在我之前的一个答案，我的第一个建议
\documentclass[tikz]{standalone}
\usetikzlibrary{quotes,angles}
\begin{document}
\begin{tikzpicture}
\draw (0,-4)--(0,4) node[above] {$Im$} (-4,0)--(4,0) node[right] {$Re$};
\draw[dashed] (0,0) circle (3) circle (2);
\coordinate (a) at (80:3);
\coordinate (b) at (3,0);
\coordinate (m) at (25:2);
\coordinate (n) at (-95:2);
\coordinate (p) at (145:2);
\coordinate (o) at (0,0);
\fill[black] (a) circle (2pt) (b) circle (2pt) (m) circle (2pt) (n) circle (2pt) (p) circle (2pt) (2,0) circle (2pt);
\draw (a) node[above right] {$z=|z|e^{i\theta}$};
\draw (b) node[below] {$|z|$};
\draw (2,0) node[below] {$|z|^{1/3}$};
\draw (m) node[right] {$|z|^{1/3}e^{i\theta/3}$};
\draw (n) node[below] {$|z|^{1/3}e^{i(\theta+4\pi)/3}$};
\draw (p) node[above] {$|z|^{1/3}e^{i(\theta+2\pi)/3}$};
\draw (.1,1.5)--(0,1.5) node[left] {$i$};
\draw (1.5,.1)--(1.5,0) node[below] {$1$};
\draw (0,0)--(a) (0,0)--(m) (0,0)--(n) (0,0)--(p);
\draw[dashed] (m)--(n)--(p)--cycle;
\pic[draw,dashed,thick,"$\theta$",angle radius=0.8cm,angle eccentricity=1.3] {angle=b--o--a};
\end{tikzpicture}
\end{document}
给出这个输出
发现读取某些节点有点困难（例如|是| 1/3埃我（θ+ 2π)/3一），我重新定义inner sep并设置fill节点的颜色。最终我得到
\documentclass[tikz]{standalone}
\usetikzlibrary{quotes,angles,positioning}
\begin{document}
\begin{tikzpicture}
\begin{scope}[every node/.style={fill=white,inner sep=2pt}]
\draw (0,-4)--(0,4) node[above] {$\Im$} (-4,0)--(4,0) node[right] {$\Re$};
\draw[dashed] (0,0) circle (3) circle (2);
\coordinate (a) at (80:3);
\coordinate (b) at (3,0);
\coordinate (m) at (80/3:2);
\coordinate (n) at ({80/3-120}:2);
\coordinate (p) at ({80/3+120}:2);
\coordinate (o) at (0,0);
\draw (a) node[above right] {$z=|z|e^{i\theta}$};
\draw (b) node[below right] {$|z|$};
\draw (2,0) node[below left=0cm and -2em] {$|z|^{1/3}$};
\draw (m) node[right] {$|z|^{1/3}e^{i\theta/3}$};
\draw (n) node[below] {$|z|^{1/3}e^{i(\theta+4\pi)/3}$};
\draw (p) node[above] {$|z|^{1/3}e^{i(\theta+2\pi)/3}$};
\draw (.1,1.5)--(0,1.5) node[left] {$i$};
\draw (1.5,.1)--(1.5,0) node[below] {$1$};
\draw (0,0)--(a) (0,0)--(m) (0,0)--(n) (0,0)--(p);
\draw[dashed] (m)--(n)--(p)--cycle;
\end{scope}
\pic[draw,dashed,thick,"$\theta$",angle radius=0.8cm,angle eccentricity=1.3] {angle=b--o--a};
\fill[black] (a) circle (2pt) (b) circle (2pt) (m) circle (2pt) (n) circle (2pt) (p) circle (2pt) (2,0) circle (2pt);
\end{tikzpicture}
\end{document}
在我看来，节点和路径的分离现在非常好，除了某些分离过度的情况：
解决方法是更改默认的矩形节点形状
像这样
抱歉，我不擅长画画，尤其是用电脑鼠标画画。
换句话说，我认为我必须创建一个新的 Ti钾Z节点形状取决于最大值和最小值”是-所有角色的“坐标”。
对我来说这太复杂了，而且我还没有找到有关这方面的任何提示。
你能帮助我吗？任何帮助我都会非常感激。
答案1
也许这个contour包是适合您的解决方案（另请参阅这个答案)？
\documentclass[tikz, border=2mm]{standalone}
\usepackage[outline]{contour}
\contourlength{2pt} % increase the white space
\usetikzlibrary{patterns}
\begin{document}
\begin{tikzpicture}
\draw [step=.25] (-2,-.5) grid (2,.5);
\node[] at (0,0) {\contour{white}{$|z|^{1/3}e^{i(\theta+2\pi)/3}$}};
\end{tikzpicture}
\end{document}
笔记：上述方法不适用于 XeLaTeX 或 LuaLaTeX。在这种情况下，您需要删除该outline选项并添加例如\contournumber{60}（或更高的数字，具体取决于所需的空白边缘平滑度，请参阅软件包文档）。