}%
\end{document}

Answer 2

另外两个选项没有pgfplots，一个没有foreach，一个有foreach：

\documentclass[tikz,border=2mm]{standalone} 
\usetikzlibrary{positioning}

\begin{document}
\begin{tikzpicture}
\draw (0,0) grid (24,24);
\node[above right] at (24,24) {$(1,1)$};
\node[above left] at (0,24) {$(0,1)$};
\node[below left] at (0,0) {$(0,0)$};
\node[below right] at (24,0) {$(1,0)$};
\end{tikzpicture}

\begin{tikzpicture}
\foreach \i in {0,...,24}{
    \draw (\i,0) -- ++(90:24);
    \draw (0,\i) -- ++(0:24);
}
\node[above right] at (24,24) {$(1,1)$};
\node[above left] at (0,24) {$(0,1)$};
\node[below left] at (0,0) {$(0,0)$};
\node[below right] at (24,0) {$(1,0)$};
\end{tikzpicture}

\end{document}