我想要创建的图表的一个示例是：
我可以使用以下 tikz 接近所需的输出：
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{intersections,shapes,arrows.meta,positioning}
\SetSymbolFont{letters}{bold}{OML}{cmbr}{bx}{it}
\renewcommand{\familydefault}{\sfdefault}
\begin{document}
\pagestyle{empty}
\begin{tikzpicture}[
line width=1.0pt
, node distance=3cm
, defblk/.style = {draw, rectangle, draw=black, minimum height=8cm, minimum width=1cm}
]
\node[defblk, align=center](a){Block A};
\node[defblk, right=of a](b){Block B};
\draw[->] ([yshift=0 * -1cm]a.north east) -- node[above]{Signal 1} ([yshift=0 * -1cm]b.north west) ;
\draw[->] ([yshift=1 * -1cm]a.north east) -- node[above]{Signal 2} ([yshift=1 * -1cm]b.north west) ;
\draw[<-] ([yshift=2 * -1cm]a.north east) -- node[above]{Signal 3} ([yshift=2 * -1cm]b.north west) ;
\draw[<-] ([yshift=4 * -1cm]a.north east) -- node[above]{Signal 4}([yshift=4 * -1cm]b.north west) ;
\draw[<-] ([yshift=5 * -1cm]a.north east) -- node[above]{Signal 5}([yshift=5 * -1cm]b.north west) ;
\end{tikzpicture}
\end{document}
这是一个相当手动的过程，但重新安排连接需要我重新输入所有不同的偏移量。我想要做的是能够以以下方式逐步指定节点：
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{intersections,shapes,arrows.meta,positioning}
\SetSymbolFont{letters}{bold}{OML}{cmbr}{bx}{it}
\renewcommand{\familydefault}{\sfdefault}
\begin{document}
\pagestyle{empty}
\begin{tikzpicture}[
line width=1.0pt
, node distance=3cm
, defblk/.style = {draw, rectangle, draw=black, minimum height=8cm, minimum width=1cm}
]
\node[defblk, align=center](a){Block A};
\node[defblk, right=of a](b){Block B};
% This syntax below is pseudo-code that expresses how
% I'd like to incrementally specify paths
\draw (a.north east)
node[above, ->](sig1){Signal 1} -- ((sig1) -| (b.west))
++(0, -1cm) node[above, ->](sig2){Signal 2} -- ((sig2) -| (b.west))
++(0, -1cm) node[above, <-](sig3){Signal 3} -- ((sig3) -| (b.west))
++(0, -1cm)
++(0, -1cm) node[above, <-](sig4){Signal 4} -- ((sig4) -| (b.west))
++(0, -1cm) node[above, <-](sig5){Signal 5} -- ((sig5) -| (b.west));
\end{tikzpicture}
\end{document}
后
根据@marmot，带有 [count=\Z] 选项的 \foreach 循环实现了我想要的效果。下面包含一个更详细的示例：
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\SetSymbolFont{letters}{bold}{OML}{cmbr}{bx}{it}
\renewcommand{\familydefault}{\sfdefault}
\begin{document}
\pagestyle{empty}
\begin{tikzpicture}[
line width=1.0pt
, node distance=3cm
, rightof/.style = {right=of #1.north east, anchor=north west}
, defblk/.style = {draw, rectangle, draw=black, minimum height=8cm, minimum width=1cm}
, sig/.style = {above right, text width=2cm, align=left, black}
, lvds/.style = {blue!80}
, lvcmos/.style = {black}
]
\node[defblk, align=center](a){Block A};
\node[defblk, right=of a](b){Block B};
\foreach \dir/\type/\name [count=\Z] in {
->/lvds/din clk
,->/lvds/din data
,->/lvds/din en
,->/lvds/din sync
,<-/lvds/din interrupt
,white//{}
,<-/lvds/dout clk
,<-/lvds/dout data
,<-/lvds/dout en
,white//{}
,<-/lvcmos/ctrl clk
,<-/lvcmos/ctrl data
,<-/lvcmos/ctrl en
}
{
\def\ioff{-1em}
\def\ispc{-1.5em}
\draw[\dir, \type] ([yshift=\ioff + \Z*\ispc]a.north east)
node[sig]{\name}
--
([yshift=\ioff + \Z*\ispc]b.north west);
}
\end{tikzpicture}
\end{document}
答案1
欢迎使用 TeX.SE！缩短代码的一种方法是使用循环。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning}
\SetSymbolFont{letters}{bold}{OML}{cmbr}{bx}{it}
\renewcommand{\familydefault}{\sfdefault}
\begin{document}
\pagestyle{empty}
\begin{tikzpicture}[
line width=1.0pt
, node distance=3cm
, defblk/.style = {draw, rectangle, draw=black, minimum height=8cm, minimum width=1cm}
]
\node[defblk, align=center](a){Block A};
\node[defblk, right=of a](b){Block B};
\foreach \X/\Y [count=\Z] in {->/0,->/1,<-/2,<-/4,<-/5}
{\draw[\X] ([yshift=\Y * -1cm]a.north east) -- node[above]{Signal \Z}
([yshift=\Y * -1cm]b.north west);}
\end{tikzpicture}
\end{document}
答案2
呵呵，@marmot 打败了我四分钟......想法是一样的，但实现方式略有不同......
\documentclass[tikz, margin=3mm]{standalone}
\usetikzlibrary{arrows.meta, positioning, quotes}
\renewcommand{\familydefault}{\sfdefault}
\begin{document}
\begin{tikzpicture}[
node distance = 5mm and 30mm,
line width = 1.0pt,
> = Stealth,
defblk/.style = {rectangle, draw=black,
minimum height=4cm, minimum width=1cm,
outer sep=0pt},
sy/.style = {yshift=#1 mm},
every edge quotes/.style = {anchor=south,inner sep=1pt, font=\footnotesize}
]
\node[defblk] (a) {Block A};
\node[defblk, right=of a] (b) {Block B};
%
\coordinate[below=of a.north east] (sig1);
\foreach \i [count=\j] in {0,1,2, 4,5}
{\ifnum\j<3
\draw[->] ([sy=-\i*5] sig1) to ["Signal \j"] ([sy=-\i*5] sig1 -| b.west)
\else
\draw[<-] ([sy=-\i*5] sig1) to ["Signal \j"] ([sy=-\i*5] sig1 -| b.west)
\fi;
}
\end{tikzpicture}
\end{document}
