我想知道是否有更好的方法来对齐图 1 和图 2 之间的右箭头。目前我可以用 来做到这一点node[right=2cm]。
我想知道为什么我不能使用node[midway]（这是图 2 和图 3 的工作原理）。我认为这会将右箭头放置在“图 1 和图 2 的中间”
\documentclass[hidelinks,14pt, letterpaper]{extarticle}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage{caption}
\begin{document}
\begin{figure}
\centering
\begin{tikzpicture}[scale=1]
\begin{scope}[local bounding box=R]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {?} (C) --
node[below] {?}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\path (R) -- (M) node[right=2cm, scale=1.4]{$\boldsymbol{\Longrightarrow}$};
\node[anchor=north,text width=6cm,align=center] at (R.south) {\captionof{figure}{Caption 1}};
\begin{scope}[xshift=6cm,local bounding box=M]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {x} (C) --
node[below] {1}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\node[anchor=north,text width=6cm,align=center] at (M.south) {\captionof{figure}{Caption 2}};
\begin{scope}[xshift=12cm,local bounding box=R]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {1} (C) --
node[below] {x}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\path (M) -- (R) node[midway,scale=1.4]{$\boldsymbol{\Longrightarrow}$};
\draw[red,thick] (R.north west) -- (R.south east)
(R.north east) -- (R.south west);
\node[anchor=north,text width=6cm,align=center] at (R.south) {\captionof{figure}{Caption 3}};
\end{tikzpicture}
\end{figure}
\end{document}
編輯：不居中
答案1
只需赋予local bounding boxes 唯一的名称并重复您在右侧所做的操作。
\documentclass[hidelinks,14pt, letterpaper]{extarticle}
\usepackage{tikz}
\usepackage{amsmath}
\usepackage{caption}
\begin{document}
\begin{figure}
\centering
\begin{tikzpicture}[scale=1]
\begin{scope}[local bounding box=L]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {?} (C) --
node[below] {?}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\node[anchor=north,text width=6cm,align=center] at (L.south) {\captionof{figure}{Caption 1}};
\begin{scope}[xshift=6cm,local bounding box=M]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {x} (C) --
node[below] {1}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\node[anchor=north,text width=6cm,align=center] at (M.south) {\captionof{figure}{Caption 2}};
\begin{scope}[xshift=12cm,local bounding box=R]
\coordinate [label=left:$A$] (A) at (-1.5cm,-1.cm);
\coordinate [label=above:$B$] (B) at (1.5cm,1.0cm);
\coordinate [label=below right:$C$] (C) at (1.5cm,-1.0cm);
\draw
(A) --
node[midway,above left=0pt] {$\sqrt{1+x^2}$} (B) --
node[right] {1} (C) --
node[below] {x}
(A);
\draw
(1.25cm,-1.0cm) rectangle (1.5cm,-0.75cm);
\end{scope}
\path (L) -- (M) node[midway,scale=1.4]{$\boldsymbol{\Longrightarrow}$};
\path (M) -- (R) node[midway,scale=1.4]{$\boldsymbol{\Longrightarrow}$};
\draw[red,thick] (R.north west) -- (R.south east)
(R.north east) -- (R.south west);
\node[anchor=north,text width=6cm,align=center] at (R.south) {\captionof{figure}{Caption 3}};
\end{tikzpicture}
\end{figure}
\end{document}
